So sanh 2^91 va 5^35
So sanh : 2^91 va 5^35
co: 2^91 = (2^13) ^7
5^35 = (5^5)^7
suy ra 2 mu 91 lon hon 5 mu 35
so sanh 291 va 5 35
Ta có:\(2^{91}=2^{13.7}=\left(2^{13}\right)^7=8192^7\)
\(5^{35}=5^{5.7}=\left(5^5\right)^7=3125^7\)
Vì 8192 > 3125 nên \(2^{91}>5^{25}\)
so sanh 291 va 535
291=(213)7=81927
535=(55)7=31257
Vì 8192>3125 nên 81927>31257 hay 291>535
so sanh
291 va 535
so sanh
a,2^160 va 4^120; b,2^91 va 5^35; c,A=2^0+2^1+2^2+...+2^12 va B=2^11
so sanh:
\(2^{91}\)va\(5^{35}\)
Ta có : 291 = 213.7 = (213)7 = 81927
535 = 55.7 = (55)7 = 31257
Vì 8192 > 3125 nên 81927 > 31257 nên 291 > 535
291=(213)7=81927
535=(55)7=31257
vì 81927>31257nên 219>535
chúc bạn học tốt!!!
\(2^{91}=\left(1.2\right)^{91}=1^{182}\)
\(5^{35}=\left(1.5\right)^{35}=1^{175}\)
Vù 182 lớn hơn 175 nên \(1^{182}>1^{175}\)
Vậy \(2^{91}>5^{35}\)
so sanh
224va 316
9920va 999910
291va 535
2^24 = (2^3)^8 = 8^8
3^16 = (3^2)^8 = 9^8
Vì 8^8 < 9^8 => 2^24 < 3^16
99^20 = 99^10 . 99^10 < 99^10 . 101^110 = (99.101)^10 = 9999^10
=> 99^20 < 9999^10
2^91 = (2^13)^7 = 8192^7
5^35 = (5^5)^7 = 3125^7
Vì 8192^7 > 3125^7 => 2^91 > 5^35
k mk nha
cac ban oi giup minh voi
so sanh 2 mu 91 va 5 mu 35 dang luy thua lop 6 nang cao
\(2^{91}\)=2,475880079x1027
\(5^{35}\)=2,910383046x1024
Vay \(2^{91}\)>\(5^{35}\)
ta có:2^91>2^90 , 2^90=2^5^18=32^18
5^35<5^36 , 5^36=5^2^18=25^18
vì 32^18>25^18
=>2^91 > 5^35
Bai 1: So sanh:
291 va 535
Bai 2: Tim x:
5x+2 =625
Bài 1:2^91=(2^13)^7=8192^7
5^35=(5^5)^7=3125^7
Mà 8192>3125=>8192^7>3125^7
=>2^91>5^35
Bài 2:5x+2 = 54
=> x+2 = 4
x = 4-2
x = 2