Bài làm 

3x2 – 8x + 4 = (4x2 – 8x + 4) - x2 = (2x – 2)2 – x2 = (2x – 2 + x)(2x – 2 – x) 
= (x – 2)(3x – 2)

3x^2-22xy-4x+8y+7y^2+1 = (y - 3x + 1) (7y - x + 1)

\(=\left(3x+y+5\right)\left(x+7y+2\right)\)

ai giải thích chi tiết hơn con này hộ mình được k ạ :))

\(=3x^2+21xy+xy+6x+5x+2y+35y+7y^2+10\)

\(=\left(3x^2+21xy+6x\right)+\left(xy+7y^2+2y\right)+\left(5x+35y+10\right)\)

\(=3x\left(x+7y+2\right)+y\left(x+7y+2\right)+5\left(x+7y+2\right)=\left(3x+y+5\right)\left(x+7y+2\right)\)

a)3x^2-22xy-4x+8y+7y^2+1 = (y - 3x + 1) (7y - x + 1)

\(3x^2+22xy+11x+37y+7y^2+10\)

\(=3x^2+xy+21xy+5x+6x+2y+35y+7y^2+10\)

\(=\left(3x^2+xy+5x\right)+\left(21xy+7y^2+35y\right)+\left(6x+2y+10\right)\)

\(=x\left(3x+y+5\right)+7y\left(3x+y+5\right)+2\left(3x+y+5\right)\)

\(=\left(3x+y+5\right)\left(x+7y+2\right)\)

\(x^8+3x^4+4\)

\(=x^8+4x^4+4-x^4\)

\(=\left(x^4+2\right)^2-\left(x^2\right)^2\)

\(=\left(x^4+2-x^2\right)\left(x^4+2+x^2\right)\)

\(3x^2+22xy+11x+37y+7y^2+10\)

\(=\left(3x^2+6x+21xy\right)+\left(7y^2+xy+2y\right)+\left(5x+35y+10\right)\)

\(=3x\left(x+7y+2\right)+y\left(x+7y+2\right)+5\left(x+7y+2\right)\)

\(=\left(3x+y+5\right)\left(x+7y+2\right)\)

\(x^8+3x^4+4\)

\(=x^8+4x^4+4-x^4\)

\(=\left(x^4+2\right)^2-x^4\)

\(=\left(x^4+x^2+2\right)\left(x^4-x^2+2\right)\)