(5^7*0,6 -5:3 và 1^2)*(40%-1,4)*9-2)^2
(5^7*0,6 -5:3 1^2)*(40%-1,4)*9-2)^2
cảu 1 tính
A = -2/4 + 2/7 - 5/28
B = ( 5/7 * 0,6 - 5 : 3 và 1/2 ) * ( 40% - 1,4 ) * ( -2) 3
\(A=\frac{-2}{4}+\frac{2}{7}-\frac{5}{28}\)
\(A=\frac{-14}{28}+\frac{8}{28}-\frac{5}{28}\)
\(A=\frac{-6}{28}-\frac{5}{28}\)
\(A=\frac{-11}{28}\)
5 : 3 và 1/2 là sao ????
giải thích rõ ra thì mình sẽ giải bài B
ý của bạn là \(\frac{5\div3}{\frac{1}{2}}=\frac{10}{3}\)đúng ko
Bài 1: Thực hiện phép tính sau:
1) \(A=\dfrac{-2}{4}+\dfrac{2}{7}-\dfrac{5}{28}\)
2) \(B=\left(\dfrac{5}{7}.0,6-5:3\dfrac{1}{2}\right).\left(40\%-1,4\right).\left(-2\right)^3\)
\(\left(\frac{5}{7}.0,6-5:3\frac{1}{2}\right).\left(40\%-1,4\right).\left(-2\right)^3\)
B=\(\left(\frac{5}{7}.0,6-5:3\frac{1}{2}\right).\left(40\%-1,4\right).\left(-2\right)^3\)
bấm máy tính đi nha!
chúc học tốt
1) thuc hien phep tinh sau:
a)B=\(\left(\dfrac{5}{7}.0,6:3\dfrac{1}{2}\right)\) .(40%-1,4).(-2)^3
B = ( \(\dfrac{5}{7}.0,6:3\dfrac{1}{2}\)) . ( 40% - 1,4) . \(\left(-2\right)^3\)
= (\(\dfrac{5}{7}.\dfrac{3}{5}\): \(\dfrac{7}{2}\)) . ( \(\dfrac{2}{5}-\dfrac{7}{5}\)) . (-8)
= (\(\dfrac{15}{35}:\dfrac{7}{2}\)) . \(\dfrac{-5}{5}\) . ( -8)
= (\(\dfrac{3}{7}.\dfrac{2}{7}\)) . (-1) . (-8)
= \(\dfrac{6}{49}\) . (-1) . (-8)
= \(\dfrac{-6}{49}\) . (-8)
= \(\dfrac{48}{49}\)
Vậy: B =\(\dfrac{48}{49}\)
Nhớ tick nha
B=(\(\dfrac{3}{7}.\dfrac{2}{7}\)).(\(\dfrac{4}{10}-\dfrac{14}{10}\)).(-8)
B=\(\dfrac{3}{7}.\left(-1\right)\left(-8\right)\)
B=\(\dfrac{24}{7}\)
Thực hiện phếp tính:
\(A=-\frac{7}{12}+\frac{11}{8}-\frac{5}{9}\)
\(B=5.\left(-2\right)^2-4.\left(-5\right)-20\)
\(C=\left(\frac{5}{7}.0,6-5:3\frac{1}{2}\right).\left(40\%-1,4\right).\left(-2\right)^2\)
A= \(\frac{19}{24}\) - \(\frac{5}{9}\)
A= \(\frac{17}{72}\)
B= 5. (-4) -4.(-5) - 20
B= -20 - (-20) - 20
B= 0 - 20
B= -20
Tính bằng cách hợp lí
a) 6-2+4/5 ×3+1/8-1+3/5:1/4
b) 13/15 *0,25 ×3 + 8/15-1+19/60 :1+23/24
c) (5/7 * 0,6 : 3+ 1/2) * (40 % - 1,4) * (-2)
a) B= ( 5/7 .0,6 - 5: 7/2 ) . ( 40% - 1,4 ) . (-2 )³
b) 1/2 .x + 3/5 . ( x - 2 ) = 3
câu a là tính câu b là tìm x nhé, giúp mk vsa,
\(B=\left(\dfrac{5}{7}\cdot0,6-5:\dfrac{7}{2}\right)\cdot\left(40\%-1,4\right)\cdot\left(-2\right)^3\\ =\left(\dfrac{5}{7}\cdot\dfrac{3}{5}-5\cdot\dfrac{2}{7}\right)\cdot\left(\dfrac{2}{5}-\dfrac{7}{5}\right)\cdot\left(-8\right)\\ =\left(\dfrac{3}{7}-\dfrac{10}{7}\right)\cdot\left(-1\right)\cdot\left(-8\right)\\ =\left(-1\right)\cdot\left(-1\right)\cdot\left(-8\right)\\ =\left(-8\right)\)
b,
\(\dfrac{1}{2}\cdot x+\dfrac{3}{5}\cdot\left(x-2\right)=3\\ \dfrac{1}{2}x+\dfrac{3}{5}x-\dfrac{6}{5}=3\\ x\left(\dfrac{1}{2}+\dfrac{3}{5}\right)=3+\dfrac{6}{5}\\ x\cdot\dfrac{11}{10}=\dfrac{21}{5}\\ x=\dfrac{21}{5}:\dfrac{11}{10}\\ x=\dfrac{42}{11}\\ Vậy......\)