so sanhs \(a=\frac{2^{18}-3}{2^{20}-3}vàB=\frac{2^{20}-3}{2^{22}-3}\)
Bài 1: So sánh lũy thừa
a) 125^80 và 25^125
b) 31^11 và 17^14
c) \(A=\frac{19^{30}+5}{19^{31}+5}vàB=\frac{19^{31+5}}{19^{32}+5}\)
d)\(A=\frac{2^{18}-3}{2^{20}-3}vàB=\frac{2^{20-3}}{2^{22}-3}\)
e) \(A=\frac{1+5+5^2+...+5^9}{1+5+5^2+...+5^8}vàB=\frac{1+3+3^2+...+3^9}{1+3+3^2+...+3^8}\)
Bài 2: Cho \(A=1+2+2^2+...+2^{30}\)
Viết A+1 dưới dạng lũy thừa
2) A=1+2+22+...+230=>2A=2+22+23+...+231
=>2A-A=A=(2+22+...+231)-(1+2+22+...+230)=231-1
=>A+1=(231-1)+1=231-(1-1)=231-0=231
lm xog chc'..............................................ặc ặc
so sank
\(A=\frac{2^{18}-3}{2^{20}-2}vaB=\frac{2^{20}-3}{2^{22}-3}\)
Ta có :
\(\dfrac{1}{A}=\dfrac{2^{20}-3}{2^{18}-3}=\dfrac{2^2.\left(2^{18}-3\right)+9}{2^{18}-3}=4+\dfrac{9}{2^{18}-3}\left(1\right)\)
\(\dfrac{1}{B}=\dfrac{2^{22}-3}{2^{20}-3}=\dfrac{2^2.\left(2^{20}-3\right)+9}{2^{20}-3}=4+\dfrac{9}{2^{20}-3}\left(2\right)\)
Từ (1) và (2) ta có \(\dfrac{1}{A}>\dfrac{1}{B}\Leftrightarrow A< B\)
so sánh
A=\(\frac{2^{18-3}}{2^{20}-3}\)và B= \(\frac{2^{20}-3}{2^{22}-3}\)
so sánh
a) \(A=\frac{2^{18}-3}{2^{20}-3}\) và \(A=\frac{2^{20}-3}{2^{22}-3}\)
cho A=\(\frac{2^{18}-3}{2^{20}-3}\)
B=\(\frac{2^{20}-3}{2^{22}-3}\)
so sanh a va b nha
ai giai nhanh tui cho 5 k
Ta có :
\(A=\frac{2^{18}-3}{2^{20}-3}\) \(B=\frac{2^{20}-3}{2^{22}-3}\)
\(2^2A=\frac{2^{20}-12}{2^{20}-3}\) \(2^2B=\frac{2^{22}-12}{2^{22}-3}\)
\(4A=\frac{2^{20}-3-9}{2^{20}-3}\) \(4B=\frac{2^{22}-3-9}{2^{22}-3}\)
\(4A=1-\frac{9}{2^{20}-3}\) \(4B=1-\frac{9}{2^{22}-3}\)
Ta thấy 220 - 3 < 222 - 3 nên \(\frac{9}{2^{20}-3}>\frac{9}{2^{22}-3}\)hay \(1-\frac{9}{2^{20}-3}>1-\frac{9}{2^{22}-3}\)
=> 4A > 4B hay A > B
Vậy A > B
Ủng hộ mk nha !!! ^_^
giải ro hon nha bạn
ai giai ro tui cho5 k
1. tính nhanh các tổng sau
a) A=\(\frac{20}{39}+\frac{22}{37}+\frac{18}{43}vàB=\frac{14}{39}+\frac{22}{39}+\frac{18}{41^{ }}\)
b) A=\(\frac{3}{8^3}+\frac{7}{8^4}\)và B=\(\frac{7}{8^3}+\frac{3}{8^4}\)
so sánh \(y=\frac{2^{18}-3}{2^{20}-3}\)và \(y=\frac{2^{20}-3}{2^{22}-3}\)
cho A=\(\frac{2^{18}-3}{2^{20}-3}\)
B=\(\frac{2^{20}-3}{2^{22}-3}\)
so sanh A và B nha
ai giải nhanh tui cho 5 k nha
Rút gọn:
A =\(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{20}\right)\)
B = \(1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2012}}\)
So sánh :
\(A=\frac{20^{10}+1}{20^{10}-1}vàB=\frac{20^{10}-1}{20^{10}-3}\)