Giúp mình đang cần gấp Cảm ơn
Giúp mình , mình đang cần gấp Cảm ơn!
Giúp mình với , mình đang cần gấp , mình cảm ơn
\(A=\left(\frac{x}{x+2}+\frac{x^3}{\left(x+2\right)\left(x^2-2x+4\right)}.\frac{x^2-2x+4}{4-x^2}\right):\frac{4}{x+2}\)
\(A=\left(\frac{x}{x+2}+\frac{x^3}{x+2\left(4-x^2\right)}\right):\frac{4}{x+2}\)
\(A=\left(\frac{4x-x^3+x^3}{x+2\left(4-x\right)}\right):\frac{4}{x+2}\)
\(A=\frac{4x}{x+2\left(4-x\right)}.\frac{x+2}{4}\)
\(A=\frac{x}{4-x}\)
\(b,\frac{x}{4-x}>0\)
xét 2 trường hợp x>0 đồng thời 4-x>0 (điều kiện x\(\ne\)4) và x<0 ,4-x<0
\(TH1:0< x< \text{4}\)
\(TH2:\)ko có giá trị x
\(c,Ax=\frac{x}{4-x}x\)=\(\frac{x^2}{4-x}\)
\(\frac{x^2-16+16}{4-x}\)
\(\frac{\left(x-4\right)\left(x+4\right)+16}{4-x}\)
\(-\left(x+4\right)+\frac{16}{4-x}\)
để AX nguyên thì \(16⋮4-x\)
lập bảng ra tìm đc x = 0,2,-4,-12,5,6,8,12,20
GIÚP MÌNH VỚI, MÌNH ĐANG CẦN GẤP, MÌNH CẢM ƠN
GIÚP MÌNH VỚI MÌNH ĐANG CẦN GẤP, MÌNH CẢM ƠN
Giúp mình nha mình đang cần gấp Cảm ơn
1. I was given a notebook as a reward by my teacher.
2. Grapes are picked and then turned into wine.
3. I wasn't allowed to stay up late by my father.
4. Pencils aren't used in your Maths exam.
5. I was allowed to go picnic with my friends by my parents yesterday.
6. I wasn't told about his story.
7. This cake is made by me.
8. When I was a child, my leg was bitten by a dog.
9. Many social skills are needed when you enter the workplace.
1, I was given a notebook by my teacher as a reward
or A notebook was given to me by my teacher as a reward
2, Grapes are picked and wine is turned into
3, I am not allowed to stay up late by my father
4, pencils are not used in your maths
5, i was not allowed to go picnic with my friends by my parents yesterday
6, i was not told about his story
7, this cake was made by me
8, When I was a kid, my leg was bitten by a dog
9, many social kills are needed when the workplace is entered
Giúp mình với mình đang cần gấp cảm ơn.
Giúp mình vs mình đang cần gấp cảm ơn
mình đang cần rất gấp,giúp mình vs Mình cảm ơn
a: Xét (O) có
CM là tiếp tuyến có M là tiếp điểm
CN là tiếp tuyến có N là tiếp điểm
Do đó: CM=CN
hay C nằm trên đường trung trực của MN(1)
Ta có: OM=ON
nên O nằm trên đường trung trực của MN(2)
Từ (1) và (2) suy ra OC là đường trung trực của MN
Giúp mình với mình cảm ơn bạn mình đang cần gấp