a) \(9\cdot3^3\cdot\frac{1}{81}\cdot3^2\)

\(=\frac{3^2\cdot3^3\cdot3^2}{3^4}\)

\(=3^3=27\)

b) \(4\cdot2^5:\left(2^3\cdot\frac{1}{16}\right)\)

\(=\frac{2^2\cdot2^2\cdot2^4}{2^3}\)

\(=2^5=32\)

c) \(3^2\cdot2^5\cdot\left(\frac{2}{3}\right)^2\)

\(=\frac{3^2\cdot2^5\cdot2^4}{3^2}\)

\(=2^9=512\)

d) \(\left(\frac{1}{3}\right)^2\cdot\frac{1}{3}\cdot9^2\)

\(=\frac{1^2\cdot1\cdot3^4}{3^2}\)

\(=3^2=9\)

d,\(=\frac{1}{3^2}\cdot\frac{1}{3}\cdot\left(3^2\right)^2=\frac{3^4}{3^3}=3\)

b,\(=2^2\cdot2^5:\left(2^3\cdot\frac{1}{2^4}\right)=2^7:\frac{1}{2}=2^7\cdot2=2^8\)

ủa , còn câu trả lời của e ạ !!! chắc oline math duyệt !!! 

a: \(=3^2\cdot3^3\cdot3^{-4}\cdot3^2=3^{2+3-4+2}=3^3\)

b: \(=2^2\cdot2^5:\left(2^3\cdot\dfrac{1}{2^4}\right)=2^7:\dfrac{1}{2}=2^8\)

c: \(=9\cdot32\cdot\dfrac{4}{9}=128=2^7\)

d: \(=\dfrac{1}{27}\cdot3^4=3^1\)

a) \(3^3\)

b)\(2^8\)

c) \(2^7\)

d) \(3^1\)

a) 9.3³.\(\dfrac{1}{81}\) .3² = 3². 3³.\(\dfrac{1}{3^4}\) . 3² = 3³

b) 4. 2⁵: \(\) (2³.\(\dfrac{1}{16}\))= 2². 2⁵: 2³. \(\dfrac{1}{2^4}\) = 2⁷: \(\dfrac{1}{2}\) = 2⁷. 2= 2⁸

c) 3². 2⁵. \(\left(\dfrac{2}{3}\right)^2\) = 3². 2⁵. \(\dfrac{2^2}{3^2}\) = 2⁵. 2² = 2⁷

d) \(\left(\dfrac{1}{3}\right)^2\) .\(\dfrac{1}{3}\) . 9² = \(\dfrac{1}{9}.\dfrac{1}{3}\). 9² = \(\dfrac{9}{3}\) = 3¹

a không bít !

b chịu

c quên rồi

d . . .

\(a,9.3^3.\frac{1}{81}.3^2=3^2.3^3.3^{\left(-4\right)}.3^2=3^{2+3-4+2}=3^3.\)

\(b,4.2^5:\left(2^3.\frac{1}{16}\right)=2^2.2^5:\left(2^3.2^{-4}\right)=2^{2+5}:2^{3-4}=2^7:2^{-1}=2^{7-\left(-1\right)}=2^8.\)

\(c,3^2.2^5.\left(\frac{2}{3}\right)^2=3^2.2^5.\frac{2^2}{3^2}=\left(\frac{3^2}{3^2}\right).\left(2^5.2^2\right)=1.2^{5+2}=2^7\)

\(d,\left(\frac{1}{3}\right)^2.\frac{1}{3}.9^2=\left(\frac{1}{3}\right)^2.\frac{1}{3}.\left(3^2\right)^2=\left(\frac{1}{3}\right)^{2+1}.3^4=\left(\frac{1}{3}\right)^3.\left(\frac{1}{3}\right)^{-4}=\left(\frac{1}{3}\right)^{3-4}=\left(\frac{1}{3}\right)^{-1}=3^1\)