dễ mà :  a, 5 - ( 1997 - 2005 ) +1997

= ( 2005 + 5 ) - ( 1997 - 1997 )

= 2010 - 0

= 2010

a, 5  - (1997 -2005 ) + 1997 

= 5 - 1997 + 2005 +1997

=  (5 + 2005 ) - ( 1997 - 1997)

= 2010 - 0 

= 2010

b, 4567 + (1234 - 4567 )-4

=  4567  + 1234 - 4567  -4

= (4567 - 4567 ) + (1234 - 4)

= 0 + 1230 

= 1230 

c, 173 - ( 36 + 173 ) + [(175 - 27 ) - 175 - ( -36 + 50 )]

= 173 - 36 - 173 + 175 - 27 - 175 - 36 - 50 

= ( 173 - 173 ) + (175 - 175 ) - ( 36 + 36 ) - (27 + 50)

= 72 - 77 

= -5

d, 3 . (25 : 5 - 14 : 2 ) - 5 . ( 6 : 2)

= 3  (-2)  - 5 .3

= 3 ( -2 - 5 )

= 3 . (-7 )

= - 21

a) 5-(1997-2005)+1997

= 5-(-1997)+2005+1997

= (5+2005)+(-1997+1997)

= 2010+0

= 0

b) 4567+(1234-4567)-4

 làm tương tự câu a

Bài 1:

a) - | 12 - 14 | - | 98 - 15 + 2 | - 14 

= - | - 2 | - | 85 | - 14

= -2 - 85 - 14

= -101

b) ( -24 ) - ( 12 - 19 ) - | 15 - 12 - 7 |

= ( -24 ) - ( - 7 ) - | -4 |

= ( -24 ) + 7 - 4

= -21

Bài 2:

a) 5 - ( 1997 - 2005 ) + 1997

= 5 - 1997 + 2005 + 1997

= ( 5 + 2005 ) + ( 1997 - 1997 )

= 2010 + 0

= 2010

b) 1579 - ( 53 + 1679 ) - ( -53 )

= 1579 - 53 - 1679 + 53

= ( 1579 - 1679 ) + ( 53 - 53 )

= ( -100 ) + 0

= -100

c) -48725 - ( 357 - 48725 ) + 300

= -48725 - 357 + 48725 + 300

= [( -48725 ) + 48725 ] + ( 357 - 300 )

= 0 + ( -57 )

= -57

d) 4567 + ( 1234 - 4567 ) - 4

= 4567 + 1234 - 4567 - 4

= ( 4567 - 4567 ) + ( 1234 - 4 )

= 0 + 1230

= 1230

a) \(-\left|12-14\right|-\left|98-15+2\right|-14\)

\(=-\left|2\right|-\left|85\right|-14\)

\(=\left(-2\right)-85-14\)

\(=\left(-2\right)-\left(85+14\right)\)

\(=\left(-2\right)-99\)

\(=\left(-2\right)+\left(-99\right)=-101\)

2)

a) \(5-\left(1997-2005\right)+1997\)

\(=5-1997+2005+1997\)

\(=5+2005+\left(1997-1997\right)\)

Do một bên trừ một bên cộng đấy :)

\(=2010\)

b) \(1579-\left(53+1679\right)-\left(-53\right)\)

\(=1579-53-1679+53\)

\(=\left(-1679\right)-\left(1579\right)\)

a. 4567+(1234-4567)-4

=4567+1234-4567-4

=(4567-4567)+(1234-4)

=0+1230

=1230

2001-( 53 -1579 ) - ( - 53 )

=2001-53+1579+53

=(2001+1579)+(53-53)

=3580+0

=3580

35-17 + 2017 - 35 + ( -2017 )

=35-17+2017-35-2017

=(35-35)+(2017-2017)-17

=0+0-17

=-17

a) 4567 + ( 1234 - 4567 ) - 4

= 4567 + 1234 - 4567 - 4

= ( 4567 - 4567 ) + ( 1234 - 4 )

= 0 + 1230

= 1230

b) 2001 - ( 53 - 1579 ) - (-53)

= 2001 - 53 + 1579 + 53

= ( 2001 + 1579 ) - ( 53 - 53 )

= 3580 - 0

= 3580

c) 35 - 17 + 2017 - 35 + (-2017)

= 35 - 17 + 2017 - 35 - 2017

= ( 35 - 35 ) - 17 + ( 2017 - 2017 )

= 0 - 17 + 0

= -17 

\(a)4567+1234-4567-4\)

\(=\left(4567-4567\right)+\left(1234-4\right)=0+1230=1230\)

\(a)4567+1234-4567-4\)

\(=4567-4567+1234-4\)

\(=0+1230=1230\)

\(b)2001-53-1519-\left(-53\right)\)

\(=2001-53-1519+53\)

\(=2001-1519-53+53\)

\(=482\)

\(c)35-17-2017-35-\left(-2017\right)\)

\(=35-35-2017+2017-17\)

\(=0-0-17=-17\)

a.... ko bit

có đáp án rùi mà

a ukm ha

4567 + 1234 -4567 -4

 = 4567 - 4567 + 1234 - 4

= 0+ 1230

= 1230

\(4567+\left(1234-4567\right)-4\)

\(=4567+1234-4567-4\)

\(=\left(4567-4567\right)+\left(1234-4\right)\)

\(=0+1230\)

\(=1230\)

Trả lời: 

4567 + ( 1234 - 4567 ) - 4 

= 4567 + 1234 - 4567 - 4 

= ( 4567 - 4567 ) + ( 1234 - 4 ) 

= 0 + 1230

= 1230

(Theo mình nghĩ là 4567+1234-4567--66 chứ không phải 4567=1234-4576--66 có lẽ bạn viết nhầm.)

4567+ 1234-4567--66

=4567+1234-4567+66

=[4567+(-4567)]+(1234+66)

=0+1300

=1300.

Chúc bạn học tốt !!!

Tớ thấy đề của cậu hình như sai á , theo tớ thì đề sẽ là :

Tính tổng sau một cách hợp lý:

4567-1234-4567-(-66)

=3333-4567-(-66)
=-1234-(-66)
=-1168

a) Ta có: \(4567+1234-4567-\left(-66\right)\)

\(=4567-4567+1234+66\)

\(=1234+66=1300\)

b) Ta có: \(2004-15+54-2004-54\)

\(=\left(2004-2004\right)+\left(54-54\right)-15\)

\(=0+0-15\)

\(=-15\)

c) Ta có: \(-45789-357-45789+57\)

\(=-91578-300=-91878\)

bài 1

a)-7105-(155-7105)+355
 =-7105 -155 +7105 +355
 =(-7105 + 7105)+(-155 + 355)

 =0 + 200

=200
 

b)(35−815)−(795−65)b)(35-815)-(795-65)

=−780−730=-780-730

=−1510

$a\left)\right(-7105)-(155-7105)+355$

$=(-7105)-155+7105+335$

$=\left[\right(-7105)+7105]+(355-155)$

$=0+200$

$=200$

$b\left)\right(35-815)-(795-65)$

$=35-815-795+65$

$=(35+65)+\left[\right(-815)-795]$

$=100+(-1610)$

$=-1510$

c)5−197−2015−2015c)5−197−2015−2015

=(5−197)+[(−2015)−2015]=(5−197)+[(−2015)−2015]

=(−192)+(−4330)=(−192)+(−4330)

=−4522=−4522

d)4567+1234−4567−(−66)d)4567+1234−4567−(−66)

=(4567−4567)+[1234−(−66)]=(4567−4567)+[1234−(−66)]

=0+1300=0+1300

=1300
 

e)2004−15+54−2004−54e)2004−15+54−2004−54

=(2004−2004)+(54−54)−15=(2004−2004)+(54−54)−15

=0+0−15=0+0−15

=−15
 

g)1259−1409−12+1259+1409g)1259−1409−12+1259+1409

=(1259+1259)+(1409−1409)−12=(1259+1259)+(1409−1409)−12

=2518+0−12=2518+0−12

=2506