A=\(2.\left(\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+......+\frac{1}{240}\right)\)

A=\(2.\left(\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+....+\frac{1}{15.16}\right)\)

A=\(2.\left(\frac{1}{4.}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+.......+\frac{1}{15}-\frac{1}{16}\right)\)

A=\(2.\left(\frac{1}{4}-\frac{1}{16}\right)\)

A=\(2.\left(\frac{4}{16}-\frac{1}{16}\right)\)

\(A=2.\frac{3}{16}\)

\(A=\frac{3}{8}\)

\(Vay\) \(A=\frac{3}{8}\)

=2

Ta co: A = 1/10+ 1/15+1/21+...+1/120 

              = 2/20+2/30+2/42+...+2/240=2/(4*5)+2/(5*6)+.....+2/(15*16)

              = 2*[1/(4*5)+1/(5*6)+...........+ 1/(15*16)]

              = 2* [ 1/4-1/5+1/5-1/6+.........+1/15-1/16]

              = 2*[1/4-1/16]

             = 2*3/16

              = 3/8

Vay A=3/8

\(C=\frac{2}{20}+\frac{2}{30}+\frac{2}{42}+...+\frac{2}{240}=2\times\left(\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+...+\frac{1}{240}\right)\)

\(C=2\times\left(\frac{1}{4\times5}+\frac{1}{5\times6}+\frac{1}{6\times7}+...+\frac{1}{15\times16}\right)\)

\(C=2\times\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{15}-\frac{1}{16}\right)=2\times\left(\frac{1}{4}-\frac{1}{16}\right)=\frac{3}{8}\)

c = 2/20 + 2/30 +2/42 + ... 2 /240

=2/4.5 +2/5.6 + 2/6.7 + ... +1/15.16

=2. (1/4.5 + 1/5.6 + 1/6.7 +...+1/15.16)

= 2.(1/4-1/5+1/5-...-1/16)

=2.(1/4-1/6)=2.3/16=3/8.

ghi nho dau cham la dau nhan

\(S=\frac{2}{20}+\frac{2}{30}+...+\frac{2}{240}\)

\(=2\left(\frac{1}{4.5}+\frac{1}{5.6}+...+\frac{1}{15.16}\right)\)

\(=2\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{15}-\frac{1}{16}\right)\)

\(=2\left(\frac{1}{4}-\frac{1}{16}\right)\)

\(=2\times\frac{3}{16}\)

\(=\frac{3}{8}\)

=(-1+4)+(-7+10)+...+(-97+100)

=3+3+...+3

=3*17=51

1/1.4+1/4.7+1/7.10+...+1/16.19

=[1/1.4+1/4.7+1/7.10+...+1/16.19] x 3

= 3/1.4+3/4.7+3/7.10+...+3/16.19

= 1-1/4+1/4-1/7+1/7-1/10+....+1/16-1/19

=1-1/19

=18/19 :3

=6/19

ĐÂY BẠN NHÉ CHÚC BẠN HỌC TỐT NHỚ K CHO MÌNH

A = \(\dfrac{1}{10}+\dfrac{1}{15}+...+\dfrac{1}{120}\)

A= \(\dfrac{2}{2}.\left(\dfrac{1}{10}+\dfrac{1}{15}+...+\dfrac{1}{120}\right)\) 

A= \(2.\left(\dfrac{1}{20}+\dfrac{1}{30}+...+\dfrac{1}{240}\right)\)

A= \(2.\left(\dfrac{1}{4.5}+\dfrac{1}{5.6}+...+\dfrac{1}{15.16}\right)\) 

A=\(2.\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{15}-\dfrac{1}{16}\right)\)

A=\(2.\left(\dfrac{1}{4}-\dfrac{1}{16}\right)\) 

A=\(\dfrac{2.3}{16}\) 

A= \(\dfrac{3}{8}\)