tìm x:
29 - ( 209/10 * x - 80 ) : 2010/29 = 0
Tìm X 29 - (209/10 * X - 80 ) : 2010/29 = 0 ( * là dấu nhân)
GIÚP MÌNH NHA MÌNH CẦN GẤP AI NHANH NHẤT MÌNH TICK
29 - ( 209/10 * x - 80 ) : 2010/29 = 0
( 209/10 * x - 80 ) : 2010/29 = 29 - 0
( 209/10 * x - 80 ) : 2010/29 = 29
( 20,9 * x -80 ) = 29 * 2010/ 29
( 20,9 * x -80 ) = 2010
20,9 * x = 2010 + 80
20,9 * x = 2090
x = 2090 : 20,9
x = 100
HOK TỐT
29 - (\(\frac{209}{10}\)*X - 80 ) : \(\frac{2010}{29}\)=0
giải
(\(\frac{209}{10}\)* X - 80 ) : \(\frac{2010}{29}\)= 29
\(\frac{209}{10}\)* X - 80 )=29 x \(\frac{2010}{29}\)
\(\frac{209}{10}\)* X - 80 = 2010
\(\frac{209}{10}\)* X = 2010 + 80
\(\frac{209}{10}\)* X= 2090
X= 2090 : \(\frac{209}{10}\)
X= 2090 * \(\frac{10}{209}\)
X=100
29 -(209/10*x - 80)* 29/2010=0
29 - (6061/20100*x - 232/201) = 0
29 - 6061/20100*x + 232/201=0
6061/201 - 6061/20100*x = 0
606100 - 6061*x = 0
-6061*x = -606100
x = 100
tìm x
29-(209/10 x X -80)=0
giúp mik nha mik sẽ tích cho (trình bày đầy đủ)
\(29-\left(\frac{209}{10}x-80\right)=0\)
\(\Leftrightarrow\frac{209}{10}x-80=29\)
\(\Leftrightarrow\frac{209}{10}x=109\Leftrightarrow x=\frac{1090}{209}\)
Tìm x bằng quy tắc chuyển vế :
a)-18-( x-6)=0
b)29-(10+29)= x-(27-9)
a) -(x-6)=18
-x+6=18
-x=12
a) -18-(x-6)=0
x-6=(-18)-0
x-6=-18
x = (-18)+6
x = -12
b) 29-(10+29)=x-(27-9)
29-39 = x-18
-10 =x-18
x-18=-10
x = (-10)+18
x = 8
Học tốt
Trl:
a) \(-18-\left(x-6\right)=0\)
\(\Rightarrow\left(x-6\right)=-18-0\)
\(\Rightarrow\left(x-6\right)=-18\)
\(\Rightarrow x=-18+6\)
\(\Rightarrow x=-12\)
b) \(29-\left(10+29\right)=x-\left(27-9\right)\)
\(\Rightarrow29-39=x-18\)
\(\Rightarrow-10=x-18\)
\(\Rightarrow x=18+\left(-10\right)\)
\(\Rightarrow x=28\)
tìm x thuộc c biết
1) 7-(18+x)= - 15
2) (x-17)-(-3)=0
3) -18-(x-6)=0
4) 29-(10+29)=x-(27-9)
1,7-(18+x)=-15
<=>18+x=7+15
<=>18+x=22
<=>x=4
2,(x-17)-(-3)=0
<=>x-17+3=0
<=>x-17=-3
,<=>x=14
<=>
1,
7 - ( 18 + x ) = - 15
18 + x = 7 + 15
18 + x = 22
x = 22 - 18
x = 4
2,
( x - 17 ) - ( - 3 ) = 0
( x - 17 ) + 3 = 0
x - 17 = - 3
x = -3 + 17
x = 14
3, -18 - ( x - 6 ) = 0
-18 = x- 6
x = - 18 + 6
x = - 12
4, 29 - ( 10 + 29 ) = x - ( 27 - 9 )
-10 = x - 18
x = - 10 + 18
x = 8
Tìm x biết:a) 29-x/21 + 27-x/23 + 25-x/25 + 23-x/27 + 21-x/29
b)x-10/30 + x-14/43 + x-5/95 + x-148/8 = 0
a, bổ sung đề
\(\dfrac{29-x}{21}+1+\dfrac{27-x}{23}+1+\dfrac{25-x}{25}+1+\dfrac{23-x}{27}+1+\dfrac{21-x}{29}+1=0\)
\(\Leftrightarrow\dfrac{50-x}{21}+\dfrac{50-x}{23}+\dfrac{50-x}{25}+\dfrac{50-x}{27}+\dfrac{50-x}{29}=0\)
\(\Leftrightarrow\left(50-x\right)\left(\dfrac{1}{21}+\dfrac{1}{23}+\dfrac{1}{25}+\dfrac{1}{27}+\dfrac{1}{29}\ne0\right)=0\Leftrightarrow x=50\)
tìm x thỏa mãn [xEN]biết [x-29].59 =0
A.x=59
B.x=0
C.x=29
DX=30
Tìm x:
a) 2n+3.5n+3=209:29
b)3n+5-3n+4=1458
c)5n+3+5n+2=3750
d)\(\dfrac{2}{7}x\) + \(\dfrac{3}{14}x\) = \(\dfrac{1}{2}\)
e)\(\dfrac{x+2}{-3}\) = \(\dfrac{-2}{x+3}\)
`@` `\text {Ans}`
`\downarrow`
`a)`
\(2^{n+3}\cdot5^{n+3}=20^9\div2^9\)
`=>`\(\left(2\cdot5\right)^{n+3}=\left(20\div2\right)^9\)
`=>`\(10^{n+3}=10^9\)
`=>`\(n+3=9\)
`=> n = 9 - 3`
`=> n= 6`
Vậy, `n=6`
`b)`
\(3^{n+5}-3^{n+4}=1458\)
`=> 3^n*3^5 - 3^n*3^4 = 1458`
`=> 3^n*(3^5 - 3^4) = 1458`
`=> 3^n*162 = 1458`
`=> 3^n = 1458 \div 162`
`=> 3^n = 9`
`=> 3^n = 3^2`
`=> n=2`
Vậy, `n=2.`
`c)`
\(5^{n+3}+5^{n+2}=3750\)
`=> 5^n*5^3 + 5^n*5^2 = 3750`
`=> 5^n*(5^3+5^2) = 3750`
`=> 5^n*150 = 3750`
`=> 5^n = 3750 \div 150`
`=> 5^n =25`
`=> 5^n = 5^2`
`=> n=2`
Vậy, `n=2.`
`d)`
\(\dfrac{2}{7}x+\dfrac{3}{14}x=\dfrac{1}{2}\)
`=> 1/2x = 1/2`
`=> x = 1/2 \div 1/2`
`=> x=1`
Vậy, `x=1`
`e)`
\(\dfrac{x+2}{-3}=\dfrac{-2}{x+3}\)
`=> (x+2)(x+3) = -3*(-2)`
`=> (x+2)(x+3) = -6`
`=> x(x+3) + 2(x+3) = -6`
`=> x^2 + 3x + 2x + 6 = -6`
`=> x^2 + 5x + 6 - 6 = 0`
`=> x^2 + 5x = 0`
`=> x(x+5) = 0`
`=>`\(\left[{}\begin{matrix}x=0\\x+5=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=0\\x=-5\end{matrix}\right.\)
Vậy, `x \in {0; -5}`
`@` `\text {Kaizuu lv u}`
tính giá trị các biểu thức:
1) A=7/10 x11 + 7/11 x 12 + 7/12 x 13 + ...... +7/69 x 70
2)B= 1/25 x 27 + 1/ 27 x 29 + 1/29 x 31 + ... + 1/ 73 x 75
3) C= 4/2 x4 +4/4 x 6 + 4/6 x 8 + ... + 4/ 2008 x 2010
1) \(A=\frac{7}{10\times11}+\frac{7}{11\times12}+\frac{7}{12\times13}+...+\frac{7}{69\times70}\)
\(A=7\times\left(\frac{1}{10\times11}+\frac{1}{11\times12}+\frac{1}{12\times13}+...+\frac{1}{69\times70}\right)\)
\(A=7\times\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{69}-\frac{1}{70}\right)\)
\(A=7\times\left(\frac{1}{10}-\frac{1}{70}\right)\)
\(A=7\times\frac{3}{35}\)
\(A=\frac{3}{5}\)
2) \(B=\frac{1}{25\times27}+\frac{1}{27\times29}+\frac{1}{29\times31}+...+\frac{1}{73\times75}\)
\(B=\frac{1}{2}\times\left(\frac{2}{25\times27}+\frac{2}{27\times29}+\frac{2}{29\times31}+...+\frac{2}{73\times75}\right)\).
\(B=\frac{1}{2}\times\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\times\left(\frac{1}{25}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\times\frac{2}{75}\)
\(B=\frac{1}{75}\)
3) \(C=\frac{4}{2\times4}+\frac{4}{4\times6}+\frac{4}{6\times8}+...+\frac{4}{2008\times2010}\)
\(C=\frac{4}{2}\times\left(\frac{2}{2\times4}+\frac{2}{4\times6}+\frac{2}{6\times8}+...+\frac{2}{2008\times2010}\right)\)
\(C=2\times\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{2008}-\frac{1}{2010}\right)\)
\(C=2\times\left(\frac{1}{2}-\frac{1}{2010}\right)\)
\(C=2\times\frac{502}{1005}\)
\(C=\frac{1004}{1005}\)
_Chúc bạn học tốt_
tìm x biết
a) 7-(18+x)=-15
b) (x-17)-(-3)=0
c)-18-(x-6)=0
d) 29-(10+29)=x-(27-9)
a,\(7-\left(18+x\right)=-15\)
\(18+x=7-\left(-15\right)\)
\(18+x=22\)
\(x=4\)
b,\(\left(x-17\right)-\left(-3\right)=0\)
\(x-17=-3\)
\(x=14\)
c,\(-18-\left(x-6\right)=0\)
\(x-6=-18\)
\(x=-12\)
d,\(29-\left(10+29\right)=x-\left(27-9\right)\)
\(x-18=-10\)
\(x=8\)
a) \(7-\left(18+x\right)=-15\)
\(\Leftrightarrow18+x=7+15\)
\(\Leftrightarrow18+x=22\)
\(\Leftrightarrow x=22-18\)
\(\Leftrightarrow x=4\)
b) \(\left(x-17\right)-\left(-3\right)=0\)
\(\Leftrightarrow\left(x-17\right)+3=0\)
\(\Leftrightarrow x-17=0-3\)
\(\Leftrightarrow x-17=-3\)
\(\Leftrightarrow x=-3+17\)
\(\Leftrightarrow x=14\)
c) \(-18-\left(x-6\right)=0\)
\(\Leftrightarrow x-6=0+\left(-18\right)\)
\(\Leftrightarrow x-6=-18\)
\(\Leftrightarrow x=-18+6\)
\(\Leftrightarrow x=-12\)
d) \(29-\left(10+29\right)=x-\left(27-9\right)\)
\(\Leftrightarrow29-10-29=x-27+9\)
\(\Leftrightarrow-10=x-27+9\)
\(\Leftrightarrow x-27=-10-9\)
\(\Leftrightarrow x-27=-19\)
\(\Leftrightarrow x=-19+27\)
\(\Leftrightarrow x=8\)
a)
7 - (18 + x) = -15
18 + x = 7 - ( -15 )
18 + x = 7 + 15
18 + x = 22
x = 22 - 18
x = 4
b)
(x - 17) - (-3) = 0
x - 17 = 0 + -3
x - 17 = -3
x = -3 + 17
x = 14
c)
-18 - (x - 6) = 0
x - 6 = -18 - 0
x - 6 = -18
x = -18 + 6
x = -12
d)
29 - (10 + 29) = x - (27 - 9)
29 - 39 = x - 18
x - 18 = -10
x = -10 + 18
x = 8