cho mình xin đề bài

(3^3)^2 + 2^x = 733

729 + 2^x = 733

       2^x = 733 - 729

       2^x = 4

     Vậy x = 2

k cho mình nha

a,-3/5.2/7+-3/7.3/5+-3/7

=-3/7.2/5+(-3/7).3/5+(-3/7) 

=-3/7(2/5+3/5+1)

=-3/7.2

=-6/7

bn ơi sao lại là 2/5

\(\frac{-3}{5}\)và\(\frac{2}{7}\)mình đổi hai mẫu cho nhau 

a)\(4^{10}.8^{15}.\left(2^{10}\right)^2.\left(2^{15}\right)^3=2^{20}.2^{30}=2^{50}\)

b)\(8^2.25^3=\left(2^2\right)^3.\left(5^3\right)^2=2^6.5^6=\left(2.5\right)^6=10^6\)

de mh giai thik : cau a ) vi chung chua cung co so nen ta doi ra thanh co so giong . nhau ta chi viec lay so mu cong voi nhau

cau b ) ta không thể đổi ra cùng cơ số được nên ta đổi ra cung so mu. thi ta chi viec nhan hai co so voi nhau giu nguyen mu

sai chỗ nào thì mấy bạn sữa giùm mình nha mình mới học lớp 5 ak

nhanh len may ban oi\

a) \(\dfrac{27^3\cdot11+9^5\cdot5}{3^9\cdot2^4}\)

\(=\dfrac{3^9\cdot11+3^{10}\cdot5}{3^9\cdot2^4}\)

\(=\dfrac{3^9\cdot\left(11+3\cdot5\right)}{3^9\cdot2^4}\)

\(=\dfrac{11+15}{16}\)

\(=\dfrac{26}{16}\)

\(=\dfrac{13}{8}\)

b) \(\dfrac{5^8+2^2\cdot25^4+2^3\cdot125^3-15^4\cdot5^4}{4^2\cdot625^2}\)

\(=\dfrac{5^8+2^2\cdot5^8+2^3\cdot5^9-3^4\cdot5^4\cdot5^4}{2^4\cdot5^8}\)

\(=\dfrac{5^8\cdot\left(1+2^2+2^3\cdot5-3^4\right)}{5^8\cdot2^4}\)

\(=\dfrac{1+4+40-81}{16}\)

\(=\dfrac{-36}{16}\)

\(=\dfrac{-9}{4}\)

c) \(\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)

\(=\dfrac{2^{10}\cdot3^8-2\cdot2^9\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}\)

\(=\dfrac{2^{10}\cdot3^8\cdot\left(1-3\right)}{2^{10}\cdot3^8\cdot\left(1+5\right)}\)

\(=\dfrac{-2}{6}\)

\(=-\dfrac{1}{3}\)

\(\left(19x+2,25\right)\div14=\left(13-8\right)^2-4\)

\(\left(19x+\frac{9}{4}\right)\div14=\left(13-8\right)^2-4\)

\(\left(19x+\frac{9}{4}\right)\div14=5^2-4\)

\(\left(19x+\frac{9}{4}\right)\div14=25-4\)

\(\left(19x+\frac{9}{4}\right)\div14=21\)

\(\left(19x+\frac{9}{4}\right)=21\times14\)

\(\left(19x+\frac{9}{4}\right)=294\)

\(19x=294-\frac{9}{4}\)

\(x=\frac{1167}{4}\div19\)

\(x=\frac{1167}{76}\)

\(1+2+3+4+...+x=378\)

\(\left(1+x\right)\cdot x\div2=378\)

\(\left(1+x\right)\cdot x=378\times2\)

\(\left(1+x\right)\cdot x=756\)

\(\left(1+x\right)\cdot x=28\cdot27\)

\(\Rightarrow x=27\)

còn câu c nữa trần cao vy lượng

b, \(x=28\)

a)\(\frac{484}{-860}=\frac{121}{215}\)

b)\(\frac{14.20-70.13}{21.10+7.80}=\frac{7.2.10.2-7.10.13}{7.3.10+7.8.10}=\frac{7.4.10-7.10.13}{7.3.10+7.8.10}=\frac{7.10.\left(4-13\right)}{7.10.\left(3+8\right)}=\frac{-9}{11}\)

c)\(\frac{-10.21.35}{15.\left(-14\right).\left(-4\right)}=\frac{-2.5.3.7.7.5}{3.5.7.\left(-2\right).\left(-4\right)}=\frac{35}{-4}\)

d)\(\frac{\left(-4\right)^3.27^2.\left(-10\right)^3}{8^3.\left(-9\right)^2.25^2}=\frac{\left(-2^2\right)^3.\left(3^3\right)^2.\left(-2.5\right)^3}{\left(2^3\right)^3.\left[\left(-3\right)^2\right]^2.\left(5^2\right)^2}=\frac{-2^5.3^5.\left(-2\right)^3.5^3}{2^6.\left(-3\right)^4.5^4}=\frac{2^2.3}{5}=\frac{4.3}{5}=\frac{12}{5}\)

a,\(\frac{484}{-860}=\frac{484:\left(-4\right)}{-860:\left(-4\right)}=\frac{-121}{215}\)

b,\(\frac{14.20-70.13}{21.10+7.80}\)\(=\frac{280-910}{210+560}=\frac{-630}{770}=\frac{-9}{11}\)

c,\(\frac{-10.21.35}{15.\left(-14\right).\left(-4\right)}=\frac{1.\left(-3\right).35}{3.2.2}=\frac{105}{12}=8\frac{3}{4}\)

d,tự làm