( 19x + 2.5² ) : 14 = ( 13 - 8 )²- 4 ²

( 19x + 2.5² ) : 14 = 5²- 4 ²

( 19x + 2.5² ) : 14 = 25- 16

( 19x + 2.5² ) : 14 =9

( 19x + 50 ) : 14 =9

 19x + 50=9 . 14

 19x + 50=126

19x=126-50

19x=76

x=76:19

x=4

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(19x+2*5^2)/14=(13-8)^2-4^

(19x+2*25)/14=(13-8)^2-16

(19x+2.25)/14=5^-16

(19x+2.25)/14=25-16

(19+2.25)=9*14

19X=126+50

x=76/19

x=4

chia từng câu ra rồi mình giải cho

a) \(\left(19x+2\cdot5^2\right)\div14=\left(13-8\right)^2-4^2\)

\(\left(19x+2\cdot25\right)\div14=5^2-16\)

\(\left(19x+50\right)\div14=25-16=9\)

\(19x+50=9\cdot14=126\)

\(19x=126-50=76\)

\(x=76\div19=4\)

b) \(2\cdot3^x=10\cdot3^{12}+8\cdot\left(3^3\right)^4\)

\(2\cdot3^x=\left(10+8\right)\cdot3^{12}\)

\(2\cdot3^x=18\cdot3^{12}\)

\(\Rightarrow2\cdot3^x=2\cdot3^2\cdot3^{12}\Rightarrow2\cdot3^x=2\cdot3^{15}\Rightarrow x=15\)

a, \left(19.x+2.5^2\right)\div14=\left(13-8\right)^2-4^2(19.x+2.52)÷14=(13−8)2−42
\left(19.x+2.25\right)\div14=5^2-4^2(19.x+2.25)÷14=52−42
\left(19.x+2.25\right)\div14=25-16(19.x+2.25)÷14=25−16
\left(19.x+50\right)\div14=9(19.x+50)÷14=9
\left(19.x+50\right)=9.14(19.x+50)=9.14
19.x+50=12619.x+50=126
19.x=126-5019.x=126−50
19.x=7619.x=76
\Rightarrow x=76\div19⇒x=76÷19
\Rightarrow x=4⇒x=4
Vậy x = 4
b, 2.3^x=10.3^{12}+8.27^42.3x=10.312+8.274
2.3^x=10.3^{12}+8.\left(3^3\right)^42.3x=10.312+8.(33)4
2.3^x=10.3^{12}+8.3^{12}2.3x=10.312+8.312
2.3^x=\left(10+8\right).3^{12}2.3x=(10+8).312
2.3^x=18.3^{12}2.3x=18.312
2.3^x=2.3^3.3^{12}2.3x=2.33.312
2.3^x=2.3^{15}2.3x=2.315
\Rightarrow x=15⇒x=15
Vậy x = 15

a.(19x+2×25):14=5^2-16 (19x+50):14=25-16 (19x+50):14=9 (19x+50)=9×14=126 19x+50=126 19x=126-50=76 x=76:19 x=4 b.2×3^x=10×3^12+2^3×3^12 2×3^x=3^12×(10+8) 2×3^x=3^12×18 2×3^x=3^12×3^2×2 2×3^x=3^14×2 Suy ra:3^x=3^14 Hay x=14

`( 19x + 2*5^2 ) : 14 = ( 13-8)^2 - 4^2`

`=> ( 19x + 50 ) : 14 = 5^2 - 4^2`

`=> ( 19x + 50 ) : 14 = 9`

`=> 19x + 50 = 9*14`

`=> 19x + 50 = 126`

`=> x = ( 126 - 50 )/19`

`=> x = 4`

Vậy `x=4` 

(19x + 2.5\(^2\) ) : 14 = 5\(^2\)- 4\(^2\)

(19x + 2.5\(^2\) ) : 14 = 9

19x + 2.5\(^2\)  = 9.14

19x + 50 = 126

19x = 126-50=76;19

x = 4

 

 

(19x+2.5²):14=(13-8)²-4²

(19x+2.25):14=5²-4²

(19x+50):14=25-16

(19x+50):14=9

19x+50=9.14

19x+50=126

19x      =126-50

19x      =76

    x      =76:19

    x      =4

\(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)

\(\Rightarrow\left(19x+50\right):14=25-16\)

\(\Rightarrow19x+50=9.14=126\)

\(\Rightarrow19x=76\)

\(\Rightarrow x=76:19=4\)

(19x+2.5²):14 =(13-8)²-4²

(19x + 50):14  = 5²-4²

(19x + 50):14  = 9

19x + 50          = 9.14

 19x+50           = 126

  19x                 =76

     x                   =76:19

     x                   =4

Chúc các bn học tốt ah🥰🥰

Ta có :

\(\frac{19x+2.5^2}{14}=\left(13-8\right)^2-4^2\)

\(\Leftrightarrow\)\(\frac{19x+2.25}{14}=5^2-4^2\)

\(\Leftrightarrow\)\(\frac{19x+50}{14}=25-16\)

\(\Leftrightarrow\)\(\frac{19x+50}{14}=9\)

\(\Leftrightarrow\)\(19x+50=126\)

\(\Leftrightarrow\)\(19x=76\)

\(\Leftrightarrow\)\(x=\frac{76}{19}\)

\(\Leftrightarrow\)\(x=4\)

Vậy \(x=4\)

\(...\Rightarrow\left(19x+50\right):14=5^2-4\Rightarrow\left(19x+50\right):14=21\Rightarrow\left(19x+50\right)=21.14\)

\(\Rightarrow19x+50=294\Rightarrow19x=244\Rightarrow x=\dfrac{244}{19}\)

câu b sai rồi,thế này mới đúng nè:

b,(19x+2.5⁵):4=(13-8)²-4²

(19x+2.5²):14=5²-4²

(19x+2.5²):14=8

19x+2.5²+126

19x+50=126

19x=76

x=4

sai rồi 8 phải sửa là 9 mới đúng