Tính nhanh: \(E=\frac{4^9\times9^5+6^9\times2^6}{2^{10}\times3^8+6^8\times20}\)
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Tính nhanh:\(\frac{1\times2\times3+2\times4\times6+3\times6\times9+4\times8\times12+5\times10\times15}{1\times3\times5+2\times6\times10+3\times9\times15+4\times12\times20+5\times15\times25}-\frac{1+2+3+2+4+6+3+6+9+4+8+12+5+10+15}{1+3+5+2+6+10+3+9+15+4+12+20+5+15+25}\)
28 tháng 9 2020 lúc 23:00
\(\frac{4^5\times9^4-2\times6^9}{2^{10}\times3^8+6^8\times20}\)
\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
\(=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}\)
\(=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)
\(=\frac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.\left(1+5\right)}\)
\(=\frac{-1}{3}\)
Ta có:
\(\frac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)
\(=\frac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}\)
\(=\frac{2^{10}\cdot3^8\cdot\left(1-3\right)}{2^{10}\cdot3^8\cdot\left(1+5\right)}\)
\(=-\frac{2}{6}=-\frac{1}{3}\)
\(\frac{4^5\times9^4-2\times6^9}{2^{10}\times3^8+6^8\times20}\)
\(=\frac{2^{10}\times3^8-2^{10}.3^9}{2^{10}\times3^8+2^{10}\times3^8\times5}\)
\(=\frac{2^{10}\times3^8\left(1-3\right)}{2^{10}\times3^8\left(1+5\right)}\)
\(=\frac{-1}{3}\)
\(\orbr{\frac{2^{10}\times3^8+6^8\times20}{2\times6^9-4^5\times9^4}}\)
Rút gọn
\(\frac{4^5\times9^4-2\times6^9}{2^{10}\times3^8+6^8\times20}\)
Các bạn ơi ,giúp mình vớiBài 1:Rút gọna)frac{2^{19}times27^3+15times4^9times9^4}{6^9times2^{10}+12^{10}}b)frac{left(frac{-1}{2}right)^3-left(frac{3}{4}right)^3timesleft(-2right)^2}{2timesleft(-1right)^5+left(frac{3}{4}right)^2-frac{3}{8}}c)frac{45times9^4-2times6^4}{2^{19}times3^8+6^8times20}Bài 2:Tìm xa)5^x+5^{x+2}650b)3^{x-1}+5times3162
Đọc tiếp
Các bạn ơi ,giúp mình với
Bài 1:Rút gọn
a)\(\frac{2^{19}\times27^3+15\times4^9\times9^4}{6^9\times2^{10}+12^{10}}\)
b)\(\frac{\left(\frac{-1}{2}\right)^3-\left(\frac{3}{4}\right)^3\times\left(-2\right)^2}{2\times\left(-1\right)^5+\left(\frac{3}{4}\right)^2-\frac{3}{8}}\)
c)\(\frac{45\times9^4-2\times6^4}{2^{19}\times3^8+6^8\times20}\)
Bài 2:Tìm x
a)\(5^x+5^{x+2}=650\)
b)\(3^{x-1}+5\times3=162\)
\(E=\dfrac{5\times4^{15}\times9^9-4\times3^{20}\times8^9}{5\times2^{10}\times6^{19}-7\times2^{29}\times27^6}\)
\(\dfrac{5\times4^{15}\times9^9-4\times3^{20}\times8^9}{5\times2^{10}\times6^{19}-7\times2^{29}\times27^6}\\ =\dfrac{5\times2^{30}\times3^{18}-2^2\times3^{20}\times2^{27}}{5\times2^{10}\times3^{19}\times2^{19}-7\times2^{29}\times3^{18}}\\ =\dfrac{5\times2^{30}\times3^{18}-2^{29}\times3^{20}}{5\times2^{29}\times3^{19}-7\times2^{29}\times3^{18}}\\ =\dfrac{2^{29}\times3^{18}\times\left(5\times2-3^2\right)}{2^{29}\times3^{18}\times\left(5\times3-7\right)}\\ =\dfrac{10-9}{15-7}\\ =\dfrac{1}{8}\)
Đúng 2
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\(C=\dfrac{5\times4^6\times9^4-3^9\times\left(-8\right)^4}{4\times2^{13}\times3^8+2\times8^4\times\left(-27\right)^3}\)
\(C=\dfrac{5\times2^{12}\times3^8-3^9\times2^{12}}{2^2\times2^{13}\times3^8+2\times2^{12}\times\left(-3^9\right)}=\dfrac{3^8\times2^{12}\times\left(5-3\right)}{2^{15}\times3^8+2^{13}\times\left(-3\right)^9}\)
\(=\dfrac{3^8\times2^{12}\times2}{2^{13}\times3^8\times\left(4-3\right)}=\dfrac{1}{1}=1\)
\(#PaooNqoccc\)
Đúng 1
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1.Tính giá trị tuyệt đối:(hẹp me)
a)\(\frac{72^3\times54^2}{108^4}\)
b)\(\frac{3^{10}\times11+3^{10}\times5}{3^9\times2^4}\)
c)\(\left(1:\frac{1}{7}\right)^2[\left(2^2\right)^3:2^5]\times\frac{1}{49}\)
d)\(\frac{4^6\times3^5-2^{12}\times3^6}{2^{12}\times9^3+8^4\times3^5}\)
1.Tính giá trị tuyệt đối:(hẹp me)
a)\(\frac{72^3\times54^2}{108^4}\)
b)\(\frac{3^{10}\times11+3^{10}\times5}{3^9\times2^4}\)
c)\(\left(1:\frac{1}{7}\right)^2[\left(2^2\right)^3:2^5]\times\frac{1}{49}\)
d)\(\frac{4^6\times3^5-2^{12}\times3^6}{2^{12}\times9^3+8^4\times3^5}\)