\(2x^2\left(x-2\right)-2x\left(x-1\right)\left(x+1\right)=2x^3-4x^2-2x^3+2x=-4x^2+2x=-2x\left(2x-1\right)\)

\(2x^2\left(x-2\right)-2x\left(x-1\right)\left(x+1\right)\)

\(=2x^3-4x^2-2x\left(x^2-1\right)\)

\(=2x^3-4x^2-2x^3+2x=-4x^2+2x\)

\(A=\left(x^2-2x+2\right)\left(x^2-2\right)\left(x^2+2x+2\right)\left(x^2+2\right)\)

\(\Leftrightarrow A=\left[\left(x^2+2-2x\right)\left(x^2+2+2x\right)\right]\left[\left(x^2-2\right)\left(x^2+2\right)\right]\)

\(\Leftrightarrow A=\left[\left(x^2+2\right)^2-4x^2\right]\left(x^4-4\right)\)

\(\Leftrightarrow A=\left(x^2+4x^2+4-4x^2\right)\left(x^4-4\right)\)

\(\Leftrightarrow A=\left(x^4+4\right)\left(x^4-4\right)\)

\(\Leftrightarrow A=x^{16}-16\)

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\(=\frac{\left(x+1\right)^2}{\left(x-1\right)^2}:\frac{2\left(x+1\right)^2}{4\left(x-1\right)^2}=\frac{\left(x+1\right)^2}{\left(x-1\right)^2}.\frac{4\left(x-1\right)^2}{2\left(x+1\right)^2}=2\)

\((2x-1)(x-2)=2x^2-4x-x+2=2x^2-5x+2\)

Cái này giống dạng toán thường thôi bạn ạ! Để mình giải cho bạn nhé!

x-2/x-1 + 2x(1-x)/x^2-x = x-2/x-1 + (-2x(x-1))/x(x-1) = x-2/x-1 + (-2x/x) = x^2-2x/x(x-1) +( -2x(x-1)/x(x-1)) = x^2-2x+(-2x(x-1))/x(x-1)

= x^2-2x-2x^2+2x/x(x-1) = -x^2/x(x-1) = -x/x-1 

\(A=\left(2x-2\right)^2-4x\left(x-2\right)+46\)

\(\Leftrightarrow A=4x^2-8x+4-4x^2+8x+46\)

\(\Leftrightarrow A=50\)

\(A=\left(2x-2\right)^2-4x\left(x-2\right)+46\)

\(A=4x^2-8x+4-4x^2+8x+46\)

\(A=50\)

Chúc bạn học tốt!!!

A = (2x - 2)² - 4x(x - 2) + 46

=> A = 4x² - 8x + 4 - 4x² + 8x + 46

=> A = (4x² - 4x²) + (-8x + 8x) + 4 + 46

=> A = 50

2ax^2-a(1+2x^2)-[a-x(x+a)]

=2ax²-2ax²+a+x²-ax+a

=(2ax²-2ax²)-(a+a)+ax+x²

=0-2a+ax+x²

=x²+ax-2a