Điều kiện x \(\ge0\)từ đó ta có

x + 2015 + x + 2016 + x + 2017 = 6x 

<=> x = 2016

Ta có \(\left|x+2015\right|+\left|x+2016\right|+\left|x+2017\right|\ge0\Rightarrow6x\ge0\Rightarrow x\ge0\)

=> \(\left|x+2015\right|+\left|x+2016\right|+\left|x+2017\right|=3x+6048=6x\Rightarrow3x=6048\Rightarrow x=2016\)

Vậy x=2016

Ta có:

\(\left|x+2015\right|\ge0\)

\(\left|x+2016\right|\ge0\)

\(\left|x+2017\right|\ge0\)

\(\Rightarrow\left|x+2015\right|+\left|x+2016\right|+\left|x+2017\right|\ge0\)

\(\Rightarrow6x\ge0\)

\(\Rightarrow x\ge0\)

\(\Rightarrow\left|x\right|=x\)

\(\Rightarrow\left|x+2015\right|+\left|x+2016\right|+\left|x+2017\right|=\left(x+2015\right)+\left(x+2016\right)+\left(x+2017\right)=6x\)

\(\Rightarrow3x+6048=6x\)

\(\Rightarrow3x=6048\)

\(\Rightarrow x=2016\)

Vậy \(x=2016\)

|x+2015|+|x+2016|+|x+2017| = 6x

<=> \(\left[\begin{array}{nghiempt}x+2015+x+2016+x+2017=6x\\x+2015+x+2016+x+2017=-6x\end{array}\right.\)

<=> \(\left[\begin{array}{nghiempt}3x+6048=6x\\3x+6048=-6x\end{array}\right.\)

<=> \(\left[\begin{array}{nghiempt}3x=6048\\-9x=6048\end{array}\right.\)

<=> \(\left[\begin{array}{nghiempt}x=2016\\x=-672\end{array}\right.\)

trừ mỗi vế cho 2 rồi tách -2 thành -1và -1

X=1 nhé

     \(\frac{x+2014}{2015}+\frac{x+2015}{2016}=\frac{x+2016}{2017}+\frac{x+2017}{2018}\)

\(\Leftrightarrow\)\(\frac{x+2014}{2015}-1+\frac{x+2015}{2016}-1=\frac{x+2016}{2017}-1+\frac{x+2017}{2018}-1\)

\(\Leftrightarrow\)\(\frac{x-1}{2015}+\frac{x-1}{2016}=\frac{x-1}{2017}+\frac{x-1}{2018}\)

\(\Leftrightarrow\)\(\left(x-1\right)\left(\frac{1}{2015}+\frac{1}{2016}-\frac{1}{2017}-\frac{1}{2018}\right)=0\)

\(\Leftrightarrow\)\(x-1=0\)   ( do  1/2015 + 1/2016 - 1/2017 - 1/2018 # 0 )

\(\Leftrightarrow\) \(x=1\)

2016 x 2016 - 2015 x 2017 + x = 2016 

(2016 x 2016) - (2015 x 2017) + x = 2016 

4064256 - 4064255 + x = 2016 

1 + x = 2016 

x = 2016 - 1 

x = 1 

x=2015

Nếu đúng thì k cho mình nhé

2016 x 2016 - 2015 x 2017 + x = 2016

40654256 - 4064255 + x           = 2016

               1              + x           = 2016

                                  x           = 2016 - 1

                                  x            = 2015

Ta có:
x biết: 2016 x 2016 - 2015 x 2017 + x = 2016
x = 2015 x 2017 + 2016 - 2016 x 2016
x = 2015 x 2017 + 2016 x (1 - 2016)
x = 2015 x 2017 - 2015 x 2016
x = 2015 x (2017 - 2016)
x = 2015 x 1
x = 2015

Ta có: \(\frac{x-2019}{2018}+\frac{x-2018}{2017}=\frac{x-2017}{2016}+\frac{x-2016}{2015}\)

\(\Leftrightarrow\left(\frac{x-2019}{2018}+1\right)+\left(\frac{x-2018}{2017}+1\right)=\left(\frac{x-2017}{2016}+1\right)+\left(\frac{x-2016}{2015}+1\right)\)

\(\Leftrightarrow\frac{x-1}{2018}+\frac{x-1}{2017}=\frac{x-1}{2016}+\frac{x-1}{2015}\)

\(\Leftrightarrow\frac{x-1}{2018}+\frac{x-1}{2017}-\frac{x-1}{2016}-\frac{x-1}{2015}=0\)

\(\Leftrightarrow\left(x-1\right)\left(\frac{1}{2018}+\frac{1}{2017}-\frac{1}{2016}-\frac{1}{2015}\right)=0\)

\(\Leftrightarrow x-1=0\)( vì \(\frac{1}{2018}+\frac{1}{2017}-\frac{1}{2016}-\frac{1}{2015}\ne0\))

\(\Leftrightarrow x=1\)

Vạy x=1

Đặt A=2016*2016-2015*2017,ta có:

A=2016 *2016 - 2015 *2017

A=2016*(2015+1)-2015*(2016+1)

A=(2016*2015+2016)-(2015*2016+2015)

A=2016*2015+2016-2015*2016-2015

A=2016-2015=1

Mà A+x=2016

=>1+x=2016

=>x=2016-1

=>x=2015

Vậy x=2015...k nha mk đang âm điểm

2016 × 2016 - 2015 × 2017 + x = 2016

 4 064 256 - 4 064 255 + x = 2016

                                     1 + x = 2016

                                            x = 2016 - 1

                                            x = 2015. Vậy x = 2015

x =2015