Ta so sánh 2009/2010 và 2010/2009
Ta có 2009/2010<1<20010/2009
=>2009/2010<2010/2009 => -2009/2010 > 2010/- 2009
 

\(\frac{-2009}{2010}và\frac{2010}{-2009}=>\frac{-2009}{2010}và\frac{-2009}{2010}=>\frac{-2009}{2010}=\frac{-2009}{2010}\)

Vậy \(\frac{-2009}{2010}=\frac{2010}{-2009}\)

vi \(\frac{-2009}{2010}>\frac{-2010}{1010}=1\)

\(\frac{2010}{-2009}=\frac{-2010}{2009}

\(\dfrac{2009}{2010}=\dfrac{2009\cdot10001}{2010\cdot10001}=\dfrac{20092009}{20102010}\)

\(\dfrac{2009}{2010}=\dfrac{20092009}{20102010}\)

1.\(\frac{1001}{1000}>\frac{1000}{1000}=1=\frac{1003}{1003}>\frac{1002}{1003}\Rightarrow\frac{1001}{1000}>\frac{1002}{1003}\)

2.a) \(x=\frac{a-3}{2a}\left(a\ne0\right)\)

\(=\frac{1}{2}\left(1-\frac{3}{a}\right)\inℤ\)

\(\Leftrightarrow\hept{\begin{cases}1-\frac{3}{a}\inℤ\\1-\frac{3}{a}⋮2\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}\frac{3}{a}\inℤ\\\frac{3}{a}\equiv1\left(mod2\right)\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}a\inƯ\left(3\right)=\left\{\pm1;\pm3\right\}\\\frac{3}{a}\equiv1\left(mod2\right)\end{cases}}\)

Ta có bảng :

Vậy \(a\in\left\{\pm1;\pm3\right\}\)

b)Ta có:\(\frac{a+2009}{a-2009}=1+\frac{4018}{a-2009}\left(a\ne2009\right)\)

\(\frac{b+2010}{b-2010}=1+\frac{4020}{b-2010}\left(b\ne2010\right)\)

\(\Rightarrow\frac{4018}{a-2009}=\frac{4020}{b-2010}\)

\(\Rightarrow\frac{a-2009}{4018}=\frac{b-2010}{4020}\)

\(\Rightarrow\frac{a-2009}{2009}=\frac{b-2010}{2010}\)

\(\Rightarrow\frac{a}{2009}-1=\frac{b}{2010}-1\)

\(\Rightarrow\frac{a}{2009}=\frac{b}{2010}\)

Thanks!

 mod2 là gì vậy