Question

 Tìm x

$( 19x + 2 . 5^{2}$ ) ; 14  = $( 13 - 8 )^{2}$ - $4^{2}$  

Answer 1

`( 19x + 2*5^2 ) : 14 = ( 13-8)^2 - 4^2`

`=> ( 19x + 50 ) : 14 = 5^2 - 4^2`

`=> ( 19x + 50 ) : 14 = 9`

`=> 19x + 50 = 9*14`

`=> 19x + 50 = 126`

`=> x = ( 126 - 50 )/19`

`=> x = 4`

Vậy `x=4` 

Answer 2

(19x + 2.5\(^2\) ) : 14 = 5\(^2\)- 4\(^2\)

(19x + 2.5\(^2\) ) : 14 = 9

19x + 2.5\(^2\)  = 9.14

19x + 50 = 126

19x = 126-50=76;19

x = 4

 

 

Answer 3

(19x+2.5²):14=(13-8)²-4²

(19x+2.25):14=5²-4²

(19x+50):14=25-16

(19x+50):14=9

19x+50=9.14

19x+50=126

19x      =126-50

19x      =76

    x      =76:19

    x      =4