mấy bn lm giúp mk nha , mk tk cho 3 tk 

a) \(\frac{6^{10}.27^5}{4^5.81^6}=\frac{\left(2.3\right)^{10}.\left(3^3\right)^5}{\left(2^2\right)^5.\left(3^4\right)^6}=\frac{2^{10}.3^{10}.3^{15}}{2^{10}.3^{24}}=\frac{2^{10}.3^{25}}{2^{10}.3^{24}}=\frac{3^{25}}{3^{24}}=3\)
b) \(\frac{72^3.54^2}{108^4}=\frac{\left(2^3.3^2\right)^3.\left(2.3^3\right)^2}{\left(2^2.3^3\right)^4}=\frac{2^9.3^6.2^2.3^6}{2^8.3^{12}}=\frac{2^{11}.3^{12}}{2^8.3^{12}}=\frac{2^{11}}{2^8}=2^3=8\)
c) \(\frac{27^4.2^3-3^{10}.4^3}{6^4.9^3.4}=\frac{\left(3^3\right)^4.2^3-3^{10}.\left(2^2\right)^3}{\left(2.3\right)^4.\left(3^2\right)^3.2^2}=\frac{3^{12}.2^3-3^{10}.2^6}{2^4.3^4.3^6.2^2}\)
= \(\frac{3^{12}.2^3-3^{10}.2^6}{2^6.3^{10}}=\frac{3^{12}.2^3}{2^6.3^{10}}-\frac{3^{10}.2^6}{2^6.3^{10}}=\frac{3^2}{2^3}-1=\frac{9}{8}-1=\frac{1}{8}\)
 

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                                                            Bài giải

\(d,\text{ }\frac{72^3\cdot54^2}{108^4}=\frac{3^6\cdot2^9\cdot3^6\cdot2^2}{3^{12}\cdot2^8}=2^3=9\)

\(e,\text{ }\frac{3^{10}\cdot11+3^{10}\cdot5}{3^9\cdot2^4}=\frac{3^{10}\left(11+5\right)}{3^9\cdot2^4}=\frac{3\cdot16}{2^4}=\frac{3\cdot2^4}{2^4}=3\)

A= 3^10.( 11+5 ) / 3^9. 2^4 

A= 3^10. 16 /3 ^9 . 16

A= 3^10/3^9= 3

B= 2^10. ( 13 +65) / 2^8.104

B= 2^10. 78/ 2^8.104

B= 2 ^10.2.39/ 2^8 .2.52

B= 2^11.39/ 2^9.52

B= 2 ^ 2. (39/ 52)

B= 4 . 39/52 = 3

C= (2^3.3^2)^3.( 2.3.3^2 )^2 / (2^2.3^3)^4

C= 2^9.3^6/ 2^2.3^2.3^4

C= 2^9.3^6/ 2^2.3^6

C= 2^9/2^2= 2^5=32

D= 11.3^29-3^30/ 2^2.3^28

D= 3^29.(1- 3)/ 2^2.3^28

D= 3^29.(-2)/ 2^2.3^28

D= 3. (-2/2^2)

D = 3. (-1/2)= -3/2

a, \(B=\dfrac{2^{10}.13+2^{10}.65}{2^8.104}\)

\(=\dfrac{2^{10}.\left(13+65\right)}{2^8.2^3.13}\)

\(=\dfrac{2^{10}.78}{2^{11}.13}\)\(=\dfrac{1.6}{2.1}=\dfrac{1.3}{1.1}=3\)

b: \(=\dfrac{2^{20}\cdot3^2+2^{54}}{2^{18}\cdot5^2}=\dfrac{2^{20}\left(3^2+2^{32}\right)}{2^{18}\cdot5^2}=\dfrac{2^2\left(3^2+2^{32}\right)}{25}\)

c: \(=\dfrac{2^9\cdot3^6\cdot3^6\cdot2^2}{2^8\cdot3^{12}}=\dfrac{2^{11}}{2^8}=8\)

d: \(=\dfrac{2^{12}\cdot3^4\cdot3^{10}}{2^{12}\cdot3^{12}}=9\)