Câu a sai đề (sửa đề lại rồi làm tương tự câu b

Câu b 

\(\frac{5932+6001\times5931}{5932\times6001-69}=\frac{5932+6001\times5931}{\left(5931+1\right)\times6001-69}=\frac{5932+6001\times5931}{5931\times6001+6001-69}=\frac{5932+6001\times5931}{5932\times6001+5932}=1\)

\(254.399-\frac{145}{254+399.255}=101346-\frac{145}{101999}=1012031170\)

\(5932+6001.\frac{5931}{35597863}=1\)

uh là nhân

a) \(=\dfrac{254x\left(400-1\right)-145}{254+\left(400-1\right)x253}=\dfrac{254x400-254-145}{254+253x400-253}\)

\(=\dfrac{101600-399}{101200+1}=\dfrac{101211}{101201}=\dfrac{101201+10}{101201}=1+\dfrac{10}{101201}\)

b) \(=\dfrac{5392+\left(600+1\right)x5391}{5392x\left(600+1\right)-69}=\dfrac{5392+600x5391+5391}{5392x600+5392-69}\)

\(=\dfrac{10783+3234600}{3235200+5323}=\dfrac{\text{3245383}}{\text{3240523}}=\dfrac{3240523+60}{3240523}=1+\dfrac{60}{3240523}\)

c) \(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{4}\right)+\dfrac{1}{2}x\left(\dfrac{1}{4}-\dfrac{1}{8}\right)+\dfrac{1}{32}\)

\(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{8}\right)+\dfrac{1}{32}\)

\(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{8}\right)+\dfrac{1}{32}=\dfrac{3}{16}+\dfrac{1}{32}=\dfrac{7}{32}\)

      \(\frac{254.399-145}{254+399.253}=\frac{\left(253+1\right).399-145}{254+399.253}\)

                                    \(=\frac{253.399+1.399-145}{254+399.253}\)

                                    \(=\frac{253.399+254}{254+399.253}\)

                                    \(=1.\)

\(\frac{5932+6001.5931}{5932.6001-69}=\frac{5932+6001.5931}{\left(5931+1\right).6001-69}\)

                                    \(=\frac{5932+6001.5931}{5931.6001+1.6001-69}\)

                                    \(=\frac{5932+6001.5931}{5931.6001+5932}\)

                                    \(=1.\)

Câu thứ nhất là: 202292,4291.       ;       Câu thứ hai là: 36011793,2.

a, \(\dfrac{254\times399-145}{254+399\times253}\)

= \(\dfrac{\left(253+1\right)\times399-`45}{254+399\times253}\)

= \(\dfrac{253\times399+399-145}{253\times399+254}\)

= \(\dfrac{253\times399+254}{253\times399+254}\)

= 1

b, \(\dfrac{5932+6001\times5931}{5932\times6001-69}\)

= \(\dfrac{5932+6001\times5931}{\left(5931+1\right)\times6001-69}\)

= \(\dfrac{5932+6001\times5931}{5931\times6001+6001-69}\)

= \(\dfrac{5932+6001\times5931}{5931\times6001+5932}\)

= 1

\(\frac{5932+6001x5931}{5932x6001-69}=\frac{6001x5931+5932}{5931x6001+6001-69}=\frac{6001x5931+5932}{6001x5931+5932}=1\)

B = 5932 + 6001 × 5931 / 5932 × 6001 - 69

B = 5932 + 6001 × 5931 / (5931 + 1) × 6001 - 69

B = 5932 + 6001 × 5931 / 5931 × 6001 + (6001 - 69)

B = 5932 + 6001 × 5931 / 5931 × 6001 + 5932

B = 1

B=1

\(\frac{5932+6001\times5931}{5932\times6001-69}=\frac{5932+6001\times5931}{\left(5931+1\right)\times6001-69}\)

\(=\frac{5932+6001\times5931}{5931\times6001+6001-69}=\frac{5932+6001\times5931}{5932\times6001+5932}=1\)

36011793,2 k minh di

5932 + 6001 × 5931 / 5932 × 6001 - 69

= 5932 + 6001 × 5931 / 5931 × 6001 + 6001 - 69

= 5932 + 6001 × 5931 / 5931 × 6001 + (6001 - 69)

= 5932 + 6001 × 5931 / 5931 × 6001 + 5932

= 1

Hic, ở đây có cả bố lẫn bà, sao bn bỉu mỗi bố z, bố + bà = các bn

Ủng hộ mk nha ☆_☆^_-

5932 + 6001 x 5931 = 5932 + 35597932

                                 = 35603864

5932 x 6001 - 69 = 35597932 - 69

                            = 35597863

5932 + 6001 x 5931 = 60021863

5932 x 6001 - 69 = 59325932

ý mk ko phải như vậy, ý mk là phân số đó

đáp án lần lượt là

2772

4154

1

1

nha

58 x 42 + 32 x 8 + 5 x 16

= 2436 + 256 + 80

= 2692 + 80

= 2772

456 : 2 x 18 + 456 : 3 - 102 

= 228 x 18 + 152 - 102

= 4104 + 152 - 102 

= 4256 - 102 

= 4154

( 254 x 399 - 145 ) : ( 254 + 399 x 253 )

= ( 101346 - 145 ) : ( 254 + 100947 )

= 101201 : 101201

= 1

( 5932 + 6001 x 5931 ) : ( 5932 x 6001 - 99 )

= ( 5932 + 35591931 ) : ( 35597932 - 99 )

= 35597863 : 35597833

= \(\frac{35597863}{35597833}=1,000000843\)