(1-1/7).(1-2/7)....(1-1/2/7).(1-1/3/7)
a)-1/24-[1/4-(1/2-7/8)]
b)(5/7-7/5)-[-1/2-(-2/7-1/10)
c)(-1/2)-(-3/5)+(-1/9)+1/71-(-2/7)+4/35-7/18
d) (3-1/4+2/3) -(5-1/3-6/5)-(6-7/4+3/2)
a) -1/24 - [ 1/4 - ( 1/2 - 7/8 )]
= -1/24 - [ 1/4 +3/8 ]
= -1/24 - 5/8
= -2/3.
a) -1/24 - [ 1/4 - ( 1/2 - 7/8 )]
= -1/24 - [ 1/4 +3/8 ]
= -1/24 - 5/8
= -2/3.
Xin lỗi nha chỉ có thời gian làm câu a) thôi
(5/7-7/7)-[0,2-(-2/7-1/10]
(3-1/4+2/3)-(5-1/3-5/6)-(6-7/4+-3/2)
1/3-3/4--3/5+1/64-2/9-1/3+1/15
3/5:(1/15-1/6)+3/5:(-1/3-16/15)
1/2(-3/4-13/14):5/7-(-2/21+1/7):7/7
\(\left(\dfrac{5}{7}-\dfrac{7}{7}\right)-\left[0,2-\left(-\dfrac{2}{7}-\dfrac{1}{10}\right)\right]\)
=\(-\dfrac{2}{7}-\left[\dfrac{1}{5}+\dfrac{2}{7}+\dfrac{1}{10}\right]\)
=\(-\dfrac{2}{7}-\dfrac{1}{5}-\dfrac{2}{7}-\dfrac{1}{10}\)
=\(\left(-\dfrac{2}{7}-\dfrac{2}{7}\right)-\left(\dfrac{1}{5}+\dfrac{1}{10}\right)\)
=\(-\dfrac{4}{7}-\left(\dfrac{2}{10}+\dfrac{1}{10}\right)\)
=\(-\dfrac{4}{7}-\dfrac{3}{10}\)
=\(-\dfrac{40}{70}-\dfrac{21}{70}\)
=\(-\dfrac{61}{70}\)
(3 - \(\dfrac{1}{4}\) + \(\dfrac{2}{3}\)) - (5 - \(\dfrac{1}{3}\) - \(\dfrac{5}{6}\)) - (6 - \(\dfrac{7}{4}\) - \(\dfrac{3}{2}\))
= 3 - \(\dfrac{1}{4}\) + \(\dfrac{2}{3}\) - 5 + \(\dfrac{1}{3}\) + \(\dfrac{5}{6}\) - 6 + \(\dfrac{7}{4}\) + \(\dfrac{3}{2}\)
= (3 - 5 - 6) + ( \(\dfrac{7}{4}\) - \(\dfrac{1}{4}\)) + (\(\dfrac{2}{3}\) + \(\dfrac{1}{3}\)) + \(\dfrac{3}{2}\) + \(\dfrac{5}{6}\)
= - 8 + \(\dfrac{3}{2}\) + 1 + \(\dfrac{3}{2}\) + \(\dfrac{5}{6}\)
= (- 8 + 1) + (\(\dfrac{3}{2}\) + \(\dfrac{3}{2}\)) + \(\dfrac{5}{6}\)
= -7 + 3 + \(\dfrac{5}{6}\)
= - 4 + \(\dfrac{5}{6}\)
= \(\dfrac{-19}{6}\)
c) 6 1/7 + 1/7 + 1/7 + 7 1/7 d) 12 1/3 : 1/4 + 3 2/3 : 1/4 e) (1 + 1/2 ) × (1 + 1/3 ) × (1 + 1/4 ) × … × (1 + 1/2020 ) f) 1 1/2 × 1 1/3 × 1 1/4 × 1 1/5 × … × 1 1/2021
2/7 : 1/4 - 1/7
7/11 x 0 + 5/9 : 1/2
( 3/7 + 1/4 ) : 3/4
4/3 x 1/2 + 7/2 : 1/4
\(\dfrac{2}{7}:\dfrac{1}{4}-\dfrac{1}{7}=\dfrac{2}{7}x\dfrac{4}{1}-\dfrac{1}{7}=\dfrac{8}{7}-\dfrac{1}{7}=\dfrac{7}{7}=1\)
\(\dfrac{7}{11}x0+\dfrac{5}{9}:\dfrac{1}{2}=0+\dfrac{5}{9}x\dfrac{2}{1}=\dfrac{10}{9}\)
\(\left(\dfrac{3}{7}+\dfrac{1}{4}\right):\dfrac{3}{4}=\left(\dfrac{12}{28}+\dfrac{7}{28}\right)x\dfrac{4}{3}=\dfrac{19}{28}x\dfrac{4}{3}=\dfrac{19}{21}\)
\(\dfrac{4}{3}x\dfrac{1}{2}+\dfrac{7}{2}:\dfrac{1}{4}=\dfrac{4}{6}+\dfrac{7}{2}x\dfrac{4}{1}=\dfrac{2}{3}+\dfrac{14}{1}=\dfrac{2}{3}+14=14\dfrac{2}{3}=\dfrac{44}{3}\)
Tính:
7 – 4 – 2 = … | 7 – 3 – 1 = … | 7 – 4 – 1 = … |
7 – 5 – 1 = … | 7 – 1 – 3 = … | 7 – 2 – 4 = … |
Lời giải chi tiết:
7 – 4 – 2 = 1 | 7 – 3 – 1 = 3 | 7 – 4 – 1 = 2 |
7 – 5 – 1 = 1 | 7 – 1 – 3 = 3 | 7 – 2 – 4 = 1 |
2/5+3/7=...
1/7+3/7+4/7=(1/7+3/7)+....=1/7+(3/7+...)=(1/7+4/7)+...
\(\dfrac{2}{5}+\dfrac{3}{7}=\dfrac{14}{35}+\dfrac{15}{35}=\dfrac{29}{35}\)
\(\dfrac{1}{7}+\dfrac{3}{7}+\dfrac{4}{7}=\left(\dfrac{1}{7}+\dfrac{3}{7}\right)+\dfrac{4}{7}=\dfrac{1}{7}+\left(\dfrac{3}{7}+\dfrac{4}{7}\right)=\left(\dfrac{1}{7}+\dfrac{4}{7}\right)+\dfrac{3}{7}\)
Số ?
2 + ....= 7 1 + .... = 5 7 - .... = 1
7 - ....= 4 .... + 1 = 7 7 - .... = 3
....+ 3 = 7 .....+ 2 = 7 .... - 0 = 7
2 + 5 = 7 1 + 4 = 5 7 - 6 = 1
7 - 3 = 4 6 + 1 = 7 7 - 4 = 3
4 + 3 = 7 5 + 2 = 7 7 - 0 = 7
ĐỀ CƯƠNG ÔN TẬP TOÁN 6 I/ PHẦN SỐ HỌC 1/ Dạng toán thực hiện phép tính – tính nhanh nếu có thể - a) - 5/7 * 2/11 - 5/7 * 9/11 + 1 5/7 b) 11 3/13 - (2 4/7 + 5 3/13) c) 2/7 * .5 * 1/4 - 2/7 * .3 * 1/4 d) 5/7 * 1/3 - 5/7 * 1/4 - 5/7 * 1/12 75\%-1 1 2 +0,5: 5 12 -( -1 2 )^ 2 e) f) 7 19 . 8 11 + 7 19 , 3 11 - 12 19 g) - 5/12 * 2/11 - 5/12 * 9/11 + 5/12 h) - 5/7 * 2/11 - 5/7 * 9/11 + 1 5/7 i) 6 7 + 5 8 :5- 3 16 .(-2)^ 2 j) 8.(-5).(-4).2 ; *) 2 3 + 1 3 .( -2 3 + 5 6 ); 2 3 k) 1) - 2/5 + (- 5/9 + 2/5) m) 17/13 - (4/13 - 11)