Phân tích đa thức thành nhân tử :
a) x + 2a( x - y ) - y
b) x^2 - ( a + b )x + ab
c) x ( y^2 - z^2 ) + y( z^2 - x^2 ) + z( x^2 - y^2 )
Phân tích đa thức thành nhân tử :
a) x + 2a( x - y ) - y
b) x^2 - ( a + b ) x + ab
f) x( y^2 - z^2 ) + y( z^2 - x^2 ) + z( x^2 - y^2 )
a x+ 2a(x-y)-y
=x-y+2a(x-y)
=(x-y)(1+2a)
b x^2-(a+b)x+ab
=x^2-(xa+xb)+ab
=x^2-xa-xb+ab
=x(x-a)-b(x-a)
=(x-a)(x-b)
f x(y^2-z^2)+y(z^2-x^2)+z(x^2-y^2)
=xy^2-xz^2+yz^2-yx^2+zx^2-zy^2
=-xzy^2-xyz^2-zyx^2
=-xyz(y+z+x)
Phân tích đa thức thành nhân tử:
a) x^2+2(x+y)y-z^2
b) x(y^2-z^2)+y(z^2-x^2)+z(x^2-y^2)
c) a^3+b^3+a^2c+b^2c-abc
phân tích đa thức thành nhân tử
a, xy (x + y) + yz (y + z) + zx (z + x) + 3xyz
b, x (y^2 - z^2) + y (z^2 - x^2) + z (x^2 - y^2)
\(x\left(y^2-z^2\right)+y\left(z^2-x^2\right)+z\left(x^2-y^2\right)\)
\(=xy^2-xz^2+yz^2-x^2y+zx^2-zy^2\)
\(=xy^2-xz^2+yz^2-x^2y+zx^2-zy^2-xyz+xyz\)
\(=\left(yz^2-xz^2-xyz+x^2z\right)-\left(zy^2-xyz-xy^2+x^2y\right)\)
\(=z\left(yz-xz-xy+x^2\right)-y\left(zy-xz-xy+x^2\right)\)
\(=\left(z-y\right)\left(yz-xz-xy+x^2\right)\)
\(=\left(z-y\right)\left[y\left(z-x\right)-x\left(z-x\right)\right]\)
\(=\left(z-y\right)\left(y-x\right)\left(z-x\right)\)
Phân tích đa thức sau thành nhân tử bằng pp nhóm hạng tử chung:
a) (a - b)(a + 2b) - (b- a)(2a - b) - (a - b)(a + 3b)
b) (x + y)(2x - y) + (2x - y)(3x - y) - (y - 2x)
c) x2(y - z) + y2(z - x) + z2(x - y)
a,\(\left(a-b\right)\left(a+2b\right)-\left(b-a\right)\left(2a-b\right)-\left(a-b\right)\left(a+3b\right)\)
\(=\left(a-b\right)\left(a+2b\right)+\left(a-b\right)\left(2a-b\right)-\left(a-b\right)\left(a+3b\right)\)
\(=\left(a-b\right)\left(a+2b+2a-b-a-3b\right)\)
\(=\left(a-b\right)\left(2a-2b\right)\)
\(=\left(a-b\right)2\left(a-b\right)\)
\(=2\left(a-b\right)^2\)
b,\(\left(x+y\right)\left(2x-y\right)+\left(2x-y\right)\left(3x-y\right)-\left(y-2x\right)\)
\(=\left(x+y\right)\left(2x-y\right)+\left(2x-y\right)\left(3x-y\right)+\left(2x-y\right)\)
\(=\left(2x-y\right)\left(x+y+3x-y+1\right)\)
\(=\left(2x-y\right)\left(4x+1\right)\)
c,\(x^2\left(y-z\right)+y^2\left(z-x\right)+z^2\left(x-y\right)\)
\(=x^2y-x^2z+y^2z-y^2x+z^2\left(x-y\right)\)
\(=x^2y-y^2x-x^2z+y^2z+z^2\left(x-y\right)\)
\(=xy\left(x-y\right)-z\left(x^2-y^2\right)+z^2\left(x-y\right)\)
\(=xy\left(x-y\right)-z\left(x-y\right)\left(x+y\right)+z^2\left(x-y\right)\)
\(=\left(x-y\right)\left(xy-zx-zy+z^2\right)\)
\(=\left(x-y\right)\left(y-z\right)\left(x-z\right)\)
a) ( a - b )( a + 2b ) - ( b - a )( 2a - b ) - ( a - b )( a + 3b )
= ( a - b )( a + 2b ) + ( a - b )( 2a - b ) - ( a - b )( a + 3b )
= ( a - b )[ ( a + 2b ) + ( 2a - b ) - ( a + 3b ) ]
= ( a - b )( a + 2b + 2a - b - a - 3b )
= ( a - b )( 2a - 2b )
= 2( a - b )( a - b ) = 2( a - b )2
b) ( x + y )( 2x - y ) + ( 2x - y )( 3x - y ) - ( y - 2x )
= ( x + y )( 2x - y ) + ( 2x - y )( 3x - y ) + ( 2x - y )
= ( 2x - y )[ ( x + y ) + ( 3x - y ) + 1 ]
= ( 2x - y )( x + y + 3x - y + 1 )
= ( 2x - y )( 4x + 1 )
c) x2( y - z ) + y2( z - x ) + z2( x - y )
= x2y - x2z + y2z - y2x + z2( x - y )
= ( x2y - y2x ) - ( x2z - y2z ) + z2( x - y )
= xy( x - y ) - z( x2 - y2 ) + z2( x - y )
= xy( x - y ) - z( x - y )( x + y ) + z2( x - y )
= ( x - y )[ xy - z( x + y ) + z2 ]
= ( x - y )( xy - zx - zy + z2 )
= ( x - y )[ ( xy - zx ) - ( zy - z2 ) ]
= ( x - y )[ x( y - z ) - z( y - z ) ]
= ( x - y )( y - z )( x - z )
Phân tích các đa thức sau thành nhân tử
a) (x^2+y^2+z^2)(x+y+z)^2+(xy+yz+zx)^2
b) 2(x^4+y^4+z^4)-(x^2+y^2+z^2)^2-2(x^2+y^2+z^2)(x+y+z)^2+(x+y+z)^4
a,Từ giả thiết ta có
(x2+y2+z2)(x+y+z)2+(xy+yz+zx)2
=(x2+y2+z2)(x2+y2+z2+2xy+2yz+2zx)+(xy+yz+zx)2
Đặt x2+y2+z2=a
xy+yz+zx=b
=>(x2+y2+z2)(x2+y2+z2+2xy+2yz+2zx)+(xy+yz+zx)2
=a(a+2b)+b2
=a2+2ab+b2
=(a+b)2
=(x2+y2+z2+xy+yz+zx)2
câu b hơi dài mình gửi sau nhé
Ta có: 2(x^4+y^4+z^4)-(x^2+y^2+z^2)^2-2(x^2+y^2+z^2)(x+y+z)^2+(x+y+z)^4
Gọi x^4+y^4+z^4=a
x^2+y^2+z^2=b
x+y+z=c
=>2(x^4+y^4+z^4)-(x^2+y^2+z^2)^2-2(x^2+y^2+z^2)(x+y+z)^2+(x+y+z)^4=2a-b^2-2bc^2+c^4
=2a-2b^2+b^2-2bc^2+c^4
=2(a-b^2)+(b+c^2)^2
Ta có
2(a-b2)=2[x^4+y^4+z^4-(x^2+y^2+z^2)2]
=2[x^4+y^4+z^4-x^4-y^4-z^4-2x2y2-2y2z2-2z2x2]
=2.(-2)(x2y2+y2z2+z2x2)
=-4(x2y2+y2z2+z2x2)
Lại có
(b+c^2)^2
=[(x^2+y^2+z^2)+(x+y+z)2]2
=[(x^2+y^2+z^2)-(x^2+y^2+z^2)-2(xy+yz+zx)]2
=4(xy+yz+zx)2
=>2(a-b^2)+(b+c^2)^2
=-4(x2y2+y2z2+z2x2)+4(xy+yz+zx)2
=8xyz(x+y+z)
phân tích đa thức sau thành nhân tử x^2 y^2(y-x)+y^2 z^2(z-y)-z^2 x^2(z-x)
bài 1: Phân tích đa thức thành nhân tử
a, (xy-1)2+ (x+y)2
b, a2+2a2+2a+1
c, (1+2a).(1-2a)-a.(a+2).(a-2)
d, a2+b2-a2b2+ab-a-b
e, xy.(x+y)-yz.(y+z)+xz(x-z)
f, xyz-(xy+yz+zx)+(x+y+z)-1
giúp em với ạ ! em đang cần gấp
\(a,=\left(xy-1-x-y\right)\left(xy-1+x+y\right)\\ b,Sửa:a^3+2a^2+2a+1\\ =a^3+a^2+a^2+a+a+1=\left(a+1\right)\left(a^2+a+1\right)\\ c,=1-4a^2-a\left(a^2-4\right)=1-4a^2-a^3+4a\\ =\left(1-a\right)\left(1+a+a^2\right)+4a\left(1-a\right)\\ =\left(1-a\right)\left(1+5a+a^2\right)\\ d,=\left(a^2-a^2b^2\right)+\left(b^2-b\right)+\left(ab-a\right)\\ =a^2\left(1-b\right)\left(1+b\right)+b\left(b-1\right)+a\left(b-1\right)\\ =\left(b-1\right)\left(-a^2-ab+b+a\right)\\ =\left(b-1\right)\left(b-1\right)\left(a+b\right)\left(1-a\right)\)
\(e,=x^2y+xy^2-yz\left(y+z\right)+x^2z-xz^2\\ =\left(x^2y+x^2z\right)+\left(xy^2-xz^2\right)-yz\left(y+z\right)\\ =x^2\left(y+z\right)+x\left(y-z\right)\left(y+z\right)-yz\left(y+z\right)\\ =\left(y+z\right)\left(x^2+xy-xz-yz\right)\\ =\left(y+z\right)\left(x+y\right)\left(x-z\right)\)
\(f,=xyz-xy-yz-xz+x+y+z-1\\ =xy\left(z-1\right)-y\left(z-1\right)-x\left(z-1\right)+\left(x-1\right)\\ =\left(z-1\right)\left(xy-y-x+1\right)=\left(z-1\right)\left(x-1\right)\left(y-1\right)\)
Phân tích đa thức thành nhân tử:
a) (x+y) . (y+z) . (z+x) + xyz
b) x . (y2-z2) + y . (z2-x2) + z . (x2-y2)
y(x+y)+yz(y+z)+xz(x+z)+2xyz
= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz
= xy(x + y) + yz(y + z + x) + xz(x + z + y)
= xy(x + y) + z(x + y + z)(y + x)
= (x + y)(xy + zx + zy + z²)
= (x + y)[x(y + z) + z(y + z)]
= (x + y)(y + z)(z + x)
phân tích đa thức sau thành nhân tử : B=2(x^4+y^4+z^4)-(x^2+y^2+z^2)^2-2(x^2+y^2+z^2)(x+y+z)^2+(x+y+z)^4 toán 8