Tìm x biết:
\(\frac{75}{2}-\frac{1}{50}.\left(\frac{2}{3}x-1\right)^3=24\)
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Tìm x biết: \(\frac{75}{2}-\frac{1}{50}.\left(\frac{2}{3}x-1\right)^3=24\)
\(\frac{75}{2}-\frac{1}{50}.\left(\frac{2}{3}x-1\right)^3=24\)
Tìm x
\(\frac{75}{2}-\frac{1}{50}.\left(\frac{2}{3}x-1\right)^3=24\)
Tìm x
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Tìm x biết:
a) 3.(x-1)2 =12
b) \(\frac{75}{2}-\frac{1}{50}.\left(\frac{2}{3}x-1\right)^3=24\)
c) 3.(x-2)2 +\(\frac{1}{2}\)(2x-4)2=45
a) (x-1)2 =12:3
(x-1)2 =4
=> x-1=4 hoặc x-1=-4
1) x-1=4 2)x-1=-4
x=4+1 x=-4+1
x=5 x=-3
Vậy x thuộc {5;-3}
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Tìm x biết :
a)\(\frac{2}{3}x-50\%x-\left(-\frac{4}{5}\right):1\frac{3}{5}=-0,12\)\(+1\frac{3}{25}\)
b)\(\left(-1\frac{1}{6}+\frac{2}{3}-\frac{3}{4}\right):x+\left(-1\frac{11}{12}\right).1\frac{21}{23}=-6\frac{1}{3}\)
c)\(50\%x-\frac{1}{3}x-\left(\frac{-2}{3}\right)^2.\left(-1\frac{1}{8}\right)=-119\frac{3}{4}+120\frac{5}{6}\)
Tìm x biết: \(1.\frac{1}{30}:\left(24.\frac{1}{6}-24.\frac{1}{5}\right)-\frac{1.\frac{1}{2}-\frac{3}{4}}{4.x-\frac{1}{2}}=\left(-1.\frac{1}{15}\right):\left(8.\frac{1}{5}-8.\frac{1}{3}\right)\)
Tìm x biết \(1\frac{1}{30}:\left(24\frac{1}{6}-24\frac{1}{5}\right)-\left(1\frac{1}{2}-\frac{3}{4}\right):\left(4x-\frac{1}{2}\right)=\left(-1\frac{1}{15}\right):\left(8\frac{1}{5}-8\frac{1}{3}\right)\)
Tìm x biết
\(\frac{1}{3}x+650\%x-x=-6\)
\(2\left(x-\frac{1}{2}\right)+3\left(-1+\frac{x}{3}\right)=x\left(\frac{2}{x}-1\right)\)
\(\frac{x-2}{20}=\frac{5}{2-x}\)
\(\left(\frac{x}{3}+\frac{1}{2}\right)\left(75\%-1\frac{1}{2}\right)=0\)
1) tìm x biết
a) \(\left(\frac{2}{3}\right)^x=\left(\frac{4}{9}\right)^{50}\)
b) \(\left(\frac{2}{3}-x\right)^2=\frac{1}{36}\)
c)\(\left(x-\frac{1}{2}\right)^{50}-\left(\frac{1}{3}\right)^{20}\times\left(-\frac{1}{9}\right)^{15}\)
2) chứng tỏ
\(\left(74^{m+1}+74^m\right)⋮25\)
a) \(\left(\frac{2}{3}\right)^x=\left(\frac{4}{9}\right)^{50}\)
\(\Rightarrow\left(\frac{2}{3}\right)^x=\left(\frac{2^2}{3^2}\right)^{50}\)
\(\Rightarrow\left(\frac{2}{3}\right)^x=\left(\frac{2}{3}\right)^{100}\)
\(\Rightarrow x=100\)
Vậy x = 100
b) \(\left(\frac{2}{3}-x\right)^2=\frac{1}{36}\)
\(\Rightarrow\left(\frac{2}{3}-x\right)^2=\left(\frac{1}{6}\right)^2\)
\(\Rightarrow\frac{2}{3}-x=\frac{1}{6}\)
\(\Rightarrow x=\frac{2}{3}-\frac{1}{6}\)
\(\Rightarrow x=\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\)
2)
Ta có:
\(74^{m+1}+74^m=74^m.74^1+74^m=74^m.\left(74+1\right)=74^m.75⋮25\)
( vì \(75⋮25\) )
\(\Rightarrowđpcm\)
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