tính:
\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
A= \(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(A=\frac{1135}{23}-\left(\frac{167}{32}+\frac{330}{23}\right)=\frac{1135}{23}-\frac{330}{23}+\frac{167}{32}=35+\frac{167}{32}=\frac{1287}{32}\)
tính hợp lí giá trị biểu thức sau :
\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)
\(=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)
\(=35\frac{0}{23}-5\frac{7}{32}\)
\(=\frac{805}{23}-\frac{167}{32}\)
\(\frac{25760}{736}-\frac{3841}{736}\)
\(=\frac{21919}{736}=\frac{953}{32}\)
Tính hợp lý giá trị biểu thức sau
\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
1135/23-167/32+330/23
=(1135/23-330/23)+167/32
=805/23+167/32
=35+167/32
=1120/32+167/32
=1287/32
Tính hợp lí\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
Giải chi tiết nhé
\(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)
\(=49\frac{8}{23}-14\frac{8}{23}-5\frac{7}{12}\)
\(=35-5\frac{7}{32}\)
\(=35-\frac{167}{32}\)
\(=\frac{1120}{32}-\frac{167}{32}\)
\(=\frac{935}{32}\)
\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)
\(=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)
\(=35-5\frac{7}{32}\)
\(=35-\frac{167}{32}\)
\(=\frac{953}{32}\)
Bài 1 TÍNH
\(\frac{5}{16}:0,125-\left(2\frac{1}{4}-0,6\right).\frac{10}{11}\)
\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
Bài 1:
5/16:0,125-(2 1/4-0,6).10/11
=5/16:5/4-(9/4-3/5).10/11
=1/4-33/20.10/11
=1/4-3/2
=-5/4
\(\frac{5}{16}:0,125-\left(2\frac{1}{4}-0,6\right).\frac{10}{11}\)
\(=\frac{5}{16}.8-\frac{33}{20}.\frac{10}{11}\)
\(=\frac{5}{2}-\frac{3}{2}=\frac{2}{2}=1\)
<br class="Apple-interchange-newline"><div></div>49823 −(5732 +14823 )
\(49\frac{8}{23}-19\frac{417}{736}\)
\(=\frac{953}{12}\)
Study well
\(\frac{5}{16}:0,125-\left(2\frac{1}{4}-0,6\right).\frac{10}{11}\)ư
= \(\frac{5}{16}:\frac{1}{8}-\left(\frac{9}{4}-\frac{3}{5}\right).\frac{10}{11}\)
= \(\frac{5}{16}.8-\left(\frac{9}{4}-\frac{3}{5}\right).\frac{10}{11}\)
= \(\frac{5}{2}-\left(\frac{45}{20}-\frac{12}{20}\right).\frac{10}{11}\)
= \(\frac{5}{2}-\frac{33}{20}.\frac{10}{11}\)
= \(\frac{5}{2}-\frac{3}{2}\)
= \(1\)
b) \(49\frac{8}{23}-\left(5\frac{5}{32}+14\frac{8}{23}\right)\)
= \(49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)
= \(\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)
= \(35-\frac{167}{32}\)
= \(\frac{1120}{32}-\frac{167}{32}\)
= \(\frac{953}{32}\)
Chúc bạn học tốt !!!
\(a,49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(b,71\frac{38}{45}-\left(43\frac{8}{45}-1\frac{17}{57}\right)\)
\(d,\left(19\frac{15}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right).\frac{4}{5}\)
Tính nhanh:
A=\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
Giúp mik vs ạ!
bài 2 : Tính:
b) \(49\frac{8}{23}-\left(5\frac{7}{32}-14\frac{8}{23}\right)\)
HÃY giúp mình phép tính này ! toán 6
bạn chỉ cần phá ngoặc là làm đc thôi
= 1135/23 - ( 167/32 - 330/23 )
= 1135/23 - (-6719/736)
= 43039/736
=49/8/23-5/7/32+14/8/23
=(49/8/23+14/8/23)-5/7/32
=63/16/23-5/7/32
=58/351/736
Tính hợp lý giá trị của biểu thức sau:
\(A=49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(B=71\frac{38}{45}-\left(43\frac{8}{45}-1\frac{17}{57}\right)\)
\(C=\frac{-3}{7}.\frac{5}{9}+\frac{4}{9}.\frac{-3}{7}+2\frac{3}{7}\)
\(D=\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right).\frac{4}{5}\)