Question

phân tích thành nhân tử
\(3x^2+22xy+11x+37y+7y^2+10\)
 

Answer 1

\(3x^2+22xy+11x+37y+7y^2+10\)

\(=3x^2+xy+21xy+5x+6x+2y+35y+7y^2+10\)

\(=\left(3x^2+xy+5x\right)+\left(21xy+7y^2+35y\right)+\left(6x+2y+10\right)\)

\(=x\left(3x+y+5\right)+7y\left(3x+y+5\right)+2\left(3x+y+5\right)\)

\(=\left(3x+y+5\right)\left(x+7y+2\right)\)