\(x+\left(\frac{-31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)

Xét \(x+\left(\frac{-31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x\)

\(\Rightarrow2x=\left(\frac{49}{12}\right)^2-\left(\frac{-31}{12}\right)^2=\frac{2401}{144}+\frac{961}{144}\)

\(\Rightarrow2x=\frac{3362}{144}\)

\(\Rightarrow x=\frac{3362}{144}.\frac{1}{2}=\frac{1681}{144}\)

Ta lai xét :

\(x+\left(\frac{-31}{12}\right)^2=y^2\)

\(\Rightarrow\frac{1681}{144}+\frac{-961}{144}=y^2\)

\(\Rightarrow\frac{720}{144}=y^2\)

\(\Rightarrow y^2=5\)

\(\Rightarrow y=2,236067977\)

\(x+\left(\frac{-31}{12}\right)^2\left(\frac{49}{12}\right)^2-x=y\)

\(x+\frac{961}{144}.\frac{2401}{144}-x=y\)

\(x+\frac{2307361}{20736}-x=y\)

\(y=\frac{2307361}{20736}\)

         Thay vào \(x+\frac{961}{144}.\frac{2401}{144}-x=y\) ta được

\(x+\frac{2307361}{20736}-x=y\)

\(x-x+\frac{2307361}{20736}=\frac{2307361}{20736}\)

Vậy x thuộc N;\(y=\frac{2307361}{20736}\)

\(\Leftrightarrow\left(x-x\right)+\frac{961}{144}\cdot\frac{2401}{144}=y\Leftrightarrow y=\frac{2307361}{20736}\)

\(\Rightarrow x\in R\)

( hình như đề sai :v )

đề saI

​

X+(-31/12)^2 = (49/12)^2 -x=y

(-31/12)^2 - (49/12)^2 = -x-x = y

961/144 - 2410/144 = -2x

-10=-2x

10=2x

10:2=x

5=x

X+961/144=y^2

5+961/144=y^2

1681/144=y^2

=>y=41/144

Dấu phân số mình ký hiệu là / đó nha

Vì 

 \(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x\Rightarrow2x=\left(\frac{49}{12}\right)^2-\left(-\frac{31}{12}\right)^2=10\)

=> 2x = 10 => x = 5

Thay x = 5 vào ta có :

     \(5+\left(-\frac{31}{12}\right)^2=y^2\Leftrightarrow\frac{1681}{144}=y^2=\left(\frac{41}{12}\right)^2=\left(-\frac{41}{12}\right)^2\)

=> y = 41/12 hoặc y = -41/12 

Tìm x,y

x*(x-y)=3/10 và y*(x-y)=–3/20

Ta có:

\(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x\)

\(\Rightarrow2x+\frac{961}{144}=\frac{2401}{144}\)

\(\Rightarrow2x=\frac{2401}{144}-\frac{961}{144}\)

\(\Rightarrow2x=\frac{1440}{144}\)

\(\Rightarrow2x=10\)

\(\Rightarrow x=5\)

Vậy \(x=5\)

tìm x và y nha

x+(-31/12)^2=(49/12)^2-x

x+x=(49/12)^2-(-31/12)^2

tính x

từ x tìm ra y

b)x(x-y):[y(x-y)]=3/10:(-3/50)=...

=>x/y=... =>x=...;y=...