-7/11.1+/19+-7/19.8/11-4/11
A= 7/19.8/11+7/19.3/11+12/19
\(A=\dfrac{7}{19}\cdot\dfrac{8}{11}+\dfrac{7}{19}\cdot\dfrac{3}{11}+\dfrac{12}{19}\\ A=\dfrac{7}{19}\left(\dfrac{8}{11}+\dfrac{3}{11}\right)+\dfrac{12}{19}\\ A=\dfrac{7}{19}\cdot1+\dfrac{12}{19}\\ A=\dfrac{19}{19}=1\)
A = 7/19.8/11+7/19.3/11+12/19
A = 7/19. . (8/11 + 3/11) + 12/19
A = 7/19 . 1 + 12/19
A = 7/19 + 12/19
A = 1
Ta có: \(A=\dfrac{7}{19}\cdot\dfrac{8}{11}+\dfrac{7}{19}\cdot\dfrac{3}{11}+\dfrac{12}{19}\)
\(=\dfrac{7}{19}\cdot\left(\dfrac{8}{11}+\dfrac{3}{11}\right)+\dfrac{12}{19}\)
\(=\dfrac{7}{19}+\dfrac{12}{19}=1\)
7/19.8/11+7/19=
\(\frac{7}{19}.\frac{8}{11}+\frac{7}{19}\)
\(=\frac{7}{19}.\frac{8}{11}+\frac{7}{19}.1\)
\(=\frac{7}{19}.\left(\frac{8}{11}+1\right)\)
\(=\frac{7}{19}.\frac{19}{11}\)
\(=\frac{7}{11}\)
\(=\frac{56}{209}+\frac{7}{19}=\frac{7}{11}\)
A=7/19.8/11+7/19.3/11+12/19
A=7/19.8/11+7/19.3/11+12/19
A=7/19.(8/11+3/11)+12/19
A=7/19.1+12/19
A=7/19+12/19
A=1
Ai có lòng tốt
cho mình một
tích đúng nhé.
Bài làm
\(A=\frac{7}{19}.\frac{8}{11}+\frac{7}{19}.\frac{3}{11}+\frac{12}{19}\)
\(A=\frac{7}{19}.\left(\frac{8}{11}+\frac{3}{11}\right)+\frac{12}{19}\)
\(A=\frac{7}{19}.1+\frac{12}{19}\)
\(A=\frac{7}{19}+\frac{12}{19}\)
\(A=1\)
Bài làm
\(A=\frac{7}{19}.\frac{8}{11}+\frac{7}{19}.\frac{3}{11}+\frac{12}{19}\)
\(A=\frac{7}{19}.\frac{8}{11}+\frac{7}{19}.\frac{3}{11}+\frac{7}{19}.\frac{12}{7}\)
\(A=\frac{7}{19}.\left(\frac{8}{11}+\frac{3}{11}+\frac{12}{7}\right)\)
\(A=\frac{7}{19}\left(\frac{11}{11}+\frac{12}{7}\right)\)
\(A=\frac{7}{19}\left(1+\frac{12}{7}\right)\)
\(A=\frac{7}{19}\left(\frac{7}{7}+\frac{12}{7}\right)\)
\(A=\frac{7}{19}.\frac{19}{7}\)
\(A=1\)
Vậy A = 1
a,(-25) .125.4.(-8) .(-17)
b,-3\4+2\7+-1\4+3\5+5\7
c,7\19.8\11+7\19.3\11-12\19
d,19 5\8:7\2013-26 5\8:7\2013
e,-5\12.2\11+-5\12.9\11+5\12
a) (- 25) x 125,4 x (-8) x (-17)
= (- 25 x 4) x (- 8 x 125) x (-17)
= (-100) x (-1000) x (-17)
= - 1 700 000
b) \(\frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)
\(=\left(\frac{-3}{4}+\frac{-1}{4}\right)+\left(\frac{2}{7}+\frac{5}{7}\right)+\frac{3}{5}\)
\(=-1+1+\frac{3}{5}\)
\(=0+\frac{3}{5}=\frac{3}{5}\)
c) \(\frac{7}{19}.\frac{8}{11}+\frac{7}{19}.\frac{3}{11}-\frac{12}{19}\)
\(=\frac{7}{19}.\left(\frac{8}{11}+\frac{3}{11}\right)-\frac{12}{19}\)
\(=\frac{7}{19}.1-\frac{12}{19}\)
\(=\frac{7}{19}-\frac{12}{19}=\frac{-5}{19}\)
d) \(19\frac{5}{8}:\frac{7}{2013}-26\frac{5}{8}:\frac{7}{2013}\)
\(=\left(19\frac{5}{8}-26\frac{5}{8}\right):\frac{7}{2013}\)
\(=-7:\frac{7}{2013}\)
\(=-2013\)
e) \(\frac{-5}{12}.\frac{2}{11}+\frac{-5}{12}.\frac{9}{11}+\frac{5}{12}\)
\(=\frac{-5}{12}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{5}{12}\)
\(=\frac{-5}{12}.1+\frac{5}{12}\)
\(=\frac{-5}{12}+\frac{5}{12}=0\)
~Học tốt~
a) 7/19.8/11+3/11.7/19+-12/19
b)-1,6 .-15/32+(0,8 - 2 4/25(hon so) ) : 3 2/3
a)7/19.8/11+3/11.7/19+-12/19
=7/19.(8/11+3/11)+-12/19
=7/19.1+-12/19
=7/19+-12/19
=-5/19
a)
\(\dfrac{7}{19}\cdot\dfrac{8}{11}+\dfrac{3}{11}\cdot\dfrac{7}{19}+\dfrac{-12}{19}\\ =\dfrac{7}{19}\cdot\left(\dfrac{8}{11}+\dfrac{3}{11}\right)+\dfrac{-12}{19}=\dfrac{7}{19}\cdot1+\dfrac{-12}{19}=\dfrac{7}{19}+\dfrac{-12}{19}=\dfrac{5}{19}\)
Tính nhanh:
7/19.8/11+7/19+12/19
/ là phần
Ai làm nhanh và đúng mình sẽ tick nha!
\(\frac{7}{19}.\frac{8}{11}+\frac{7}{19}+\frac{12}{19}=\frac{7.8+7.11+12.11}{19.11}=\frac{256}{209}\)
4) so sánh hai phân số sau
a) 7/15 và 4/9
B1 tính nhanh nếu có thể
a) (-18).5+5.10+5.(-2)
b) (-15):(-5)+7.(-3/7)
c) (-157)+(-16)+257+(-43)+(-84)
d) (+23)+(-135)-(-77)-/-65/+(-30)
e) -5/7 + (-6/11+1)
f) 1/2-2/3+4/5-5/6
g)1/3.4/5+1/3.6/5+2/3
h) -5/7.2/11+-5/7.9/11+1 5/7 không phải 15 phần 7
I)19/5.2007/2017+19/5.10/2017
K) 4/25.5/9+-4/25.10/3+7/9
m) 7/19.8/11+7/19.3/11+12/19
n)17/13.18/23-4/13.18/23-(-5)/23
P) 5/7 .5/11+5/7.2/11-5/7.14/11
q)-2/17+15/19+-15/17+13/20+4/19
X)7/-25+-18/25+4/23+5/8+19/23
S)5/7.-4/19+-15/7.5/19
Câu 1: thực hiện phép tính 1 cách hợp lý
A) -3/7+5/13+-4/13
B) 7/19.8/11+3/11.7/19+-12/19
Plzzzz mình đang cần gấppppppppppppppppppp
Rút gọn M=7/4-7/18-7/19 N=11/4-11/18-11/19
Sửa đề: Tính M/N
\(\dfrac{M}{N}=\dfrac{\dfrac{7}{4}-\dfrac{7}{18}-\dfrac{7}{19}}{\dfrac{11}{4}-\dfrac{11}{18}-\dfrac{11}{19}}\)
\(=\dfrac{7\left(\dfrac{1}{4}-\dfrac{1}{18}-\dfrac{1}{19}\right)}{11\left(\dfrac{1}{4}-\dfrac{1}{18}-\dfrac{1}{19}\right)}=\dfrac{7}{11}\)