Ta có:

( 5 2 - 1).P = ( 5 2  – 1).12.( 5 2  + 1)( 5 4  + 1)( 5 8  + 1)( 5 16  + 1)

= 12.(  5 2  – 1).( 5 2  + 1)( 5 4 + 1)( 5 8  + 1)( 5 16 + 1)

= 12.(  5 4  - 1)(  5 4  + 1)(  5 8  + 1)( 5 16  + 1)

= 12.(  5 8  - 1)(  5 8  + 1)( 5 16  + 1)

= 12.(  5 16  - 1)( 5 16  + 1)

= 12.(  5 32  - 1)

\(C=48\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)=2\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)=2\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\left(5^{128}-1\right)=2.5^{128}-2\)

c: Ta có: \(C=48\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\cdot\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^2-1\right)\left(5^2+1\right)\cdot\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{16}-1\right)\cdot\left(5^{16}+1\right)\cdot\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{32}-1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{64}-1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{128}-1\right)\)

\(=2\cdot5^{128}-2\)

d: Ta có: \(E=\left(x-2\right)^3-\left(x+1\right)\left(x^2-x+1\right)+6\left(x-1\right)^2\)

\(=x^3-6x^2+12x-8-x^3-1+6x^2-12x+6\)

\(=-3\)

Ta có: \(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(\Rightarrow P=\dfrac{24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{\left(5^{16}-1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{5^{32}-1}{2}\)

1 + 1 + 1 + 1 + 1 + 1 x 0 + 1 = 6

Còn bn nào trl = 0 là sai  

Vì nhân chia trc cộng trừ sau

~ Học tốt ~

Câu hỏi :

1 + 1 + 1 + 1 + 1 + 1 × 0 + 1 = ?

Trả lời :

= 6

Ak , mà bn ơi . Bn cs 1 điểm hỏi đáp thì k mk cx ko lên điểm đâu , pk trên hoặc = 10 điểm k ms lên điểm đc !!!

thi 1+1=3 dung roi 

Ta có

\(1+1=3\)

\(\Rightarrow2=3\)

\(\Rightarrow1\cdot2=1\cdot3\)

\(\Rightarrow2=3\)

mà 2 =1+1 => 1+1=3 (đpcm)

ko cs kiến thức nào 1+1=3( trừ khi tính sai)

a) x+ 22 + ( -14) + 52

=x+22 - 14 + 52

= x+(22+52-14)

=x+ (74-14)

=x + 60

b)(-90) - ( p + 10) + 100

=-90 - p - 10+100

=(-90 - 10 + 100) - p 

=(-100 +100) - p 

= -p

đúng ko vậy

Đúng rồi nhé 

3.2³ + 18 : 2³ . 2²= 3 . 8 + 18 : 8 . 4 = 21 +2,25.4=21+9=30

407+ [(180- 160) : 4 + 3² ]=407+ [(180- 160) : 4 + 9 ]=407+14=421

58 . 75 + 58 . 50 - 58 . 25=58 . (75 +  50 -  25)=58.100=5800

khỏi chép đề nha

a) = 32,768 + 18 : 8 . 4

    = 32,768 + 2,25 . 4

    = 32,768 + 9

    = 41,768

b) = 407 + ( 20 : 4 + 9 )

    = 407 + ( 5 + 9 )

    = 407 + 14

    = 421

c) = 58 . ( 75 + 50 - 25 )

    = 58 . 100

    = 5800

tk nha

3.2³ + 18 : 3² + 2³ . 2² nha do mk viết lộn

a= 4

b = 4

c= 6

d=6

tick đuê!!!!

câu b,c bài này thì sao

b)(-90)-(p+10)+100

=-(p+10)+10

=-P

x+22+(-14)+52

=x+8+52

=x+60

a) x + 22 + (-14) + 52 = x + [ 22 + 52 ] + (-14) = x + 74 + (-14)

   = x + [ 74 + (-14) ] = x + 60

b) (-90) - (p + 10) + 100 = (-90) - p - 10 + 100 = - p - 90 - 10 + 100

    = -p - (90 + 10) + 100 = -p - 100 + 100 = -p + [ (-100) + 100] = -p