\(\left[12\cdot15-x\right]\cdot\frac{1}{4}=120\cdot\frac{1}{4}\)

\(\Leftrightarrow\left[180-x\right]\cdot\frac{1}{4}=30\)

\(\Leftrightarrow180-x=30:\frac{1}{4}\)

\(\Leftrightarrow180-x=120\)

\(\Leftrightarrow x=60\)

tl moi cau

\(\left[x\cdot0,25+2012\right]\cdot2013=\left[50+2012\right]\cdot2013\)

\(\Leftrightarrow x\cdot0,25\cdot2013+2012\cdot2013=2062\cdot2013\)

\(\Leftrightarrow x\cdot\frac{2013}{4}+4050156=4150806\)

\(\Leftrightarrow x\cdot\frac{2013}{4}=100650\)

\(\Leftrightarrow x=100650:\frac{2013}{4}=100650\cdot\frac{4}{2013}=200\)

e: \(\dfrac{17}{5}:x=\dfrac{34}{5}:\dfrac{4}{3}=\dfrac{34}{5}\cdot\dfrac{3}{4}=\dfrac{102}{20}=\dfrac{51}{10}\)

\(\Leftrightarrow x=\dfrac{17}{5}:\dfrac{51}{10}=\dfrac{17}{5}\cdot\dfrac{10}{51}=\dfrac{10}{5}\cdot\dfrac{17}{51}=2\cdot\dfrac{1}{3}=\dfrac{2}{3}\)

f: \(x:\dfrac{4}{5}=\dfrac{25}{8}:\dfrac{5}{4}=\dfrac{25}{8}\cdot\dfrac{4}{5}=\dfrac{100}{40}=\dfrac{5}{2}\)

\(\Leftrightarrow x=\dfrac{5}{2}\cdot\dfrac{4}{5}=\dfrac{4}{2}=2\)

g: \(\left(0.25x+2012\right)\cdot2013=\left(50+2012\right)\cdot2013\)

\(\Leftrightarrow0.25x+2012=50+2012\)

\(\Leftrightarrow0.25x=50\)

hay x=200

h: \(\left(x-\dfrac{1}{2}\right)\cdot\dfrac{5}{3}=\dfrac{7}{4}-1=\dfrac{3}{4}\)

\(\Leftrightarrow x-\dfrac{1}{2}=\dfrac{3}{4}:\dfrac{5}{3}=\dfrac{9}{20}\)

\(\Leftrightarrow x=\dfrac{9}{20}+\dfrac{1}{2}=\dfrac{9}{20}+\dfrac{10}{20}=\dfrac{19}{20}\)

giúp mik nhé

đi mà giúp đi

e)175:x=345:43

3,4:x=6,8:43

3,4:x=5,1

x=3,4:5,1

x=23

f)x:45 =258:54

x:45=52

x=52×45

x=2

g)(x×0,25+2012)×2013=(50+2012)×2013g)

(x×0,25+2012)×2013=2062×2013

x×0,25+2012=(2062×2013):2013

x×0,25+2012=2062

x×0,25=2062−2012

x×0,25=50

x=50:0,25

x=200

h)(x−12)×53=74−12h)

(x−12)×53=54

x−12=54:53

x−12=34

x=34+12

x=54

dư 0

vì ta thấy:

2010+2013=2015 chia hết cho 5

nên A+B chia 5 dư 0

tíc mình nha

Ta có :

2012 x 2012 x 2012 x ... x 2012 x 2012 ( 2013 chữ số 2012 ) = 2012 ^ 2013 => chữ số tận cùng là 8                               (1)

2013 x 2013 x 2013 x ... x 2013 x 2013 ( 2012 chữ số 2013 ) = 2013 ^ 2012 => chữ số tận cùng là 9                               (2)

Từ (1) và (2) => ( 8 + 9 ) : 5 = 17 : 5 dư 2

Mơ đi nhé. Dư 3

(0,25X + 2012) x 2013 = (50 + 2012) x 2013

0,25X + 2012 = 50 + 2012

0,25X = 50

X = \(\frac{50}{0,25}=200\)

x=200

Bạn tham khảo nhé : 

Ta có : 

\(\frac{x-3}{2012}+\frac{x-2}{2013}=\frac{x-2013}{2}+\frac{x-2012}{3}\)

\(\Leftrightarrow\)\(\left(\frac{x-3}{2012}-1\right)+\left(\frac{x-2}{2013}-1\right)=\left(\frac{x-2013}{2}-1\right)+\left(\frac{x-2012}{3}-1\right)\)

\(\Leftrightarrow\)\(\frac{x-2015}{2012}+\frac{x-2015}{2013}=\frac{x-2015}{2}+\frac{x-2015}{3}\)

\(\Leftrightarrow\)\(\frac{x-2015}{2012}+\frac{x-2015}{2013}-\frac{x-2015}{2}-\frac{x-2015}{3}=0\)

\(\Leftrightarrow\)\(\left(x-2015\right)\left(\frac{1}{2012}+\frac{1}{2013}-\frac{1}{2}-\frac{1}{3}\right)=0\)

Mà \(\frac{1}{2012}+\frac{1}{2013}-\frac{1}{2}-\frac{1}{3}\ne0\)

\(\Rightarrow\)\(x-2015=0\)

\(\Rightarrow\)\(x=2015\)

Vậy \(x=2015\)

Chsuc bạn học tốt ~

chuyển vế t cs 

x+x-x-x=....

0x=.....

Suy ra vô nghiệm

(=) [(x-3/2012)-1]+[(x-2/2013)-1]= [(x-2013/2)-1]+[(x-2012/3)-1]

(=) x-2015/2012 .   +.   x-2015/2013. = x-2015/2.     +.     x-2015/3

(=)( x-2015 ) × (1/2012    + . 1/2013.    -. 1/2 .   -   1/3 .) =0

Mà 1/2012+1/2013-1/2-1/3≠0

=) x-2015 =0

(=) x=2015

Điều kiện: \(x\ge2012;y\ge2013;z\ge2014\)

Áp dụng bất đẳng thức Cauchy, ta có:

\(\left\{{}\begin{matrix}\dfrac{\sqrt{x-2012}-1}{x-2012}=\dfrac{\sqrt{4\left(x-2012\right)}-2}{2\left(x-2012\right)}\le\dfrac{\dfrac{4+x-2012}{2}-2}{2\left(x-2012\right)}=\dfrac{1}{4}\\\dfrac{\sqrt{y-2013}-1}{y-2013}=\dfrac{\sqrt{4\left(y-2013\right)}-2}{2\left(y-2013\right)}\le\dfrac{\dfrac{4+y-2013}{2}-2}{2\left(y-2013\right)}=\dfrac{1}{4}\\\dfrac{\sqrt{z-2014}-1}{z-2014}=\dfrac{\sqrt{4\left(z-2014\right)}-2}{2\left(z-2014\right)}\le\dfrac{\dfrac{4+z-2014}{2}-2}{2\left(z-2014\right)}=\dfrac{1}{4}\end{matrix}\right.\)

Cộng vế theo vế, ta được:

\(\dfrac{\sqrt{x-2012}-1}{x-2012}+\dfrac{\sqrt{y-2013}-1}{y-2013}+\dfrac{\sqrt{z-2014}-1}{z-2014}\le\dfrac{3}{4}\)

Đẳng thức xảy ra khi \(x=2016;y=2017;z=2018\)

Vậy....

x = 2013