a) 126+(−20)+2004+(−106)126+(−20)+2004+(−106)

=2004+126+[(−20)+(−106)]=2004+126+[(−20)+(−106)]

=2004+126+[−(20+106)]=2004+126+[−(20+106)]

=2004+126+(−126)=2004+126+(−126)

=2004+[126+(−126)]=2004+0=2004=2004+[126+(−126)]=2004+0=2004.

b) (−199)+(−200)+(−201)=−(199+200+201)(−199)+(−200)+(−201)=−(199+200+201)

=−(199+201+200)=−[(199+201)+200]=−(199+201+200)=−[(199+201)+200]

=−(400+200)=−600=−(400+200)=−600.

a) 126 + (-20) + 2004 + (-106)

 = 106 + 1898

 =   2004

b) (-199) + (-200) + (-201)

 =  (-399) + (-201)

=  -600

a) 126 + (-20) + 2004 + (-106) = 126 + 2004 + (-20) + (-106)

= 2130 + [- (20 + 106)] = 2130 + (-126) = 2130 – 126 = 2004.

b) (-199) + (-200) + (-201) = – (199 + 200 + 201)

= – (199 + 201 + 200) = – [(199 + 201) + 200] = – (400 + 200) = -600.

a) 126 + (-20) + 2004 + (-106) = 126 + 2004 + (-20) + (-106)

= 2130 + [- (20 + 106)] = 2130 + (-126) = 2130 – 126 = 2004.

b) (-199) + (-200) + (-201) = – (199 + 200 + 201)

= – (199 + 201 + 200) = – [(199 + 201) + 200] = – (400 + 200) = -600.

a) 126 + (-20) + 2004 + (-106) = 126 + 2004 + (-20) + (-106)

= 2130 + [- (20 + 106)] = 2130 + (-126) = 2130 – 126 = 2004.

b) (-199) + (-200) + (-201) = – (199 + 200 + 201)

= – (199 + 201 + 200) = – [(199 + 201) + 200] = – (400 + 200) = -600.

a: \(\left(2345+45\right)-2345\)

\(=2345+45-2345\)

\(=45+\left(2345-2345\right)\)

=45+0

=45

b: \(\left(-2010\right)-\left(119-2010\right)\)

\(=-2010-119+2010\)

\(=\left(-2010+2010\right)-119\)

=0-119

=-119

c: \(\left(18+29\right)+\left(158-18-29\right)\)

\(=18+29+158-18-29\)

\(=158+\left(18-18\right)+\left(29-29\right)\)

=158+0+0

=158

d: \(126+\left(-20\right)+2004+\left(-106\right)\)

\(=126-20+2004-106\)

\(=\left(126-20-106\right)+2004\)

=0+2004

=2004

e: \(\left(-199\right)+\left(-200\right)+\left(201\right)\)

\(=-199-200+201\)

\(=-199+\left(201-200\right)\)

=-199+1

=-198

f: \(99+\left(-100\right)+101\)

\(=\left(99+101\right)-100\)

=200-100

=100

g: \(217+\left[43+\left(-217\right)+\left(-23\right)\right]\)

\(=217+43-217-23\)

\(=\left(217-217\right)+\left(43-23\right)\)

=0+20

=20

a) 126 + ( -20) + 2004 +( -106 )

B1 : Bỏ các dấu ngoặc :

=126  - 20 + 2004  -106

B2 : Tính :

= 2004

b) ( -199 ) + ( -200 ) + ( -201 )

B1 : Bỏ ngoặc

= ( -199 )  -200 -201 

B2 : Tính :

= -600

a=106+1898

  =2004

b=[(-119)+(-201)]+(-200)

  =-320+(-200)

  =120

Bạn Ngân ơi 2 cách phải có kết quả giống nhau chứ

a )2004

b )1404

a) 26+(-20+20040+(-106)

=126+(2004-20)+(-106)

=126+1804+(-106)

=1930+(-106)

=1930-106

=1824

Chỉ help thế thui nha

a 2002

b1404

a) 126+ (-29)+ 2004+ (-106)

= [126+ (-106)] +2004+ (-29)

= 20+ 2004- 29

= 2024-29

= 1995

b) (-199)+ (-200)+ (-201)

= -(199+200+201)

= -600

a) 126 + (-20) + 2004 + (-106)

= [126 + (-20) + (-106)] + 2004

= 0 + 2004

= 2004

b) (-199) + (-200) + (-201)

= [(-199) + (-201)] + (-200)

= (-400) + (-200)

= -600

ok k cho minh nhe