Bài 1:

2^\(x\) = 4

2\(^x\) = 2²

 \(x=2\)

Vậy \(x=2\)

Bài 2:

2\(^x\) = 8

2\(^x\) = 2³

\(x=3\)

Vậy \(x=3\)

Bài 3

2\(^x\) = 16

2\(^x\) = 2⁴

  \(x=4\)

Vậy \(x=4\)

a)     4^x  = 8^12

    (2^2)^x = (2^3)^12

     2^2x   = 2^36

=> 2x = 36

=>   x = 36 : 2 = 18

a) 4^x=8^12

4^x=(2^3)^12

4^x=2^36

4^x=4^18

=> x=18 hoặc -18

Các phần khác tương tự nha

a) 4^x=8¹²

(2²)^x=(2³)¹²

2^2x=2³⁶

2x=36

  x=36:2

  x=18

vậy x=18

b) 3^2x+2=9¹⁰

3^2x+2=(3²)¹⁰

3^2x+2=3²⁰

2x+2=20

2x=20-2

2x=18

  x=18:2

  x=9

vậy x=9

c)2^x=4³:2⁵

2^x=(2²)³:2⁵

2^x=2⁶:2⁵

2^x=2^6-5

2^x=2¹

x=1

vậy x=1

hello 123

mũ viết thay cái này nè ^

shirt + 6

viết vậy khó hiểu quá

rối loạn mắt rồi

a)

\(\text{( 25 – 2x )³ : 5 – 3^2 = 4^2}\)

\(\text{( 25 – 2x )³ : 5 – 9 = 16}\)

\(\text{( 25 – 2x )³ : 5 = 16 + 9}\)

\(\text{( 25 – 2x )³ : 5 = 25}\)

\(\text{( 25 – 2x )³ = 25 . 5}\)

\(\text{( 25 – 2x )³ = 125}\)

\(\text{( 25 – 2x )³ = 5³}\)

\(\text{25 – 2x = 5}\)

\(\text{2x = 25 – 5}\)

\(\text{2x = 20}\)

\(\text{x = 10}\)

\(\text{________________________________________}\)

b)

\(\text{2.3^x = 10.3^12 + 8.27^4}\)

\(\text{2.3^x = 10.3^12 + 8.(3^3)^4}\)

\(\text{2.3^x = 3^12 . (10+8)}\)

\(\text{2.3^x = 3^12 . 18}\)

\(\text{3^x = 3^12 . 18:2}\)

\(\text{3^x = 3^12 . 9}\)

\(\text{3^x = 3^12 . 3^2}\)

\(\text{3^x = 3^14}\)

\(\text{=> x=14}\)

2^x = 4³ : 2⁵

2^x = (2²)³ : 2⁵

2^x = 2⁶ : 2⁵

2^x = 2

=> x = 1

viết kiểu gì ko hiểu

gì vậy trời

1)1/9 x 3^x = 2187:81=27

            3^x=27:1/9=243=3⁵

            =>x=5

\(\frac{1}{9}.3^4.3^x=3^7\)

\(\Leftrightarrow3^x=3^7:\frac{1}{9}:3^4=243\)

\(\Leftrightarrow3^x=3^5\)

\(\Leftrightarrow x=5\)

3, \(\left(x-2\right)^2-5\left(2-x\right)=0\Leftrightarrow\left(2-x\right)^2-5\left(2-x\right)=0\)

\(\Leftrightarrow\left(2-x-5\right)\left(2-x\right)=0\Leftrightarrow\left(x+3\right)\left(2-x\right)=0\Leftrightarrow x=-3;x=2\)

4, \(x^3-8+2x^2-4x=0\Leftrightarrow\left(x-2\right)\left(x^2+2x+4\right)+2x\left(x-2\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(x+2\right)^2=0\Leftrightarrow x=\pm2\)

5, \(x^2\left(x-3\right)+18-6x=0\Leftrightarrow x^2\left(x-3\right)-6\left(x-3\right)=0\)

\(\Leftrightarrow\left(x^2-6\right)\left(x-3\right)=0\Leftrightarrow x=\pm\sqrt{6};x=3\)

tìm x

3, ( x - 2 ) mũ 2 - 5( 2 - x ) = 0

x=-3, x=2

4, ( x mũ 3 - 8 ) + 2x mũ 2 - 4x = 0

x= 2 , x= -2 

5, x mũ 2 ( x - 3 ) + 18 - 6x = 0

x=-căn bậc hai(6), x=căn bậc hai(6), x=3

sao mọi người  tl mà ko k vậy