\(\frac{x}{5}=\frac{5}{6}+\frac{-19}{30}\)
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\(\frac{x}{5}=\frac{5}{6}+\frac{-19}{30}\)
\(x=\frac{1}{2}+\frac{-2}{3}\)
\(\frac{x}{30}=\frac{3}{5}+\frac{7}{30}\)
Đề bài: Tìm x biết:
1,x/5=5/6+-19/30
x/5=25/30+-19/30
x/5=6/30
x/5=1/5 =>x=1
2, x=1/2+-2/3
x=3/6+-4/6
x=-1/6
3, x/30=3/5+7/30
x/30=18/30+7/30
x/30=25/30 => x=25
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24 tháng 6 2020 lúc 7:19
Tìm x biết:
\(\frac{x}{5}=\frac{5}{6}.\frac{-30}{19}\)
Tìm x, biết
\(\frac{x}{5}=\frac{5}{6}+\frac{_{_{-19}}}{30}\)
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Tìm x, biết:
a)x=\(\frac{-1}{2}+\frac{3}{4}\)
b)\(\frac{x}{5}=\frac{5}{6}+\frac{-19}{30}\)
a)x=-2/4+3/4=1/4
b)x/5=25/30+-19/30=6/30=1/5=>x=1.
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a)x\(=\frac{-1}{2}+\frac{3}{4}=\frac{-2}{4}+\frac{3}{4}=\frac{-2+3}{4}=\frac{1}{4}\)
b) Ta có: \(\frac{5}{6}+\frac{-19}{30}=\frac{25}{30}+\frac{-19}{30}=\frac{25-19}{30}=\frac{6}{30}=\frac{1}{5}\)
Vậy,\(\frac{x}{5}=\frac{1}{5}\)⇒\(x=1\)
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Tìm x
a) \(\frac{x}{5}=\frac{5}{6}+\frac{-19}{30}\)
b) \(\frac{9}{x}=\frac{2}{5}+\frac{7}{20}\)
a)\(\frac{x}{5}=\frac{25}{30}+\frac{-19}{30}=\frac{6}{30}=\frac{1}{5}\Rightarrow x=1\)
b)\(\frac{9}{x}=\frac{8}{20}+\frac{7}{20}=\frac{15}{20}=\frac{3}{4}=\frac{9}{12}\Rightarrow x=12\)
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B=\(\frac{5}{7}.\frac{14}{11}-\frac{5}{7}.\frac{5}{11}-\frac{5}{11}.\frac{2}{7}\)
C=\(1+\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+\frac{2}{30}+\frac{2}{42}\)
D=\(\frac{0,75-0,6+\frac{3}{19}+\frac{3}{19}}{2,75-2,2+\frac{11}{19}+\frac{11}{91}}\)
\(\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{30}{31}\right).\left(-\frac{5}{12}+\frac{1}{4}+\frac{1}{6}\right)\)
\(\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{30}{31}\right)\times\left(\frac{-5}{12}+\frac{1}{4}+\frac{1}{6}\right)\)
\(=\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{30}{31}\right)\times\left(\frac{-5}{12}+\frac{3}{12}+\frac{2}{12}\right)\)
\(=\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{30}{31}\right)\times\left(\frac{-5+3+2}{12}\right)\)
\(=\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{30}{31}\right)\times0\)
\(=0\)
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\(\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{30}{31}\right)\times\left(\frac{-5}{12}+\frac{1}{4}+\frac{1}{6}\right)\)
\(=\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{30}{31}\right)\times\left(\frac{-5}{12}+\frac{3}{12}+\frac{2}{12}\right)\)
\(=\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{30}{31}\right)\times\left(\frac{-5+3+2}{12}\right)\)
\(=\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{30}{31}\right)\times0\)
\(=0\)
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TÌM X BIẾT :
a)X=\(\frac{-1}{2}\)+\(\frac{3}{4}\)
b)\(\frac{X}{5}\)=\(\frac{5}{6}\)+\(\frac{-19}{30}\)
a) \(X=\frac{-1}{2}+\frac{3}{4}\)
\(\Leftrightarrow X=\frac{-2}{4}+\frac{3}{4}\)
\(\Leftrightarrow X=\frac{1}{4}\)
b) \(\frac{X}{5}=\frac{5}{6}+\frac{-19}{30}\)
\(\Leftrightarrow\frac{X}{5}=\frac{25}{30}+\frac{-19}{30}\)
\(\Leftrightarrow\frac{X}{5}=\frac{6}{30}=\frac{1}{5}\)
\(\Leftrightarrow X=1\)
Đáp số: a) \(X=\frac{1}{4}\)
b) \(X=1\)
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a, tính:\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
b, tìm x biết:\(1\frac{1}{30}:(24\frac{1}{6}-24\frac{1}{5})-\frac{1\frac{1}{2}-\frac{3}{4}}{4x-\frac{1}{2}}=(-1\frac{1}{5}):(8\frac{1}{5}-8\frac{1}{3})\)