(Dấu . là dấu nhân)
a/\(\dfrac{2}{5}\cdot\dfrac{4}{3}-\dfrac{2}{5}:3\)
\(=\dfrac{2}{5}\cdot\dfrac{4}{3}-\dfrac{2}{5}\cdot\dfrac{1}{3}\)
\(=\dfrac{2}{5}\cdot\left(\dfrac{4}{3}-\dfrac{1}{3}\right)\)
\(=\dfrac{2}{5}\cdot1\)
\(=\dfrac{2}{5}\)
b/\(\dfrac{2010}{2018}:\dfrac{1}{2}+\dfrac{7}{2018}:\dfrac{1}{2}\)
\(=\left(\dfrac{2010}{2018}+\dfrac{7}{2018}\right):\dfrac{1}{2}\)
\(=\dfrac{2017}{2018}:\dfrac{1}{2}\)
\(=\dfrac{2017}{2018}\cdot2\)
\(=\dfrac{2017}{1009}\)

a, \(\dfrac{2}{5}\) \(\times\) \(\dfrac{4}{3}\) - \(\dfrac{2}{5}\) : 3

=  \(\dfrac{2}{5}\) \(\times\) \(\dfrac{4}{3}\) - \(\dfrac{2}{5}\) \(\times\) \(\dfrac{1}{3}\)

= \(\dfrac{2}{5}\) \(\times\) ( \(\dfrac{4}{3}\) - \(\dfrac{1}{3}\))

= \(\dfrac{2}{5}\)  \(\times\) 1

= \(\dfrac{2}{5}\) 

b, \(\dfrac{2010}{2018}\) : \(\dfrac{1}{2}\) + \(\dfrac{7}{2018}\) : \(\dfrac{1}{2}\) + \(\dfrac{1}{2018}\) : \(\dfrac{1}{2}\)

= \(\dfrac{2010}{2018}\) \(\times\) \(\dfrac{2}{1}\) + \(\dfrac{7}{2018}\) \(\times\) \(\dfrac{2}{1}\) + \(\dfrac{1}{2018}\) \(\times\) \(\dfrac{2}{1}\)

= \(\dfrac{2}{1}\) \(\times\) ( \(\dfrac{2010}{2018}\) + \(\dfrac{7}{2018}\) + \(\dfrac{1}{2018}\))

= 2 \(\times\) \(\dfrac{2018}{2018}\)

= 2 \(\times\) 1

= 2

Tính bằng cách thuận tiện nhất:

2018 : 1/2 + 2018 :1/3 + 2018 : 1/4 +2018

= 2018 : 1/2 + 2018 :1/3 + 2018 : 1/4 +2018 : 1

= 2018 : (1/2 + 1/3 + 1/4 + 1 )

= 2018 : 25/12

= 968,64.

Mk ko bít đúng không nhưng mình cứ đăng lên, nếu sai thì thông cảm nhé.

thank bạn nha

\(2018\times\frac{3}{4}+2018\times\frac{1}{4}-2018\)

\(=2018\times\left(\frac{3}{4}+\frac{1}{4}-1\right)\)

\(=2018\times0=0\)

B-a:tương tự bài A

b,\(\frac{14}{18}\times\frac{8}{5}-\frac{7}{9}\times\frac{3}{5}\)

\(=\frac{7}{9}\times\frac{8}{5}-\frac{7}{9}\times\frac{3}{5}\)

\(=\frac{7}{9}\times\left(\frac{8}{5}-\frac{3}{5}\right)\)

\(=\frac{7}{9}\times1=\frac{7}{9}\)\

thanks

B-a,\(\frac{3\times125+3\times125}{6\times43+6\times57}=\frac{2\times3\times125}{6\times\left(43+57\right)}\)

\(=\frac{3\times250}{6\times100}=\frac{5}{2\times2}=\frac{5}{4}\)

thanks

A) 2018*3/4+2018*1/4-2018

=2018*(3/4+1/4)-2018

=2018*4/4-2018

=2018*1-2018

=2018-2018

=0

bn thông cảm mình có việc bận,chút nữa mình trả lời câu B

CHO MÌNH HỎI CÁI DẤU KIA LÀ GÌ VẬY BẠN

a, \(13\) \(\times\) 15 - 150 + 97 \(\times\) 15

= 15 \(\times\) ( 13 - 10 + 97)

= 15 \(\times\) ( 3 + 97)

= 15 \(\times\) 100

= 1500  

b, \(\dfrac{2016}{2015}\) \(\times\) \(\dfrac{4}{7}\) - \(\dfrac{4}{7}\) \(\times\) \(\dfrac{1}{2015}\) + \(\dfrac{3}{7}\)

= \(\dfrac{4}{7}\) \(\times\) ( \(\dfrac{2016}{2015}\) - \(\dfrac{1}{2015}\)) + \(\dfrac{3}{7}\)

= \(\dfrac{4}{7}\) \(\times\) \(\dfrac{2015}{2015}\) + \(\dfrac{3}{7}\)

= \(\dfrac{4}{7}\) + \(\dfrac{3}{7}\)

= \(\dfrac{7}{7}\)

= 1

a, 13 \(\times\) 15 - 150 + 97 \(\times\)15

13 \(\times\) 15 - 15 \(\times\) 10 + 97 \(\times\) 15

= 15 \(\times\) ( 13 - 10 + 97)

= 15 \(\times\) ( 3 + 97)

= 15 \(\times\) 100

=1500   

b, \(\dfrac{2016}{2015}\) \(\times\) \(\dfrac{4}{7}\) - \(\dfrac{4}{7}\) \(\times\) \(\dfrac{1}{2015}\) + \(\dfrac{3}{7}\)

= \(\dfrac{4}{7}\) \(\times\) ( \(\dfrac{2016}{2015}\) - \(\dfrac{1}{2015}\)) + \(\dfrac{3}{7}\) 

= \(\dfrac{4}{7}\) \(\times\) \(\dfrac{2015}{2015}\) + \(\dfrac{3}{7}\)

= \(\dfrac{4}{7}\) + \(\dfrac{3}{7}\)

= \(\dfrac{7}{7}\)

= 1

a)  4/15   x  2016/2018+  4/15  x  3/2018-  4/15  x  1/2018             

= 4/15   x  (2016/2018 +  3/2018 - 1/2018)

= 4/15 x (\(1\frac{1}{2018}\)-1/2018)

=4/15 x 1

= 4/15

   b) 8/15   x  8 -  2 x  8/15+3 x  8/15+   8/15

= 8/15 x ( 8 - 2 + 3 + 1)

= 8/15 x 10

= 80/15 => \(5\frac{1}{3}\)

Mấy cái kia mình lười làm phân số nên mình chỉ viết rõ hỗn số thôi, bạn thông cảm nha. Chúc bạn học giỏi <3

giúp mình nốt câu này nhaa :(

( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x ( 1 + 1/3 - 4/3)

=( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x ( 4/3 - 4/3)

=( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x 0

=0

Ta có: \(\left(2013\cdot2014+2014\cdot2015+2015\cdot2016\right)\left(1+\dfrac{1}{3}-\dfrac{4}{3}\right)\)

\(=\left(2013\cdot2014+2014\cdot2015+2015\cdot2016\right)\left(\dfrac{3}{3}+\dfrac{1}{3}-\dfrac{4}{3}\right)\)

=0

0,6 

3/5x6/7+3/5x16/14-3/5x1

=3/5x(6/7+16/14-1)

=3/5x1

=3/5