a,999/2610=111/290

b,374/506=17/23

c,3600-75/8400-175=3/7

d,9^14.25^5.8^7/18^12.625^3.24^3=3/25

a, Ta có:999/2610=111/290

b, Ta có:374/506=17/2

c,Ta có:3600-75/8400-175=48.75-75/48.175-175=75.(48-1)/175.(48-1)=75/175=3/7

d, Ta có:(3^2)^14.(5^2)^5.(2^3)^7/(2.3^2)^12.(5^4)^3.(2^3.3)^3

=3^28.5^10.2^21/2^12.3^24.5^12.2^9.3^3

=3^28.5^10.2^21/2^21.3^27.5^12

=3/5^2=3/25

\(\frac{44116-14}{10290-35}=\frac{44102}{10255}\)

\(\frac{3600-75}{8400-175}=\frac{75\left(48-1\right)}{35\left(240-5\right)}=\frac{15\cdot47}{7\cdot235}=\frac{3\cdot5\cdot47}{7\cdot5\cdot47}=\frac{3}{7}\)

g, \(\frac{44116-14}{10290-35}=\frac{44102}{10255}\)

h, \(\frac{3600-75}{8400-175}=\frac{3525}{8225}=\frac{3}{7}\)

a, \(\dfrac{990}{2610}=\dfrac{11}{29}\)

b) \(\dfrac{3600-75}{8400-175}=\dfrac{3}{7}\)

c) \(\dfrac{9^{14}\cdot25^5\cdot8^7}{18^{12}\cdot625^5\cdot24^3}=\dfrac{3}{25}\)

dễ lắm mà

ừa, nhưng mik còn những câu sau khó hơn nhưng mỏi tay quá nên tí gửi tiếp!

a,=-36/7

b,=11/29

c,=17/23

d,=3/7

e,=-5/9

ấn máy cho nhanh

đề ko yêu cầu tính nhanh mà ta, 

Thực hiện phép tính :

a) 46 - { [ ( 16 + 71 : 4 ) : 15 ] } - 2

= 46 - { [ ( 16 + 17,75 ) : 15 ] }

= 46 - { 33,75 : 15 }

= 46 - 2,25

= 43,75

b) 120 - { 300 : [ 150 - ( 2 . 5³ - 2³ . 25 ) ] }

= 120 - { 300 : [ 150 - (  2 . 5³ - 2³ . 5² ) ] }

= 120 - { 300 : [ 150 - (  2 . 5² ( 5 . 2² ) ] }

= 120 - { 300 : [ 150 - ( 50 . 20 ) ] }

= 120 - { 300 : [ 150 - 1000 ] }

= 120 - 300 : ( -850 )

= 120 + \(\frac{300}{850}\)

= \(\frac{10200}{850}\)+  \(\frac{300}{850}\)

= \(\frac{10500}{850}\)

= \(\frac{210}{17}\)

c) ( 20 . 24 + 12 . 24 - 4⁸ . 2² ) : 8²

= [ 24 . ( 20 + 12 ) - 4⁸ . 4 ] : 64

= ( 32 . 24 -  4⁹ ) : 64

= ( 768 - 4⁹ ) : 64

= 768 : 64 + 4⁹ : 64

= 12 + 4⁹ : 4³

= 12 + 4⁶

= 12 + 4096

= 4108

d) ( 75 . 5⁴ + 175 . 5⁴ ) : ( 20 . 25 . 125 - 625 . 75 )

= [ 5⁴  . ( 75 + 175 ) ] : ( 62500 - 625 . 75 )

= 5⁴ . 250 : 625 . ( 100 - 75 )

= 5² . ( 5² . 10 ) : 625 . 25

= 25 . 250 : 625 . 25

= 250

a) \(\sqrt{15+2\sqrt{5}-\sqrt{21-4\sqrt{5}}}\)

\(=\sqrt{15+2\sqrt{5}-\sqrt{\left(1-2\sqrt{5}\right)^2}}\)

\(=\sqrt{15+2\sqrt{5}-\left(2\sqrt{5}-1\right)}\)

\(=\sqrt{15+2\sqrt{5}-\left(2\sqrt{5}-1\right)}\)

\(=\sqrt{15+2\sqrt{5}-2\sqrt{5}+1}\)

\(=\sqrt{16}\)

\(=4\)

b) \(\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}}\)

\(=\sqrt[4]{5-\sqrt{3-\sqrt{29-12\sqrt{5}}}}\)

\(=\sqrt[4]{5-\sqrt{3-\sqrt{\left(3-2\sqrt{5}\right)^2}}}\)

\(=\sqrt[4]{5-\sqrt{3-\left(2\sqrt{5}-3\right)}}\)

\(=\sqrt[4]{5-\sqrt{3-2\sqrt{5}+3}}\)

\(=\sqrt[4]{5-\sqrt{6-2\sqrt{5}}}\)

\(=\sqrt[4]{5-\sqrt{\left(1-\sqrt{5}\right)^2}}\)

\(=\sqrt[4]{5-\left(\sqrt{5}-1\right)}\)

\(=\sqrt[4]{5-\sqrt{5}+1}\)

\(=\sqrt[4]{6-\sqrt{5}}\)

a) \(\left(2^3.9^4+9^3.45\right):\left(9^2.10-9^2\right)\)

   =\(\left(2^3.9^4+9^3.9.5\right):9^2\left(10-1\right)\)

   = \(\left(8-9^4+9^4.5\right):9^2.9\)

   =\(9^4\left(8-5\right):9^3\)

   =\(9^4.3:9^3\)

   =\(9^4:9^3.3\)

   =\(9.3\)

   =\(27\)