\(-\frac{17}{21}:\left(\frac{5}{4}-\frac{2}{5}\right)< x+\frac{4}{7}< 1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}\)

\(\Leftrightarrow-\frac{17}{21}:\frac{17}{20}< x+\frac{4}{7}< \frac{12}{12}-\frac{6}{12}+\frac{4}{12}-\frac{3}{12}\)

\(\Leftrightarrow-\frac{17}{21}.\frac{20}{17}< x+\frac{4}{7}< \frac{7}{12}\)

\(\Leftrightarrow-\frac{20}{21}< x+\frac{4}{7}< \frac{7}{12}\)

\(\Leftrightarrow-\frac{20}{21}< x< \frac{1}{84}\)

\(\Leftrightarrow-\frac{80}{84}< x< \frac{1}{84}\)

\(\Leftrightarrow-80< x< 1\Leftrightarrow x\in\left\{-79;-78;...;0\right\}\)

mà để Giá trị nguyên lớn nhất của x

\(\Rightarrow x=-1\)

Ta thấy 17/5  <  | - 20/5 |  <  21/5

=> x = - 20/5 = - 4.

bậc của đa thức  f(x)=5 là

Ta có : 17/5 < | -20/5 | < 21/5

Suy ra x = -20/5 = -4

1. \(\frac{-17}{21}:\left(\frac{5}{4}-\frac{2}{5}\right)< x+\frac{4}{7}< 1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}\)

\(-\frac{17}{21}:\frac{17}{20}< x+\frac{4}{7}< \frac{7}{12}\)

\(-\frac{20}{21}< x+\frac{4}{7}< \frac{7}{12}\)

\(-\frac{80}{84}< \frac{84x+48}{84}< \frac{49}{84}\)

\(-80< 84x+48< 49\)

\(\begin{cases}-80< 84x+48\\84x+48< 49\end{cases}\) 

\(\begin{cases}84x>-128\\84x< 1\end{cases}\)

\(\begin{cases}x>-\frac{32}{21}\\x< \frac{1}{84}\end{cases}\)

\(\Rightarrow-\frac{32}{21}< x< \frac{1}{84}\)

\(-\frac{17}{21}\div\left(\frac{5}{4}-\frac{2}{5}\right)< x+\frac{4}{7}< 1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}\)

\(-\frac{20}{21}< x+\frac{4}{7}< \frac{7}{12}\)

\(-\frac{32}{21}< x< \frac{1}{84}\)

\(-1^{11}_{21}< x< \frac{1}{84}\)

\(\Rightarrow x\in\left\{-1;0\right\}\)

Vậy x = 0

\(\frac{4}{3}\times1,25\times\left(\frac{16}{5}-\frac{5}{16}\right)< 2x< 4-\frac{4}{3}+3-\frac{3}{2}+2\)

\(\frac{77}{16}< 2x< \frac{37}{6}\)

\(\frac{77}{32}< x< \frac{37}{12}\)

\(2^{13}_{32}< x< 3^1_{12}\)

=> x = 3

2. \(\frac{4}{3}.1,25\left(\frac{16}{5}-\frac{5}{16}\right)< 2x< 4-\frac{4}{3}+3-\frac{3}{2}+2\)

\(\frac{16}{15}.\frac{231}{80}< 2x< \frac{37}{6}\)

\(\frac{77}{25}< 2x< \frac{37}{6}\)

\(\begin{cases}\frac{77}{25}< 2x\\2x< \frac{37}{6}\end{cases}\)

\(\begin{cases}2x>\frac{77}{25}\\x< \frac{37}{12}\end{cases}\)

\(\begin{cases}x>\frac{77}{50}\\x< \frac{37}{12}\end{cases}\)

\(\frac{77}{50}< x< \frac{37}{12}\)

                                                                     Bài giải

\(-\frac{20}{21}< x+\frac{4}{7}< \frac{7}{12}\)

\(-\frac{20}{21}-\frac{4}{7}< x+\frac{4}{7}-\frac{4}{7}< \frac{7}{12}-\frac{4}{7}\)

\(-\frac{32}{21}< x< \frac{1}{84}\)

\(-1,5...< x< 0,01...\)

\(\Rightarrow\text{ }x=-1\)

Thi vòng 12 à bạn!!! Để mk chép đề mà làm 

Ta có:

\(\frac{6}{5}< x-\frac{3}{2}< \frac{12}{5}\)

\(=>\frac{12}{10}< x-\frac{15}{10}< \frac{24}{10}\)

\(=>\frac{12+15}{10}< x< \frac{24+15}{10}\)

\(=>\frac{27}{10}< x< \frac{39}{10}\) (mà x là số nguyên)

\(=>x=3\)

bằng 3 nha hihi

\(\left(x-\frac{3}{5}\right).\left(x+\frac{2}{7}\right)< 0\)

\(\Rightarrow\hept{\begin{cases}x-\frac{3}{5}< 0\\x+\frac{2}{7}>0\end{cases}\text{hoặc}\hept{\begin{cases}x-\frac{3}{5}>0\\x+\frac{2}{7}< 0\end{cases}}}\)

\(\Rightarrow\hept{\begin{cases}x< \frac{3}{5}\\x>-\frac{2}{7}\end{cases}\text{hoặc}\hept{\begin{cases}x>\frac{3}{5}\\x< -\frac{2}{7}\end{cases}}}\)

\(\Rightarrow\orbr{\begin{cases}-\frac{2}{7}< x< \frac{3}{5}\\x\in\varnothing\end{cases}}\)

\(\Rightarrow-\frac{2}{7}< x< \frac{3}{5}\)

\(\Rightarrow x=0\)

Vậy x = 0

\(\left(x-\frac{3}{5}\right)\cdot\left(x+\frac{2}{7}\right)< 0\)

TH1 : \(\Rightarrow\hept{\begin{cases}x-\frac{3}{5}< 0\\x+\frac{2}{7}>0\end{cases}}\)                 \(\Rightarrow\hept{\begin{cases}x< \frac{3}{5}\\x>-\frac{2}{7}\end{cases}}\)              \(\Rightarrow\text{ }-\frac{2}{7}< x< \frac{3}{5}\)

TH2 : \(\Rightarrow\hept{\begin{cases}x-\frac{3}{5}>0\\x+\frac{2}{7}< 0\end{cases}}\)                 \(\Rightarrow\hept{\begin{cases}x>\frac{3}{5}\\x< -\frac{2}{7}\end{cases}}\)             \(\Rightarrow\text{ Không xảy ra}\)

                            Vì \(x\in Z\text{ }\Rightarrow\text{ }x=0\)

\(\left(x-\frac{3}{5}\right)\cdot\left(x+\frac{2}{7}\right)< 0\) 

TH1 : \(\Rightarrow\hept{\begin{cases}x-\frac{3}{5}< 0\\x+\frac{2}{7}>0\end{cases}}\)                 \(\Rightarrow\hept{\begin{cases}x< \frac{3}{5}\\x>-\frac{2}{7}\end{cases}}\)              \(\Rightarrow\text{ }-\frac{2}{7}< x< \frac{3}{5}\)

TH2 : \(\Rightarrow\hept{\begin{cases}x-\frac{3}{5}>0\\x+\frac{2}{7}< 0\end{cases}}\)                 \(\Rightarrow\hept{\begin{cases}x>\frac{3}{5}\\x< -\frac{2}{7}\end{cases}}\)             \(\Rightarrow\text{ Không xảy ra}\)

                            Vì \(x\in Z\text{ }\Rightarrow\text{ }x=0\)