1^2/1.2 x 2^2/2.3 x 3^2 /3.4 x.......x 99^2/99.100
nhanh tk
tìm x biết
x/200 = 1 mũ 2/1.2 x 2 mũ 2/2.3 x 3 mũ 2/3.4.........99 mũ 2/ 99.100
\(\dfrac{x}{200}\)= \(\dfrac{1^2}{1.2}\) . \(\dfrac{2^2}{2.3}\) . \(\dfrac{3^2}{3.4}\) . .... .\(\dfrac{99^2}{99.100}\)
bạn hãy rút gọn vế phải: x/200=1/2.2/3.3/4......98/99.99/100
Rồi sẽ có cái phương trình:x/200=1/100
từ đó suy ra:x/200=2/200 =>x=2
:)))))
\(\dfrac{x}{200}=\dfrac{1^2}{1.2}.\dfrac{2^2}{2.3}.\dfrac{3^2}{3.4}...\dfrac{99^2}{99.100}\)
\(\Leftrightarrow\dfrac{x}{200}=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}...\dfrac{99}{100}\)
\(\Leftrightarrow\dfrac{x}{200}=\dfrac{1}{100}\)
\(\Leftrightarrow x=2\)
Tìm x, sao cho giá trị của phân số là 1:
1.2+2.3+3.4+...+99.100/x^2+(x^2+1)+(x^2+2)+...+(x^2+99)
Bài 5 :
a) Chứng minh rằng : 1/1.2 + 1/3.4 + 1/5.6 + ... + 1/199.200/ 1/101 + 1/102 + 1/103 + ... + 1/200 = 1
b) So sánh A = 1 mũ 2/1.2 x 2 mũ 2/2.3 x 3 mũ 2/3.4 x 99 mũ 2/99.100 x 100 mũ 2/100.101 và B = 2 mũ 2/1.3 x 3 mũ 2/2.4 x 4 mũ 2/3.5
x .... x 59 mũ 2/58.60
Chỗ 4 mũ 2/3.5 x ... x 59 mũ 2/58.60 nha
a, Ta có : \(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{199.200}=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{199}-\frac{1}{200}\)
\(=\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{199}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{200}\right)\)
\(=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+...+\frac{1}{199}+\frac{1}{200}\right)-2\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{200}\right)\)
\(=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{199}+\frac{1}{200}\right)-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}\right)\)
\(=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
=> \(\frac{\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{199.200}}{\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}}=1\)
=> đpcm
Study well ! >_<
Tìm x : ( 1.2 + 2.3 + 3.4 +..... + 98. 99 )x / 26950 = 12/6/7 : 3/2
Đặt A = 1.2 + 2.3 + 3.4 + ... + 98.99
A = 1/3 . ( 1.2.3 + 2.3.3 + 3.4.3 + ... + 98.99.3)
A = 1/3 . [ 1.2.(3-0) + 2.3.(4-1) + 3.4.(5-2) + ... + 98.99.(100-97)
A = 1/3 . ( 1.2.3 - 0.1.2 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 98.99.100 - 97.98.99)
A = 1/3 . [(1.2.3 + 2.3.4 + 3.4.5 + ... + 98.99.100) - ( 0.1.2 + 1.2.3 + 2.3.4 + ... + 97.98.99)]
A = 1/3 . ( 98.99.100 - 0.1.2)
A = 1/3 .98.99.100
A = 323400
Ta có: 323400x/26950 = 12/6/7 : 3/2
12x = 14 × 2/3
12x = 28/3
x = 28/3 : 12
x = 28/3 × 1/12 = 7/9
Vậy x = 7/9
\(\frac{1.2+2.3+3.4+...+99.100}{x^2+\left(x^2+1\right)+\left(x^2+2\right)+...x^2+99}\)
tim x
Tính hiệu x-y biết
x=1.2+2.3+3.4+.......+99.100
y=12+22+32+....+992
\(x=1.2+2.3+3.4+...+99.100\)
\(x=1.\left(1+1\right)+2.\left(2+1\right)+3.\left(3+1\right)+...+99.\left(99+1\right)\)
\(x=1^2+1.1+2^2+2.1+3^2+3.1+...+99^2+99.1\)
\(x=y+\left(1+2+3+...+99\right)\)
\(x=y+\frac{99.\left(99+1\right)}{2}=y+4950\)
\(x-y=4950\)
a,Chứng tỏ rằng : 1.1/3.1/5.....1/99=2/51.2/52.2/53.....2/100
b, Tìm x biết (1.2+2.3+3.4+...+98.99).x=2252
Tìm x thuộc z:
\(\frac{1.2+2.3+3.4+...+99.100}{x+\left(x^2+1\right)+\left(x^2+2\right)+...+\left(x^2+99\right)}\)=\(50^{116}_{131}\)
Cái x đầu tiên không phải x2 à. Còn cái vế phải là hỗn số hả