1/1x2+1/3x4+1/5x6+................+1/19x 20
giải ra giùm mình cái
giúp mình với:
1/1x2+1/2x3+1/3x4+1/4x5+1/5x6=?
= 1- 1/2+1/2-1/3+...+1/5-1/6
=1-1/6
=5/6
Giải dùm mình với!!!!
1/1x2+1/2x3+1/3x4+1/4x5+1/5x6
\(=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{5.6}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{5}-\frac{1}{6}\)
\(=1-\frac{1}{6}\)
\(=\frac{5}{6}\)
\(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}\)
=>\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
=> 1-\(\frac{1}{6}\)
=\(\frac{6}{6}-\frac{1}{6}=\frac{6}{6}+\frac{-1}{6}=\frac{5}{6}\)
1/1x2+1/2x3+1/3x4 +1/4x5+1/5x6+1/5x7
giải ra cho mik nha Cảm ơn
\(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}+\frac{1}{5x7}\)
Đề sai hay bạn sai v ạ, tính nhanh thì lẽ ra phải là 6x7
\(\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{5.6}+\dfrac{1}{5.7}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{5}-\dfrac{1}{7}\)
\(=1-\dfrac{1}{6}+\dfrac{1}{5}-\dfrac{1}{7}=\dfrac{187}{210}\)
ko nhaa cô giáo mik viết thế mà ko sai đou
1/1x2 + 1/2x3 +1/3x4 +1/4x5 +1/5x6
1/1x2 + 1/2x3 + 1/3x4 +1/4x5 +1/5x6
= 1 -1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6
= 1 - 1/6 = 5/6
Cho biểu thức A= 1/1x2 + 1/3x4 + 1/5x6 + ....... + 1/49x50
tính : 1/1x2+1/2x3+1/3x4+1/4x5+1/5x6
\(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(=\frac{1}{1}-\frac{1}{6}\)
\(=\frac{5}{6}\)
\(\frac{1}{1.2}\)\(+\)\(\frac{1}{2.3}\)\(+\)\(\frac{1}{3.4}\)\(+\)\(\frac{1}{4.5}\)\(+\)\(\frac{1}{5.6}\)
\(=\)\(\frac{1}{1}\)\(-\)\(\frac{1}{2}\)\(+\)\(\frac{1}{2}\)\(-\)\(\frac{1}{3}\)\(+\)\(\frac{1}{3}\)\(-\)\(\frac{1}{4}\)\(+\)\(\frac{1}{4}\)\(-\)\(\frac{1}{5}\)\(+\)\(\frac{1}{5}\)\(-\)\(\frac{1}{6}\)
\(=\)\(\frac{1}{1}\)\(-\)\(\frac{1}{6}\)
\(=\)\(\frac{5}{6}\)
Hok tốt
A=1/1x2+1/3x4+1/5x6+...+1/49x50
Chứng minh rằng A<1
Lời giải:
$A=\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{49.50}$
$< \frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{25.26}$
$=\frac{2-1}{1.2}+\frac{3-2}{2.3}+\frac{4-3}{3.4}+...+\frac{26-25}{25.26}$
$=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+....+\frac{1}{25}-\frac{1}{26}$
$=1-\frac{1}{26}< 1$ (đpcm)
Tính nhanh tổng sau :
1/1x2 + 1/2x3 + 1/3x4 + 1/4x5 + 1/5x6 + 1/6x7
ai nhanh mình tích cho mình cần gấp đó
1/1x2 + 1/2x3 + 1/3x4 + 1/4x5 + 1/5x6 + 1/6x7
=1/1-1/2+1/2-1/3+...-1/7
=1+(1/2-1/2+1/3-1/3+...+1/6-1/6)-1/7
=1 +0+0+...-1/7
=1-1/7
=6/7
Kếết quả là 116/24
Rút gọn ra phân số tối giản là 29/6
Cho A = 1/1x2 +1/3x4 + 1/5x6 + ...+1/15x16 + 1/17x18
Chứng tỏ:A=1/10+1/11+1/12+...+1/17+1/18.
Bạn nào giải giúp mình nhé!Nhớ ghi ra cách trình bày (nếu được)
Tks