\(a)x=\dfrac{1}{4}+\dfrac{5}{13}=\dfrac{33}{52}.\\ b)\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}.\\ \Leftrightarrow\dfrac{x}{3}=\dfrac{11}{21}.\\ \Leftrightarrow\dfrac{7x}{21}=\dfrac{11}{21}.\\ \Rightarrow7x=11.\\ \Leftrightarrow x=\dfrac{11}{7}.\\ c)\dfrac{x}{3}=\dfrac{16}{24}+\dfrac{24}{36}=\dfrac{2}{3}+\dfrac{2}{3}=\dfrac{4}{3}.\\ \Rightarrow x=4.\\ d)\dfrac{x}{15}=\dfrac{1}{5}+\dfrac{2}{3}=\dfrac{13}{15}.\\ \Rightarrow x=13.\)

1, 54 : x - 1 = 5

54 : x = 5+1 = 6

x = 54 : 6 = 9

2, 42 : x + 0 = 8

x = 42 : 8 = 21/4

3, 24 : x - 8 = 0

24 : x = 0 + 8 = 8

x = 24 : 8 = 3

Tk mk nha

1) 54:x-x:x=3x2-1

    54:x-  1 =6-1

    54:x-   1=5

    54:x      =6

         x=54:6=9

ban lam sai rui de mk lam lai nhe.

\(12.\left(x-1\right):3=4^3-2^3\)

\(12.\left(x-1\right):3=64-8\)

\(12.\left(x-1\right):3=56\)

\(12.\left(x-1\right)=56.3\)

\(12.\left(x-1\right)=168\)

\(x-1=168:12\)

\(x-1=14\)

             \(x=15\)

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dmm

a: \(\left(x+1\right)^3+\left(x-2\right)^3=2x^3+2\left(2x-1\right)^2-9\)

\(\Leftrightarrow x^3+3x^2+3x+1+x^3-6x^2+12x-8=2x^3+2\left(4x^2-4x+1\right)-9\)

\(\Leftrightarrow2x^3-3x^2+15x-7=2x^3+8x^2-8x-7\)

\(\Leftrightarrow-11x^2+23x=0\)

\(\Leftrightarrow x\left(-11x+23\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{23}{11}\end{matrix}\right.\)

\(a,x-\dfrac{7}{12}x=\dfrac{5}{24}-\dfrac{3}{8}x\)

\(\Leftrightarrow\dfrac{5}{12}x+\dfrac{3}{8}x=\dfrac{5}{24}\)

\(\Leftrightarrow\dfrac{19}{24}x=\dfrac{5}{24}\Leftrightarrow x=\dfrac{5}{19}\)

Vậy x = 5/19

\(b,\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=0\\-3-\dfrac{x}{2}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-6\end{matrix}\right.\)

Vậy x = 1/2 hoặc x = -6

\(c,\dfrac{x-3}{-2}=\dfrac{-8}{x-3}\)

\(\Leftrightarrow\left(x-3\right)^2=16\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=4\\x-3=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-1\end{matrix}\right.\)

Vậy x = 7 hoặc x = -1

a: =>6/x=x/24

=>x^2=144

=>x=12 hoặc x=-12

b: =>x(1-7/12+3/8)=5/24

=>x*19/24=5/24

=>x=5/24:19/24=5/19

c: =>(x-1/3)^2=1+3/4+1/2=9/4

=>x-1/3=3/2 hoặc x-1/3=-3/2

=>x=11/6 hoặc x=-7/6

d: =>(x-3)^2=16

=>x-3=4 hoặc x-3=-4

=>x=-1 hoặc x=7

e: =>9/x=-1/3

=>x=-27

f: =>x-1/2=0 hoặc -x/2-3=0

=>x=1/2 hoặc x=-6

\(\dfrac{24}{x}:\dfrac{8}{3}=\dfrac{3}{5}\)

\(\dfrac{24}{x}=\dfrac{3}{5}.\dfrac{8}{3}\)

\(\dfrac{24}{x}=\dfrac{8}{5}\)

\(\dfrac{24}{x}=\dfrac{24}{15}\)

=>x=5

Vậy x=5

\(x+3\dfrac{1}{2}+x=24\dfrac{1}{4}\)

\(\left(x+x\right)+3\dfrac{1}{2}=24\dfrac{1}{4}\)

\(x.2+\dfrac{7}{2}=\dfrac{97}{4}\)

\(x.2=\dfrac{97}{4}-\dfrac{7}{2}\)

\(x.2=\dfrac{97}{4}-\dfrac{14}{4}\)

\(x.2=\dfrac{83}{4}\)

\(x=\dfrac{83}{4}:2\)

\(x=\dfrac{83}{4}.\dfrac{1}{2}\)

\(x=\dfrac{83}{8}\)

\(x=10\dfrac{3}{8}\)

a.24/x:8/3=3/5

suy ra :24/x=8/5

suy ra:x=15

b. x=35/8

a)        \(\frac{24}{x}:\frac{8}{3}=\frac{3}{5}\)                        \(\frac{24}{x}=\frac{3}{5}.\frac{8}{3}\)                                                                                                                                          \(\frac{24}{x}=\frac{8}{5}\)                              \(x=24.5:8\)                \(x=15\)

b) Đề bài sai rồi 

có thể giải được ko

1: 

\(\Leftrightarrow\left(x^2+5x+6\right)\left(x^2+5x+4\right)=24\)

\(\Leftrightarrow\left(x^2+5x\right)^2+10\left(x^2+5x\right)=0\)

\(\Leftrightarrow x^2+5x=0\)

=>x=0 hoặc x=-5

3: \(\Leftrightarrow\left(x^2+x+6\right)\left(x^2+x-2\right)=0\)

=>(x+2)(x-1)=0

=>x=-2 hoặc x=1