Bài 1:

a. A=(-a+b-c)-(-a-b-c)

    A=-a+b+c+a+b+c

    A=(-a+a)+(b+b)-(c-c)

    A=0+2b-0

    A= 2b

b Thay b= -1 vào biểu thức A=2b ta có

A= 2.(-1)=-2

Bài 2: 

a, A = (a + b) - (a - b) + (a - c) - (a + c)

 A = a + b - a + b + a - c - a - c 

A = (a - a + a - a) + (b + b) - (c + c)

A = 0 + 2b - 0

A = 2b 

b, B = (a + b - c) + (a - b + c) - (b + c - a) - (a - b - c)

B = a + b - c + a - b + c - b - c + a - a + b + c

B = (a + a + a - a) + (b - b - b + b) - (c - c + c - c)

B = 2a + 0 - 0

B = 2a 

a)(a+b)-(a-b)+(a-c)-(a+c) 

=a+b-a+b+a-c-a-c

=2b-2c

b)(a+b-c)+(a-b+c)-(b+c-a)-(a-b-c)

=a+b-c+a-b+c-b-c+a-a+b+c

=2a

Giải:

a) A=(a+b)-(a-b)+(a-c)-(a+c)

    A=a+b-a+b+a-c-a-c

    A=0+(a-a)-c-c

    A=0+0-c-c

    A=-c-c

b) B=(a+b-c)+(a-b+c)-(b+c-a)-(a-b-c)

    B=a+b-c+a-b+c-b-c+a-a+b+c

    B=(a+a+a-a)+(b-b-b+b)+(-c+c-c+c)

    B=(a+a)+0+0

    B=a+a

Chúc bạn học tốt!

Làm lại:

a) A=(a+b)-(a-b)+(a-c)-(a+c)

    A=a+b-a+b+a-c-a-c

    A=(a-a+a-a)+(b+b)+(-c-c)

    A=(b+b)+(-c-c)

    A=2b-2c

Chúc bạn học tốt!

a) `A=(a+b)-(a-b)+(a-c)-(a+c)`

`=a+b-a+b+a-c-a-c`

`=2b-2c`

b) `B=(a+b-c)+(a-b+c)-(b+c-a)-(a-b-c)`

`=a+b-c+a-b+c-b-c+a-a+b+c`

`=2a`

\(A=\left(a+b\right)-\left(a-b\right)+\left(a-c\right)-\left(a+c\right)\)

\(A=a+b-a+b+a-c-a-c\)

\(A=2b-2c\)

\(B=\left(a+b-c\right)+\left(a-b+c\right)-\left(b+c-a\right)-\left(a-b-c\right)\)

\(B=a+b-c+a-b+c-b-c+a-a+b+c\)

\(B=2a\)

a) \(A=\left(a+b\right)-\left(a-b\right)+\left(a-c\right)-\left(a+c\right)\) 

\(A=a+b-a+b+a-c-a-c\) 

\(A=\left(a-a+a-a\right)+\left(b+b\right)+\left(-c-c\right)\) 

\(A=0+2b+-2c\) 

\(A=2b-2c\) 

b) \(B=\left(a+b-c\right)+\left(a-b+c\right)-\left(b+c-a\right)-\left(a-b-c\right)\) 

\(B=a+b-c+a-b+c-b-c+a-a+b+c\) 

\(B=\left(a+a+a-a\right)+\left(b-b-b+b\right)+\left(-c+c-c+c\right)\) 

\(B=2a+0+0\) 

\(B=2a\)

a)

A= (-m+n-p)-(-m-n-p)

A= -m+n-p+m+n+p

A= (-m+m) +(n+n) + (-p+p)

A= 0+2n+0

A = 2n

Bài 1: 

A = (-m + n - p) - (-m - n - p)

A = -m + n - p + m + n + p

A = (-m + m) + (n + n) - (p - p)

A = 2n

Với n = -1 => A = 2(-1) = -2

Bài 2: 

A = (-2a + 3b - 4c) - (-2a -3b - 4c)

A = -2a + 3b - 4c + 2a + 3b + 4c

A = (-2a + 2a) + (3b + 3b) - (4c - 4c)

A = 6b

Với b = -1 => A = 6(-1) = -6

Bài 3:

a) A = (a + b) - (a - b) + (a - c) - (a + c)

A= a + b - a + b + a - c - a - c

A = (a - a + a - a) + (b + b) - (c + c)

A = 2(b - c)

b) B = (a + b - c) + (a - b + c) - (b + c - a) - (a - b - c)

B = a + b - c + a - b + c - b - c + a - a + b + c

B = (a + a + a - a) + (b - b - b + b) - (c - c + c - c)

B = 2a

1. A = ( -2a + 3b - 4c ) - ( -2a - 3b - 4c )

a) Rút gọn

A = ( -2a + 3b - 4c ) - ( -2a - 3b - 4c )

   = -2a + 3b - 4c + 2a + 3b + 4c

   = ( -2a + 2a ) + ( 3b + 3b ) + ( -4c + 4c )

   = 0 + 6b + 0

   = 6b

B1.a, A=6b

      b,A=-10851

B2.a,A=2b-2c

     b,B=2a

Bài 1:b)Tính giá trị :  A = (–2a + 3b – 4c) – (–2a – 3b – 4c)

Ta thay a = 2012 ; b = -1 ; c = -2013 vào A ,Ta được:

 A = [-2 . 2012 + 3 . (-1) - 4 . (-2013)]

\(\Rightarrow\)A = [ -4024 + (-3) - (-8052)]

\(\Rightarrow\)A = [ -4027 + 8052]

\(\Rightarrow\)A = 4025

Vậy A = 4025

Bài 1:

   A= (-1+b-c)-(-a-b-c)=-a+b-c+a+b+c=2b.

Bài 2:

   A= (a+b)-(a-b)+(a-c)-(a+c) = a+b-a+b+a-c-a-c = 2b-2c = 2(b-c)

   B= (a+b-c)+(a-b+c)-(b+c-a)-(a-b-c) = a+b-c+a-b+c-b-c+a-a+b+c = 2a

a, -( -a + c - d) - ( c - d + d) =  a - c + d - c + d - d =  a + d

b, - ( a+b-c+d) + (a-b-c-d) = -a -b+c-d + a-b-c-d = -2b + (-2c)= -2(b+c)

A=a+b-a+b+a-c-a-c=a+2b-2c

B=a+b-c+a-b+c-b-c+a-a+b+c=2a