x/2+99/2=0
(x+20)+(x+21)+(x+22)+...+(x+299)=2100+99
f, \(x^2-x+25\)
\(=x^2-2.\dfrac{1}{2}.x+\left(\dfrac{1}{2}\right)^2-\left(\dfrac{1}{2}\right)^2+25\)
\(=\left(x-\dfrac{1}{2}\right)^2+\dfrac{99}{4}\)
Vì \(\left(x-\dfrac{1}{2}\right)^2\) ≥ 0 nên \(\left(x-\dfrac{1}{2}\right)^2+\dfrac{99}{4}\ge\dfrac{99}{4}\) với mọi x
Dấu "=" xảy ra ⇔ \(x-\dfrac{1}{2}=0\Leftrightarrow x=\dfrac{1}{2}\)
Vậy GTNN của đa thức là \(\dfrac{99}{4}\) tại \(x=\dfrac{1}{2}\)
Tìm x:
( x + 2) + ( x + 4 ) + ( x + 6 ) + ................. + ( x + 100 ) = 2700
Tính tổng
0+1+2+3+.........+99
1+2+3+4+..........+99
1+3+5+7+..........+99
cau 1 :
Tu dau bai ta co:
X x 50 + ( 100 + 2 ) x 50 : 2 = 2700
X x 50 + 2550 = 2700
X x 50 = 2700 - 2550
X x 50 = 150
X = 150 : 50
X = 3
Bai 2
1 ) ( 99 + 0 ) x 100 : 2 = 4950
2 ) ( 99 + 1 ) x 99 : 2 = 4950
3 ) day tren co so cac so hang la :
( 99 - 1 ) : 2 + 1 = 50 ( so )
Vay tong la : ( 99 + 1 ) x 50 : 2 = 2500
lik e cho minh nha moi nguoi
x/2 +99/2=0.Vay x=
\(\frac{x}{2}+\frac{99}{2}=0\)
Mà: \(-\frac{99}{2}+\frac{99}{2}=0\Rightarrow x=-99\)
=> \(\frac{x+99}{2}=0\)
=> x+99=0
=> x=-99
(99+x).(x^2-16)=0
(99+x).(x^2-16)=0
<=> (x-4).(x+4).(99+x)=0
<=> x-4=0 => x=4
x+4=0 => x=(-4)
99+x=0 => x=(-99)
vậy x thuộc (4;-4;-99)
( 99 + x ).( x2 -16) = 0
TH1: 99 + x = 0
x = 0 - 99
x = -99
TH2: x2 - 16 = 0
x2 = 0 + 16
x2 = 16
x2 = 42
=> x = 4
Vậy....
x/2+99/2=0
\(\frac{x}{2}+\frac{99}{2}=0\Rightarrow\frac{x}{2}=0-\frac{99}{2}\Rightarrow\frac{x}{2}=\frac{-99}{2}\Rightarrow x=-99\)
x+(x+1*2)+...+(x+99*100)=0
Tìm x
99 - 2 = x
x - 99 x 3 = 0
x : 21 = 14
cau1: 99-2=97
Cau 2: x=99x3=297 vay x=297
cau 3: x:21=14
x=21x14
x=294
99 - 2 = x
Vậy 99 -2 = 97
Vậy x = 97
x - 99 x 3 = 0
x - 99 =0 bởi vì 0 : 3 = 0
X = 0 + 99 = 99
x = 14 x 21
x = 294
tích mik mik tích lại
Tìm x, biết :
x/2 +99/2 = 0
\(\frac{x}{2}+\frac{99}{2}=0\)
\(x:2=0-\frac{99}{2}\)
\(x:2=-\frac{99}{2}\)
\(x=-\frac{99}{2}.2\)
\(x=-99\)nha Trần Thị Hiền ^_^
\(\frac{x}{2}+\frac{99}{2}=0\)
\(\frac{x}{2}=0-\frac{99}{2}\)
\(\frac{x}{2}=-\frac{99}{2}\)
\(\frac{x}{2}+\frac{99}{2}=0\)
\(\frac{x}{2}=0+\frac{99}{2}\)
\(\frac{x}{2}=\frac{99}{2}\)
\(x=\frac{99}{2}\times2\)
\(x=99\)
nha bạn ^_^
Trần Thị Hiền