a.-12 ( x-5 ) +7 (3-x) = 5

-12x +60 + 21 - 7x =5

60+21-5                 = 12x + 7x

76                          = 19x

x                            = 4

b.30(x +2) - 6(x-5) -24x = 100

30x+60 - 6x -30-24x       = 100

60-30-100                       = 30x -6x - 24x

-70                                  = 0x

x                                     = -70

\(a)\) \(\left(-12\right)\left(x-5\right)+7\left(3-x\right)=5\)

\(\Leftrightarrow\)\(\left(-12\right)x+60+21-7x=5\)

\(\Leftrightarrow\)\(\left(-12\right)x-7x=5-60-21\)

\(\Leftrightarrow\)\(x\left(-12-7\right)=-76\)

\(\Leftrightarrow\)\(x.\left(-19\right)=-76\)

\(\Leftrightarrow\)\(x=\frac{-76}{-19}\)

\(\Leftrightarrow\)\(x=4\)

Vậy \(x=4\)

\(b)\) \(\left(x-2\right)\left(x+4\right)=0\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x-2=0\\x+4=0\end{cases}}\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x=2\\x=-4\end{cases}}\)

Vậy \(x\in\left\{2;-4\right\}\)

Tìm x . biết : 

\(a,\frac{2}{5}:\left(-x-\frac{1}{2}\right)=\frac{4}{5}\)

\(\Rightarrow-x-\frac{1}{2}=\frac{2}{5}:\frac{4}{5}\)

\(\Rightarrow-x-\frac{1}{2}=\frac{2}{5}.\frac{5}{4}\)

\(\Rightarrow-x-\frac{1}{2}=\frac{1}{2}\)

\(\Rightarrow-x=\frac{1}{2}+\frac{1}{2}\)

\(\Rightarrow-x=1\)

\(\Rightarrow x=-1\)

Vậy \(x=-1\)

a. \(\frac{2}{5}.\left(-x-\frac{1}{2}\right)=\frac{4}{5}\)

\(\Rightarrow-x-\frac{1}{2}=\frac{2}{5}:\frac{4}{5}\)

\(\Rightarrow-x-\frac{1}{2}=\frac{2}{5}.\frac{5}{4}\)

\(\Rightarrow-x-\frac{1}{2}=\frac{1}{2}\)

\(\Rightarrow-x=\frac{1}{2}+\frac{1}{2}\)

\(\Rightarrow-x=1\)

\(\Rightarrow x=-1\)

a) Bạn xemm lại đề nhé.

b) \(5\left(x+35\right)=515\)

\(x+35=515\div5\)

\(x+35=103\)

\(x=103-35\)

\(x=68\)

Vậy \(x=68\).

c) \(90-3\left(x+1\right)=42\)

\(3\left(x+1\right)=90-42\)

\(3\left(x+1\right)=48\)

\(x+1=48\div3\)

\(x+1=16\)

\(x=16-1\)

\(x=15\)

Vậy \(x=15\).

d) \(12x-33=3^2.3^3\)

\(12x-33=3^5\)

\(12x-33=243\)

\(12x=243+33\)

\(12x=276\)

\(x=276\div12\)

\(x=23\)

Vậy \(x=23\).

e) \(100-7\left(x-5\right)=58\)

\(7\left(x-5\right)=100-58\)

\(7\left(x-5\right)=42\)

\(x-5=42\div7\)

\(x-5=6\)

\(\Rightarrow x=6+5=11\)

Vậy \(x=11\).

j) \(24+5x=7^5\div7^3\)

\(24+5x=7^2\)

\(24+5x=49\)

\(5x=49-24\)

\(5x=25\)

\(\Rightarrow x=25\div5=5\)

Vậy \(x=5\).

541+(218-x)=735

(218-x)=735-541

(218-x)=194

x=218-194

x=24

vậy x=24

5 (x+35)=515

(x+35)=515:5

(x+35=103

x=103-35

x=68

vậy x=68

90-3 (x+1)=42

3 (x+1)=90-42

3 (x+1)=48

(x+1)=48:3

(x+1)=16

x=16-1

x=15

vậy x=15

12x-33=3^2.3^3

12x-33=3^5

12x-33=243

12x=243-33

12x=210

x=210:12

x=17,5

vậy x=17,5

100- 7 (x-5)=58

7 (x-5)=100-58

7 (x-5)=42

(x-5)=42:7

(x-5)=6

x=6-5

x=1

vậy x=1

24+5x=7^5:7^3

24+5x=7^2

24+5x=49

5x=49-24

5x=25

x=25:5

x=5

vậy x=5

huyền linh ý a đúng r mà

-2/3x+5/8=-7/12

-2/3x       =-7/12-5/8

-2/3x       =-29/24

x             =-29/24:-2/3

x             =-29/16

Học tốt nha bn.

\(\frac{-2}{3}:x+\frac{5}{8}+\frac{-7}{12}\)

\(\frac{-2}{3}:x=\frac{-7}{12}-\frac{5}{8}\)

\(\frac{-2}{3}:x=\frac{-29}{24}\)

\(x=\frac{-2}{3}:\left(\frac{-29}{24}\right)\)

\(x=\frac{16}{29}\)

Từ biểu thức, ta suy ra:

-12x+60+21-7x=5

<=>81-19x=5

<=>81-19x-5=0

<=>76-19x=0

<=>19x=76

<=>x=4

Vậy x=4

  -12 ( x-5 ) + 7 ( 3 - x ) = 5 

=> -12x + 60 + 21 - 7x = 5

=> -19x = 5 - 81

=> -19x = -76

=> x = 4

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