973-x=159
\(\frac{x-971}{972}+\frac{x-973}{970}+\frac{x-975}{968}+\frac{x-977}{966}=\frac{x-972}{971}+\frac{x-970}{973}+\frac{x-968}{975}+\frac{x-966}{977}\)
\(\frac{x-971}{972}+\frac{x-973}{970}+\frac{x-975}{968}+\frac{x-977}{966}=\frac{x-972}{971}+\frac{x-970}{973}+\frac{x-968}{975}+\frac{x-966}{977}\)
\(\Rightarrow\frac{x-971}{972}-1+\frac{x-973}{970}-1+\frac{x-975}{968}-1+\frac{x-977}{966}-1=\frac{x-972}{971}-1+\frac{x-970}{973}-1+\frac{x-968}{975}-1+\frac{x-966}{977}-1\)\(\Rightarrow\frac{x-1943}{972}+\frac{x-1943}{970}+\frac{x-1943}{968}+\frac{x-1943}{966}=\frac{x-1943}{971}+\frac{x-1943}{973}+\frac{x-1943}{975}+\frac{x-966}{977}\)
\(\Leftrightarrow\frac{x-1943}{972}+\frac{x-1943}{970}+\frac{x-1943}{968}+\frac{x-1943}{966}-\frac{x-1943}{971}-\frac{x-1943}{973}-\frac{x-1943}{975}-\frac{x-966}{977}=0\)
\(\Leftrightarrow\left(x-1943\right).\left(\frac{1}{972}+\frac{1}{970}+\frac{1}{968}+\frac{1}{966}-\frac{1}{971}-\frac{1}{973}+\frac{1}{975}+\frac{1}{977}\right)=0\)
\(\Leftrightarrow\left(x-1943\right)=0\Leftrightarrow x=1943\)
Vậy...
x x 8+29=973
tìm x
X x 8 + 29 = 973
X x 8 = 973 - 29
X x 8 = 944
X = 944 : 8
X = 118
Tìm x : 973-x:34+12=729
\(\text{Tìm }x\text{ : }\)
\(973-x\text{ : }34+12=729\)
\(973-x\text{ : }34=729-12\)
\(973-x\text{ : }34=717\)
\(x\text{ : }34=973-717\)
\(x\text{ : }34=256\)
\(x=256\cdot34\)
\(x=8704\)
a) (y – 607 200) : 305 = 642 + 318
c) (1780 – 973) x (75 : y) = 2401 + 20
a)\(\left(y-607200\right):305=642+318\)
⇔\(\left(y-607200\right):305=960\)
⇔\(y-607200=292800\)
⇔\(y=900000\)
a)(y−607200):305=642+318(y−607200):305=642+318
(y−607200):305=960(y−607200):305=960
y−607200=292800y−607200=292800
y=900000
c)\(\left(1780-973\right)\left(75:y\right)=2401+20\)
⇔\(807\left(75:y\right)=2421\)
⇔\(75:y=3\)
⇔\(y=25\)
Tìm tập hợp x biết:
127 < x < 973 và x chia hết cho 3
x = 129;132;135;138;141;144;147;150;153;156;159;162;165;168;.................................;966;969;972.
Tìm y biết:
a) (y – 1) : 105 = 125 x 80
b) (y – 607 200) : 305 = 642 + 318
c) (1780 – 973) x (75 : y) = 2401 + 20
a) (y – 1) : 105 = 125 x 80
(y – 1) : 105 = 10000
(y – 1) = 10000 x 105
(y – 1) = 1050000
y = 1050000 + 1
y = 1050001
b) (y – 607 200) : 305 = 642 + 318
(y – 607 200) : 305 = 960
(y – 607 200) = 960 x 305
(y – 607 200) = 292800
y = 292800 + 607 200
y = 900000
\(a.\left(y-1\right):105=125x80\) \(b.\left(y-607200\right):305=642+318\)
\(\left(y-1\right):105=10000\) \(\left(y-607200\right):305=960\)
\(y-1=10000x105=1050000\) \(y=960+607200=608160\)
\(y=1050000+1=1050001\)
\(c.\left(1780-973\right)x\left(75:y\right)=2401+20\)
\(807x\left(75:y\right)=2401+20\)
\(807x\left(75:y\right)=2421\)
\(75:y=2421:807=3\)
\(y=75:3=25\)
a) (y - 1) : 105 = 125 x 80
(y - 1) : 105 = 10000
(y - 1) = 10000 x 105
(y - 1) = 10500000
y = 10500000 + 1
y = 10500001.
b) (y – 607 200) : 305 = 642 + 318
(y – 607 200) : 305 = 960
(y – 607 200) = 960 x 305
(y – 607 200) = 292800
y = 292800 + 607 200
y = 900000.
c) (1780 − 973) x (75 : y) = 2401 + 20
= 807 x (75 : y) = 2401 + 20
807 x (75 : y) = 2421
75 : y = 2421 : 807 = 3
y = 75 : 3
y = 25.
Tìm x,biết x:8=121(dư 5)
A.973 B.968 C.40 D.161
x - 5 = 8 x 121
x - 5 = 968
x= 968 + 5
x= 973
x:8=121 ( dư 5 )
x=121x8+5
x=968+5
x=973
Đáp án:A nha
123 + x = 547 + 973
ai trước đây từng quen biết với melosa thủy anh lona thì kb mk nha
đề bài là tìm x
123 + x = 547 + 973
123 +x=1520
x=1520-123
x=1397
Đúng 100%
123-234+973=???