\(8x^2-2x-3=8x^2+4x-6x-3=4x\left(2x+1\right)-3\left(2x+1\right)=\left(4x-3\right)\left(2x+1\right)\)

\(8x^2-2x-3=\left(4x-3\right)\left(2x+1\right)\)

x³ - 2x² - 8x

= x( x² - 2x - 8 )

= x( x² - 4x + 2x - 8 )

= x[ x( x - 4 ) + 2( x - 4 ) ]

= x( x - 4 )( x + 2 )

\(x^3-2x^2-8x=x\left(x^2-2x-8\right)=x\left(x^2-2x+1-9\right)=x\left[\left(x-1\right)^2-3^2\right]=x\left(x-4\right)\left(x+2\right)\)

Trả lời:

x³ - 8x + 2x ( x - 2 )

= x³ - 8x + 2x² - 4x

= x ( x² - 8 + 2x - 4 )

= x ( x² + 2x - 12 )

cần gấp nha , mik chọn cho

\(2x^3-5x^2+8x-3\)

\(\Leftrightarrow2x^3-x^2-4x^2+2x+6x+3\)

\(\Leftrightarrow x^2\cdot\left(2x-1\right)-2x\cdot\left(2x-1\right)+3\cdot\left(2x+1\right)\)

\(\Leftrightarrow\left(2x-1\right)\cdot\left(x^2-2x+3\right)\)

\(2x^3-5x^2+8x-3\)

\(=2x^3-x^2-4x^2+2x+6x-3\)

\(=x^2\left(2x-1\right)-2x\left(2x-1\right)+3\left(2x-1\right)\)

\(=\left(2x-1\right)\left(x^2-2x+3\right)\)

 = 2x^3  - 4x^2 - x^2 + 2x + 6x - 3 

 = 2x^2 ( x - 1/2 ) - x ( x - 1/2 ) +3 ( x - 1/2 )

= ( x - 1/2 )( 2x^2 - x + 3 ) 

a: \(x^4-2x^3+x^2-2x\)

\(=\left(x^4-2x^3\right)+\left(x^2-2x\right)\)

\(=x^3\left(x-2\right)+x\left(x-2\right)\)

\(=x\left(x-2\right)\left(x^2+1\right)\)

b: \(x^4+x^3-8x-8\)

\(=\left(x^4+x^3\right)-\left(8x+8\right)\)

\(=x^3\left(x+1\right)-8\left(x+1\right)\)

\(=\left(x+1\right)\left(x^3-8\right)\)

\(=\left(x+1\right)\left(x-2\right)\left(x^2+2x+4\right)\)