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a) 1221 : ( x - 16 ) = 21

                ( x - 16 ) = 1221 : 21

                  x - 16   = 58,142..

                  x           = 58,142 + 16

                  x           = 74,142...

b) 435 + ( 6x - 8 ) = 457

              ( 6x - 8 ) = 457 - 435

                6x - 8   = 22

                6x        = 22 + 8

                6x        = 30

                  x        = 30 : 6

                  x        = 5

[(2+y)x81-3530]=714:21

[(2+y)x81-3530]=34

(2+y)x81=34+3530

(2+y)x81=3564

2+y=3564:81

2+y=44

y=44-2

y=42

[ y*81 +2*81-3530 ] *21 =714

y*81 +2*81-3530=714:21

81*(y+2)-3530=34

81*(y+2)=34+3530

81*(y+2)=3564

y+2=3564:81

y+2=44

y=44-2

y=42

[ y x 81 + 2 x 81 -3530 ] =714 :21

[ y x 81 + 2 x 81 -3530]= 34

y x 81 + 2 x 81 = 34 + 3530

y x 81 + 2 x 81 = 3564

y x 81 + 2 = 3564 : 81

y x 81 + 2 = 44

y x 81 = 44 -2

y x 81 = 42

y = 81 : 42

y = 2

Có: \(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}...\frac{30}{62}.\frac{31}{64}=\frac{1}{2.2}.\frac{2}{2.3}.\frac{3}{2.4}...\frac{30}{2.31}.\frac{31}{2.32}=\frac{1}{2}.\frac{1}{2}.\frac{1}{2}...\frac{1}{2}.\frac{1}{2}.\frac{1}{32}\)

\(=\frac{1}{2^{31}.2^5}=\frac{1}{2^{36}}=2^x\)\(\Rightarrow1=2^x.2^{36}=2^{36+x}\)\(\Rightarrow2^{36+x}=2^0\Rightarrow36+x=0\Rightarrow x=-36\)

=>\(1\cdot\dfrac{2}{4}\cdot\dfrac{3}{6}\cdot...\cdot\dfrac{31}{62}\cdot\dfrac{1}{64}=2^x\)

=>\(2^x=\dfrac{1}{2}\cdot\dfrac{1}{2}\cdot...\cdot\dfrac{1}{2}\cdot\dfrac{1}{64}=\left(\dfrac{1}{2}\right)^{30}\cdot\left(\dfrac{1}{2}\right)^6=\dfrac{1}{2^{36}}\)

=>x=-36

 ( x -4 ) x3 + 7 = 240

(x-4) x 3= 240 -7

(x-4) x 3 = 233

x-4= 233/3

x= 233/3 +4

x= 245/3

3 x ( X - 5 ) + 8 x X = 62

3 x X + 8 x X - 15 = 62

11 x X = 62 + 15

11 x X = 77

X=77:11

X=7

\(\left(x-4\right)\times3+7=240\)

\(\left(x-4\right)\times3=233\)

\(x-4=\dfrac{233}{3}\)

\(x=\dfrac{233}{3}+4\)

\(x=\dfrac{245}{3}\)

\(3\times\left(x-5\right)+8\times x=62\)

\(3\times x-15+8\times x=62\)

\(3\times x+8\times x=77\)

\(11\times x=77\)

\(x=\dfrac{77}{11}=7\)

<=> \(\frac{1.2.3....31}{4.6.8....64}=2^n\Rightarrow\frac{1.2.3....30.31}{2\left(2.3.4.5...31\right).32}=2^n\Leftrightarrow\frac{1}{2.32}=2^n\Leftrightarrow\frac{1}{2^6}=2^n\)

=> 2^6.2^n = 1 

=> 2^ (n + 6 ) = 2^0

=> n+ 6  = 0 

=> n = - 6 

\(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}....\frac{31}{64}=\frac{1.2.3....31}{4.6.8....64}=\frac{1.2.3....31}{2.3.2.4....2.32}=\frac{1.2.3....31}{2^{30}.\left(3.4....32\right)}=\frac{2}{2^{30}.32}=\frac{1}{2^{34}}=2^{-34}=2^n=>n=-34\)

2^n × 2³¹ = \(\dfrac{ }{ }\)2/4×4/6×6/8×...×62/64

2^n×2³¹=1/32=2^-5

2^n=2^-5 ÷ 2³¹=2^-36

=>n=-36

a) x × 5 = 50 – 15

x × 5 = 35

x = 35 : 5

x = 7

b) x : 4 = 38 – 33

x : 4 = 5

x = 5 × 4

x = 20

c) x + 356 = 414 + 62

x + 356 = 476

x = 476 – 356

x = 120

d) x : 4 = 2 × 3

x : 4 = 6

x = 6 × 4

x = 24

\(\frac{1}{4}.\frac{2}{6}............\frac{31}{64}=2^x\)

\(\Rightarrow\frac{1.2........31}{2.2.2.3...........2.31.64}=2^x\)

\(\Rightarrow\frac{1}{2^{30}.2^4}=2^x\)

\(\Rightarrow\frac{1}{2^{34}}=2^x\)

\(\Rightarrow x=-34\)

Ta có: \(2^x=\dfrac{1}{4}\cdot\dfrac{2}{6}\cdot\dfrac{3}{8}\cdot\dfrac{4}{10}\cdot\dfrac{5}{12}\cdot...\cdot\dfrac{30}{62}\cdot\dfrac{31}{64}\)

\(\Leftrightarrow2^x=\dfrac{1\cdot2\cdot3\cdot4\cdot...\cdot31}{2\cdot\left(2\cdot3\cdot4\cdot...\cdot31\right)\cdot64}\)

\(\Leftrightarrow2^x=\dfrac{1}{2}\cdot\dfrac{1}{64}=\dfrac{1}{128}\)
\(\Leftrightarrow2^x=\dfrac{1}{2^6}\)

\(\Leftrightarrow2^{x+6}=1\)

\(\Leftrightarrow x+6=0\)

hay x=-6

Vậy: x=-6

`1/4 . 2/6 . 3/8 ... . 30/62 .31/64 =2^x`

`-> (1.2.3....30.31)/(4.6.8....62.64)=2^x`

`-> (1.(2.3...31))/(2.(2.3.4...31).32)=2^x`

`-> 1/(2.32)=2^x`

`-> 1/64=2^x`

`-> 1/(2^6)=2^x`

`-> x=-6`.