a) \(S_1=1+2+3+4+......+999\)

\(\Rightarrow S_1=\dfrac{\left(999+1\right).\left[\left(999-1\right):1+1\right]}{2}\)

\(\Rightarrow S_1=\dfrac{1000.\left(998+1\right)}{2}\)

\(\Rightarrow S_1=\dfrac{1000.999}{2}\)

\(\Rightarrow S_1=\dfrac{999000}{2}\)

\(\Rightarrow S_1=499500\)

b) \(S_2=10+12+14+......+2010\)

\(\Rightarrow S_2=\dfrac{\left(2010+10\right).\left[\left(2010-10\right):2+1\right]}{2}\)

\(\Rightarrow S_2=\dfrac{2020.\left(2000:2+1\right)}{2}\)

\(\Rightarrow S_2=\dfrac{2020.\left(1000+1\right)}{2}\)

\(\Rightarrow S_2=\dfrac{2020.1001}{2}\)

\(\Rightarrow S_2=\dfrac{2022020}{2}\)

\(\Rightarrow S_2=1011010\)

c) \(S_3=21+23+25+.......1001\)

\(\Rightarrow S_3=\dfrac{\left(1001+21\right).\left[\left(1001-21\right):2+1\right]}{2}\)

\(\Rightarrow S_3=\dfrac{1022.\left(980:2+1\right)}{2}\)

\(\Rightarrow S_3=\dfrac{1022.\left(490+1\right)}{2}\)

\(\Rightarrow S_3=\dfrac{1022.491}{2}\)

\(\Rightarrow S_3=\dfrac{501802}{2}\)

\(\Rightarrow S_3=250901\)

d) \(S_5=1+4+7+......+79\)

\(\Rightarrow S_5=\dfrac{\left(79+1\right).\left[\left(79-1\right):3+1\right]}{2}\)

\(\Rightarrow S_5=\dfrac{80.\left(78:3+1\right)}{2}\)

\(\Rightarrow S_5=\dfrac{80.\left(26+1\right)}{2}\)

\(\Rightarrow S_5=\dfrac{80.27}{2}\)

\(\Rightarrow S_5=\dfrac{2160}{2}\)

\(\Rightarrow S_5=1080\)

e) \(S_7=15+25+35+45+......+115\)

\(\Rightarrow S_7=\dfrac{\left(115+15\right).\left[\left(115-15\right):10+1\right]}{2}\)

\(\Rightarrow S_7=\dfrac{130.\left(100:10+1\right)}{2}\)

\(\Rightarrow S_7=\dfrac{130.\left(10+1\right)}{2}\)

\(\Rightarrow S_7=\dfrac{130.11}{2}\)

\(\Rightarrow S_7=\dfrac{1430}{2}\)

\(\Rightarrow S_7=715\)

S1= 1+2+3...+999

S1= (999-1) :1 +1= 999

S1= (999+1) x999 :2=499500 

S1= 499500

S2= ( 1010 -10) : 2 +1= 501

S2= (1010+ 10) x 501:2= 255510

255510 đó

2 . tìm x :

a ) 5^2x = 625

 5^2x = 5⁴

=> 2 . x = 4

x = 4 : 2

x = 2

b ) 9^x-1 = 9

9^x-1 = 9¹

=> x - 1 = 1

x = 1 + 1

x = 2

c ) 2^x : 2⁵ = 1

2^x-5 = 1

=> x = 5 , vì 2^5-5 = 2⁰ = 1

a) Tổng S1 là: (999+1)x999:2=499500

b) Tổng S2 là: (2010+10)x1001:2=1011010

b) Tổng S3 là: (1001+21)x491250901

sai roi. ngu lam con cho oi

chuan lm sai bet

Công thức tính SSH nè : (số đầu + số cuối) : khoảng cách +1

Công thức tinh tổng : (số đầu + số cuối) nhân SSH chia 2

a, S1= (1+999) . 999 : 2

        = 1000 . 999 :2

         =4500

b, S2 = (10 + 2010) . 1001 :2

         = 2020 .1001 :2

         = 1011010

c, S3 = (21 + 1001) . 491 :2

         = 1002 . 491 :2

tui làm theo cách đó,sai be bét

sai be bét