(x+1)+(x+2)+........+(x+100)=5750
(x+1)+(x+2)+(x+3)+...+(x+100)=5750
Ta có: \(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5750\)
\(\Leftrightarrow100x+5050=5750\)
\(\Leftrightarrow100x=700\)
hay x=7
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(x+1)+(x+2)+...+(x+100)=5750
(x+x+...+x)+(1+2+3+...+100)=5750
100x+5050=5750
100x=5750-5050
100x=700
x=700/100
x=7
(x+1) + (x+2) + (x+3) +....+ (x+100) = 5750
\(\Leftrightarrow100x+5050=5750\)
hay x=7
(x+1) + (x+2) + (x+3) +....+ (x+100) = 5750
x + 1 + x + 2 + x + 3 +...+ x + 100 = 5750
(x + x + x +...+ x) + (1 + 2 + 3 +...+ 100) = 5750
100x + 5050 = 5750
100x = 5750 - 5050
100x = 700
x = 700 : 100
x = 7
x+1+x+2+x+3+.......x+100=5750
=>100x+5050=5750
=>100x=700
=>x=7
(x+1) + (x+2)+........+(x+100) = 5750
Ta có : (x+1) +(x+2) +......+(x+100)=5750
\(\Leftrightarrow\) 100.x +(1+2+...+100) =5750
\(\Leftrightarrow\) 100.x +5050 =5750
\(\Leftrightarrow\) 100x =5750-5050
\(\Leftrightarrow\) 100.x =700
\(\Leftrightarrow\)x=700: 100
\(\Leftrightarrow\) x =7
Vậy x=7
Có 100 nhóm nên có 100 số x
(x+x+...+x)+(1+2+3+4+...+100)=5750
x.100 + 5050=5750
x.100=5750-5050
x.100=700
x=700:100
x=7
( x + 1 ) + ( x + 2 ) + ... + ( x + 100 ) = 5750
( x x + x + x + ... + x ) + ( 1 + 2 + 3 + 4 + ... + 100 ) = 5750
100x + ( 100 + 1 ) x 100 : 2 = 5750
100x + 101 x 50 = 5750
100x + 5050 = 5750
100x = 5750 - 5050
100x = 700
x = 700 : 100
x = 7
(x+1)+(x+2)+..............+(x+100)=5750
( x +1 )+ ( x + 2 ) + ... + ( x + 100 ) = 5750
( x + x + x + ...+ x ) + ( 1 + 2 + ... + 100 ) = 5750
x * 100 + 5050 = 5750
x * 100 = 700
x = 7
(x+1)+(x+2)+...+(x+100)=5750
(x+1)+(x+2)+...+(x+100)=5750
=> (x+x+.....+x)+(1+2+3+......+100)=5750
=> 100x+(100+1).100:2=5750
=> 100x+10100:2=5750
=> 100x+5050=5750
=> 100x=5750-5050
=> 100x=700
=> x=7
(x+1)+(x+2)+...+(x+100)=5750
( x + 1 ) + ( x + 2 ) + .... + ( x + 100 ) = 5750
( x + x + .... + x ) + ( 1 + 2 + ..... + 100 ) = 5750
( x . 100 ) + ( 1 + 100 ) . 100 : 2 = 5750
( x . 100 ) + 5050 = 5750
x . 100 = 5750 - 5050
x . 100 = 700
x = 700 : 100
x = 7
Vậy x = 7
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Vậy ta tách dãy trên thành 2 phần
(x+1)+(x+2)+...+(x+100)=5750
= ( x + x + x ... + x [ tổng cộng có 100 x ] ) + ( 1 + 2 + 3 + ... + 99 + 100 ) = 5750
= x . 100 + ( 1 + 2 + 3 + ... + 99 + 100 ) = 5750
Ta tính tổng các số từ 1 - 100
( 1 + 100 ) . 100 : 2 = 5050
x . 100 + 5050 = 5750
x . 100 = 5750 - 5050
x . 100 = 700
x = 700 : 100
x = 7
(x+1)+(x+2)+...+(x+100)=5750
(x+1)+(x+2)+.............+(x+100)=5750
<=>x+1+x+2+............+x+100=5750
=>(x+x+...........+x)+(1+2+...........+100)=5750
=>100x+5050=5750
=>100x=700
=?x=700:7
=>x=7
(2x+1)+(2x+2)+...+(2x+2015)=0
Vì cứ 1 số hạng lại có 2x
Số số hạng từ 1 đến 2015 là:
(2015-1):1+1=2015(số)
Tổng dãy số là:
(2015+1)x2015:2=2031120
Do đó có 2015 2x
Ta có:
(2x+1)+(2x+2)+...+(2x+2015)=0
2015.2x+(1+2+...+2015)=0
4030x+2031120=0
4030x=-2031120
x=-2031120:4030
x=-504
Vậy x=-504
(x+1)+(x+2)+...+(x+100)=5750
x+1+x+2+...+x+100= 5750
100.x+ 5050= 5750
100.x= 5750-5050
100.x= 700
x= 700:100
x=7.
Vậy x=7