\(=25\cdot\left(76+24\right)+75\left(147-47\right)\)

=10000

25. (76+24) + 75.(147-47)

= 25. 100 +75. 100

= 10000

25.76 + 75.147 + 25.24 - 47.75
=[ 25 . ( 76 + 24 )] + [75 . ( 147 – 47 ) ]
= [ 25 . 100 ] + [ 75 . 100 ]
= 2500 + 7500
= 10 000

a) 15 . 18 = (10+5).18 = 180 + 90= 270

b)  25.24   = (20+5).24 = 480 + 120 = 600

c)125.72 = (100+25) . 72 = 7200 + 1800 = 9000

d) 55.14 = 55. ( 10+4) = 550 + 220= 770

a. 15.18=3.5.3.6=(3.3).(5.6)=9.30=270

b. 25.24=5.5.6.4=(5.4).(5.6)=20.30=600

c. 125.72=5^3.2^3.9=(5.2)^3.9=1000.9=9000

d. 55.14=5.11.7.2=(7.11).(5.2)=77.10=770

a) 15.18

=3.5.3.6

= (3.3).(5.6)

=9.30

=270

b) 25.24

=5.5.2.12

=(5.2).(5.12)

=10.60

=600

c)125.72

=25.5.8.9

=(25.8).(5.9)

=200.45

=9000

d)55.14

=5.11.2.7

=(5.2).(11.7)

=10.77

=770.Hok tốt~

270

600

9000

770

theo thứ tự r đó

a) 15.18

=3.5.3.6

=9.30

=270

b) 25.24

=5.5.2.2.6

=10.10.6

=600

a) 270

 b)600

 c)9000

  d)770

a) 15.18 = 3.5.3.6= 3².5.6= 9.30 = 270

b) 25.24= 25.4.6= 100.6 = 600

c) 125.72= 5.5².4.18 = 5.100.18= 1800.5=9000   

d) 55.14= 5.11.7.2 = 5.2.11.7= 10.11.7= 110.7= 770

\(A=\frac{1}{25.24}+\frac{1}{24.23}+...+\frac{1}{6.5}\)

\(=\frac{25-24}{24.25}+\frac{24-23}{23.24}+...+\frac{6-5}{5.6}\)

\(=\frac{1}{24}-\frac{1}{25}+\frac{1}{23}-\frac{1}{24}+...+\frac{1}{5}-\frac{1}{6}\)

\(=\frac{1}{5}-\frac{1}{25}=\frac{4}{25}\)

Vậy \(A=\frac{4}{25}\)

Ta có :  \(A=\frac{1}{25.24}+\frac{1}{24.23}+...+\frac{1}{6.5}\)

                \(=\frac{1}{25}-\frac{1}{24}+\frac{1}{24}-\frac{1}{23}+...+\frac{1}{6}-\frac{1}{5}\)

                \(=\frac{1}{25}-\frac{1}{5}\)\(=\frac{1}{25}-\frac{5}{25}=\frac{-4}{25}\)

650-(28.25):5+(25.24):5+26.25

=650-700:5+600:5+26.25

=650-140+120+650

=1280

Ai k mình mình k lại cho

A = 44 . 82 -2² + 18 . 44

   =  44 . 82 - 4 + 18 . 44

   =  44. ( 82 + 18 ) - 4

   =  44 .     100      - 4

   =     4400            - 4

   =                   4396

Ta có: \(A=44\cdot82-2^2+18\cdot44\)

\(=44\cdot\left(82+18\right)-4\)

\(=44\cdot100-4\)

\(=4400-4=4396\)