\(a,\dfrac{199}{200}=1-\dfrac{1}{200};\dfrac{200}{201}=1-\dfrac{1}{201}\\ Vì:\dfrac{1}{200}>\dfrac{1}{201}\\ \Rightarrow1-\dfrac{1}{200}< 1-\dfrac{1}{201}\\ Vậy:\dfrac{199}{200}< \dfrac{200}{201}\\ b,\dfrac{2001}{2002}=1-\dfrac{1}{2002};\dfrac{2002}{2003}=1-\dfrac{1}{2003}\\ Vì:\dfrac{1}{2002}>\dfrac{1}{2003}\Rightarrow1-\dfrac{1}{2002}< 1-\dfrac{1}{2003}\\ Vậy:\dfrac{2001}{2002}< \dfrac{2002}{2003}\)

\(c,\dfrac{2021}{2020}=1+\dfrac{1}{2020};\dfrac{2020}{2019}=1+\dfrac{1}{2019}\\ Vì:\dfrac{1}{2020}< \dfrac{1}{2019}\\ Nên:1+\dfrac{1}{2020}< 1+\dfrac{1}{2019}\\ Vậy:\dfrac{2021}{2020}< \dfrac{2020}{2019}\\ d,\dfrac{199}{198}=1+\dfrac{1}{198};\dfrac{200}{199}=1+\dfrac{1}{199}\\ Vì:\dfrac{1}{198}>\dfrac{1}{199}\\ Nên:1+\dfrac{1}{198}>1+\dfrac{1}{199}\\ Vậy:\dfrac{199}{198}>\dfrac{200}{199}\)

a) Ta có:

\(1-\frac{9}{11}=\frac{11-9}{11}=\frac{2}{11}\)

\(1-\frac{13}{15}=\frac{15-13}{15}=\frac{2}{15}\)

Vì \(\frac{2}{15}< \frac{2}{11}\Rightarrow1-\frac{9}{11}< 1-\frac{13}{15}\Rightarrow\frac{9}{11}>\frac{13}{15}\)

b) Ta có

\(\frac{201}{301}>\frac{201}{308}>\frac{199}{308}\Rightarrow\frac{201}{301}>\frac{199}{308}\)

Không quy đồng tử số và mẫu số , hãy so sánh các phân số sau : 2012/ 2013 và 1998 / 1999

 2012/ 2013 > 1998 / 1999

DỄ MÀ

2012/2013>1998/1999 HOẶC 2012/2013 < 1998/1999

\(\frac{2012}{2013}\)và \(\frac{1998}{1999}\).

Lại có:

\(\frac{2012}{2013}=\frac{2013-1}{2013}=1-\frac{1}{2013}\).

\(\frac{1998}{1999}=\frac{1999-1}{1999}=1-\frac{1}{1999}\).

Mà \(\frac{1}{2013}< \frac{1}{1999}\)\(\Rightarrow\frac{-1}{2013}>\frac{-1}{1999}\).

\(\Rightarrow1-\frac{1}{2013}>1-\frac{1}{1999}\).

Do đó\(\frac{2012}{2013}>\frac{1998}{1999}\).

Vậy \(\frac{2012}{2013}>\frac{1998}{1999}\)

ko biet luon a bn

\(\frac{2000}{2001}=1-\frac{1}{2001}\)

\(\frac{2001}{2002}=1-\frac{1}{2002}\)

\(2001< 2002\Rightarrow\frac{1}{2001}>\frac{1}{2001}\)

                             \(\Rightarrow1-\frac{1}{2001}< 1-\frac{1}{2002}\)

                              \(\Rightarrow\frac{2000}{2001}< \frac{2001}{2002}\)

ta có:2000/2001=1-1/2001

2001/2002=1-1/2002

mà 2001<2002

suy ra 1/2001>1/2002

suy ra 1-1/2001<1-1/2002

vậy 2000/2001<2001/2002

Trả lời:

Ta có: \(\frac{2000}{2001}=\frac{2001-1}{2001}=\frac{2001}{2001}-\frac{1}{2001}=1-\frac{1}{2001}\)

          \(\frac{2001}{2002}=\frac{2002-1}{2002}=\frac{2002}{2001}-\frac{1}{2002}=1-\frac{1}{2002}\)

Ta thấy: \(2001< 2002\)

\(\Leftrightarrow\frac{1}{2001}>\frac{1}{2002}\)

\(\Leftrightarrow-\frac{1}{2001}< -\frac{1}{2002}\)

\(\Leftrightarrow1-\frac{1}{2001}< 1-\frac{1}{2002}\)

\(\Leftrightarrow\frac{2000}{2001}< \frac{2001}{2002}\)

Vậy ....