Câu1
( x-7/4)+( x-6/3)+( x-5/2)+( x+81/7)=0
Câu2
( 1/1×101)+( 1/2×102)+( 1/3×103)+(1/10×11×X=(1/1×11)+(1/2×12)+...+(1/100×110)
Câu3
( x-1/2013)+( x-2/2012)+( x-3/2011)+...+( x-2012/2) =2012
tìm x
a ,x-7/4+x-6/3+x-5/3+x+81/7=0
b,x-1/2013+x-2/2012+x+3/2011+...+x-2012/2=2012
c(1/1x101=1/2x102+1/3x103+1/4x164+1/10x110)x X =(1/1x11+1/2x12+...+1/100x110)
ai nhanh mình tick
a) 2x-1/11+2x-2/12+2x-3/13=2x+5/5+2x+6/4+2x+7/3
b) x-1/2016+x-2/2015+x-3/2014+x-4/2013+x-5/2012 -5=0
c) x+2017/2+x+2015/3+x+2013/4+x+2011/5+8=0
(1-2+3-4+5-6+7-8+...+101-102+103) * x-120=2012
(1-2+3-4+5-6+7-8+...+101-102+103) * x-120=2012
[ -1 + ( -1 ) ... ( -1 ) + 103] * x -120 = 2012
( -1 x 51 + 103 ) * x - 120 = 2012
( -51 +103) * x = 2012 + 120
52 * x =2132
x= 2132 : 52
x= 41
Câu 1:So sánh M= 1/1.2+1/2.3+...+1/49.50 với 1
Câu 2: Tính. B=1+2+2^2+2^3+...+2^2008/1-2^2009
Câu 3.Tính. B=1/2+1/6+1/12+1/20+1/30+...+1/9900
Câu 4.Tính. 1/1.3+1/3.5+1/5.7+...+1/2009.2011
Câu 5. So sánh:
A=2011+2012/2012+2013
Và B=2011/2012+2011/2012+2012/2013
Câu 6: Tìm x biết :.(x/7+0,25)=-1/28
a) \(\dfrac{2}{1^2}.\dfrac{6}{2^2}.\dfrac{12}{3^2}.\dfrac{20}{4^2}.\dfrac{30}{5^2}.....\dfrac{110}{10^2}.x=-20\)
b) \(\left(1+\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2013}\right).x+2013=\dfrac{2014}{1}+\dfrac{2015}{2}+...+\dfrac{4025}{2012}+\dfrac{4026}{2013}\)
c) \(\left(\dfrac{1}{1.2}+\dfrac{1}{3.4}+...+\dfrac{1}{99.100}\right).x=\dfrac{2012}{51}+\dfrac{2012}{52}+...+\dfrac{2012}{99}+\dfrac{2012}{100}\)
a) 2x-1/11+2x-2/12+2x-3/13=2x+5/5+2x+6/4+2x+7/3
b) x-1/2016+x-2/2015+x-3/2014+x-4/2013+x-5/2012 -5=0
c) x+2017/2+x+2015/3+x+2013/4+x+2011/5+8=0
giúp mình với mọi người làm ơn đi mình cần gấp lắm!!!!
a) 2x-1/11+2x-2/12+2x-3/13=2x+5/5+2x+6/4+2x+7/3
b) x-1/2016+x-2/2015+x-3/2014+x-4/2013+x-5/2012 -5=0
c) x+2017/2+x+2015/3+x+2013/4+x+2011/5+8=0
giúp mình với mọi người làm ơn đi mình cần gấp lắm!!!!
a)2x-1/11+2x-2/12+2x-3/13=2x+5/5+2x+7/6+2x+7/3
b)x-1/2016+x-2/2015+x-3/2014+x-4/2013+x-5/2012-5=0
c)x+2017/2+x+2015/3+x+2013/4+x+2011/5+8=0
giúp mình với mọi người ơi làm ơn mình cần gấp lắm!!!!
a: Sửa đề: \(\dfrac{2x-1}{11}+\dfrac{2x-2}{12}+\dfrac{2x-3}{13}=\dfrac{2x+5}{5}+\dfrac{2x+7}{3}+\dfrac{2x+4}{6}\)
\(\Leftrightarrow\dfrac{2x-1}{11}+1+\dfrac{2x-2}{12}+1+\dfrac{2x-3}{13}+1=\dfrac{2x+5}{5}+1+\dfrac{2x+7}{3}+1+\dfrac{2x+4}{6}+1\)
=>2x+10=0
hay x=-5
b: \(\dfrac{x-1}{2016}+\dfrac{x-2}{2015}+\dfrac{x-3}{2014}+\dfrac{x-4}{2013}+\dfrac{x-5}{2012}-5=0\)
\(\Leftrightarrow\left(\dfrac{x-1}{2016}-1\right)+\left(\dfrac{x-2}{2015}-1\right)+\left(\dfrac{x-3}{2014}-1\right)+\left(\dfrac{x-4}{2013}-1\right)+\left(\dfrac{x-5}{2012}-1\right)=0\)
=>x-2017=0
hay x=2017
a)2^x+2^x+1+2^x+2+2^x+3=480
b)(1/2+1/3+...+1/2012+1/2013)*x=2012/1+2011/2+2010/3+..+2/2011+1/2012