\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)=\frac{23}{27}-\frac{5}{9}\)
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)=\frac{8}{27}\)
\(\left(2+\frac{3}{4}x\right)=\frac{7}{9}:\frac{8}{27}\)
\(\left(2+\frac{3}{4}x\right)=\frac{7}{9}.\frac{27}{8}\)
\(\left(2+\frac{3}{4}x\right)=\frac{21}{8}\)
\(\frac{3}{4}x=\frac{21}{8}-2\)
\(\frac{3}{4}x=\frac{5}{8}\)
\(x=\frac{5}{8}:\frac{3}{4}\)
\(x=\frac{5}{8}.\frac{4}{3}\)
\(x=\frac{5}{6}\)
\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)=\frac{23}{27}-\frac{5}{9}\)
\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)=\frac{8}{27}\)
\(2+\frac{3}{4}x=\frac{7}{9}\div\frac{8}{27}\)
\(2+\frac{3}{4}x=\frac{21}{8}\)
\(\frac{3}{4}x=\frac{21}{8}-2\)
\(\frac{3}{4}x=\frac{5}{8}\)
\(x=\frac{5}{8}\div\frac{3}{4}\)
\(x=\frac{5}{6}\)
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)=\frac{8}{27}\)
\(2+\frac{3}{4}x=\frac{7}{9}:\frac{8}{27}\)
\(2+\frac{3}{4}x=\frac{21}{8}\)
\(\frac{3}{4}x=\frac{21}{8}-2\)
\(\frac{3}{4}x=\frac{5}{8}\)
\(x=\frac{5}{6}\)
Vậy \(x=\frac{5}{6}\)
Tính giá trị biểu thức
\(1.A=\frac{1}{5}+\frac{3}{17}-\frac{4}{3}+\left(\frac{4}{5}-\frac{3}{17}+\frac{1}{3}\right)-\frac{1}{7}+\left[\frac{-14}{30}\right]\)
\(2.B=\left(\frac{5}{8}-\frac{4}{12}+\frac{3}{2}\right)-\left(\frac{5}{8}+\frac{9}{13}\right)-\left[\frac{-3}{2}\right]+\frac{7}{-15}\)
\(3.C=\frac{5}{18}+\frac{8}{19}-\frac{7}{21}+\left(\frac{-10}{36}+\frac{11}{19}+\frac{1}{3}\right)-\frac{5}{8}\)
\(4.D=\frac{1}{9}-\left[\frac{-5}{23}\right]-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{14}-\frac{7}{30}\)
\(5.E=\frac{1}{13}+\left(\frac{-5}{18}-\frac{1}{13}+\frac{12}{17}\right)+\left(\frac{12}{17}+\frac{5}{18}+\frac{7}{5}\right)\)
\(6.F=\frac{15}{14}-\left(\frac{17}{23}-\frac{80}{87}+\frac{5}{4}\right)+\left(\frac{12}{17}-\frac{15}{14}+\frac{1}{4}\right)\)
\(7.G=\frac{1}{25}-\frac{4}{27}+\left(\frac{-23}{27}+\frac{-1}{25}-\frac{5}{43}\right)+\frac{5}{43}-\frac{4}{7}\)
\(8.H=\frac{4}{15}-\frac{23}{28}-\left(\frac{-23}{28}+\frac{-11}{15}-\frac{29}{27}\right)-\frac{2}{27}\)
\(9.K=\frac{1}{16}-\frac{5}{21}+\left(\frac{-1}{16}+\frac{-3}{5}-\frac{-5}{21}\right)+\frac{-2}{5}+\frac{3}{4}\)
\(10.L=\frac{7}{12}+\frac{15}{14}-\left(\frac{14}{22}+\frac{-1}{14}+\frac{5}{21}\right)-\frac{-5}{21}+\frac{3}{5}\)
yutyugubhujyikiu
Tìm x
\(\frac{7}{9}:\left(2+\frac{3}{4}X\right)+\frac{5}{9}=\frac{23}{27}\)
MF MAF:
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)=\frac{23}{27}-\frac{5}{9}\)
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)=\frac{23}{27}-\frac{15}{27}\)
\(\left(2+\frac{3}{4}x\right)=\frac{7}{9}:\frac{8}{27}\)
\(\frac{3}{4}x=\frac{21}{8}-\frac{16}{8}\)
\(\frac{3}{4}x=\frac{5}{8}\)
\(x=\frac{5}{8}:\frac{3}{4}\)
\(x=\frac{5}{6}\)
Vậy x = 5/6
Tham khảo nha ~~
tìm số x biết
a) \(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\) b) \(\frac{-2}{3}.x+\frac{1}{5}=\frac{3}{10}\) c) \(\left|x\right|-\frac{3}{4}=\frac{5}{3}\)
a. \(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
\(\Rightarrow\frac{7}{9}:\left(2+\frac{3}{4}x\right)=\frac{23}{27}-\frac{5}{9}\)
\(\Rightarrow\frac{7}{9}:\left(2+\frac{3}{4}x\right)=\frac{8}{27}\)
\(\Rightarrow2+\frac{3}{4}x=\frac{7}{9}:\frac{8}{27}\)
\(\Rightarrow2+\frac{3}{4}x=\frac{21}{8}\)
\(\Rightarrow\frac{3}{4}x=\frac{21}{8}-2\)
\(\Rightarrow\frac{3}{4}x=\frac{5}{8}\)
\(\Rightarrow x=\frac{5}{8}:\frac{3}{4}\)
\(\Rightarrow x=\frac{5}{6}\)
b. \(\frac{-2}{3}x+\frac{1}{5}=\frac{3}{10}\)
\(\Rightarrow\frac{-2}{3}x=\frac{3}{10}-\frac{1}{5}\)
\(\Rightarrow\frac{-2}{3}x=\frac{1}{10}\)
\(\Rightarrow x=\frac{1}{10}:\left(\frac{-2}{3}\right)\)
\(\Rightarrow x=\frac{-3}{20}\)
c. \(\left|x\right|-\frac{3}{4}=\frac{5}{3}\)
\(\Rightarrow\left|x\right|=\frac{5}{3}+\frac{3}{4}\)
\(\Rightarrow\left|x\right|=\frac{29}{12}\)
\(\Rightarrow x=\frac{29}{12}\) hoặc \(x=-\frac{29}{12}\)
\(\frac{7}{9}:\left(2+\frac{3}{4}\right)+\frac{5}{9}=\frac{23}{27}\)
a) \(\frac{2}{3}.x-\frac{3}{2}.x=\frac{5}{12}\)
b) \(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=-\frac{53}{10}\)
c) \(\frac{7}{9}:\left(2+\frac{3}{4}.x\right)+\frac{5}{9}=\frac{23}{27}\)
a) 2/3*x-3/2*x=5/12
x*(2/3-3/2)=5/12
x*(-5/6)=5/12
x=5/12:(-5/6)
x=-1/2
b)2/5+3/5*(3x-3,7)=-53/10
3/5*(3x-3,7)=(-53/10)-2/5=-57/10
(3x-3,7)=(-57/10):3/5=-19/2
3x=(-19/2)+3,7
3x=-29/5
x=(-29/5):3=-29/15
c) 7/9:(2+3/4*x)+5/9=23/27
7/9:(2+3/4*x)=8/27
2+3/4*x=21/8
3/4*x=5/8
x=5/6
k mình nha
a) 2/3.x-3/2.x=5/12
x.(2/3-3/2) =5/12
x.-5/6 =5/12
x =5/12:-5/6
x =1/2
b)2/5+3/5.(3x-3,7)=-53/10
3/5.(3x-3,7)=-53/10-2/5
3/5.(3x-3,7)=-57/10
3x-3,7 =-57/10:3/5
3x-3,7 =-19/2
3x =--19/2+3,7
3x =-29/5
x =-29/5:3
x =29/15
c)7/9:(2+3/4.x)+5/9=23/27
7/9:(2+3/4.x) =23/27-5/9
7/9:(2+3/4.x) =28/27
2+3/4.x =7/9:28/27
2+3/4.x =3/4
3/4.x =3/4-2
3/4.x =-5/4
x =-5/4:3/4
x =-5/3
Tim x biet
c) \(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
d) \(|x-\frac{1}{3}|-\frac{3}{4}=\frac{5}{3}\)
c) \(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)=\frac{23}{27}-\frac{5}{9}\)
\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)=\frac{23}{27}-\frac{15}{27}\)
\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)=\frac{8}{27}\)
\(2+\frac{3}{4}x=\frac{7}{9}\div\frac{8}{27}\)
\(2+\frac{3}{4}x=\frac{7}{9}.\frac{27}{8}\)
\(2+\frac{3}{4}x=\frac{21}{8}\)
\(\frac{3}{4}x=\frac{21}{8}-2\)
\(\frac{3}{4}x=\frac{21}{8}-\frac{16}{8}\)
\(\frac{3}{4}x=\frac{5}{8}\)
\(x=\frac{5}{8}\div\frac{3}{4}\)
\(x=\frac{5}{8}.\frac{4}{3}\)
\(x=\frac{5}{6}\)
Vậy \(x=\frac{5}{6}\).
d) \(\left|x-\frac{1}{3}\right|-\frac{3}{4}=\frac{5}{3}\)
\(\left|x-\frac{1}{3}\right|=\frac{5}{3}+\frac{3}{4}\)
\(\left|x-\frac{1}{3}\right|=\frac{20}{12}+\frac{9}{12}\)
\(\left|x-\frac{1}{3}\right|=\frac{29}{12}\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{1}{3}=\frac{29}{12}\\x-\frac{1}{3}=-\frac{29}{12}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{11}{4}\\x=-\frac{25}{12}\end{cases}}\)
Vậy \(x\in\left\{\frac{11}{4};-\frac{25}{12}\right\}\).
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
giúp mình tìm x với
7/9:(2+3/4x)=23/27-5/9
7/9:(2+3/4x)=23/27-15/27
7/9:(2+3/4x)=8/27
2+3/4x=7/9:8/27
2+3/4x=21/8
3/4x=21/8-2
3/4x=21/8-16/8
3/4x=5/8
x=5/8:3/4
x=5/6
Một đ ú n g nha..............
Bài 4: Tính hợp lý
a) \(A=\left(\left|\frac{-3}{4}\right|+\left|\frac{-2}{5}\right|\right):\frac{3}{7}+\left(\frac{-3}{5}+\left|\frac{-1}{4}\right|\right):\frac{3}{7}\)
b) \(B=2\frac{5}{23}-\left(\frac{-7}{9}\right)-\left|\frac{-5}{23}\right|+\frac{12}{9}+\left|-0,75\right|\)
Bài 5 : Tìm x :
\(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\left|\frac{-2}{3}\right|\)
b) \(\left|x\right|:\left(\frac{1}{9}-\frac{2}{5}\right)=\frac{-1}{2}\)
c) \(\left(x-\frac{1}{5}\right).\left(1\frac{3}{5}+2x\right)=0\)