Cho \(\frac{a+5}{a-5}=\frac{b+6}{b-6}\left(a\ne5;b\ne6\right)CMR:\frac{a}{b}=\frac{5}{6}\)
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\(Cho\frac{a+5}{a-5}=\frac{b+6}{b-6}\left(a\ne5,b\ne6\right).Cmr\frac{a}{b}=\frac{5}{6}\)
59. Cho \(\frac{a+5}{a-5}=\frac{b+6}{b-6}\left(a\ne5;b\ne6\right)\). Chứng minh rằng \(\frac{a}{b}=\frac{5}{6}\)
\(\left(a+5\right)\left(b-6\right)=\left(a-5\right)\left(b+6\right)\)
\(\Leftrightarrow ab-6a+5b-30=ab+6a-5b-30\)
\(\Leftrightarrow ab-ab+5b+5b-30+30=6a+6a\)
\(\Leftrightarrow10b=12a\)
\(\Rightarrow\frac{a}{b}=\frac{10}{12}=\frac{5}{6}\left(đpcm\right)\)
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\(\frac{a+5}{a-5}\)=\(\frac{b+6}{b-6}\)(ta hoán đổi trung tỉ)=>\(\frac{a+5}{b+6}\)=\(\frac{a-5}{b-6}\)=>\(\frac{\left(a+5\right)-5}{\left(b+6\right)-6}\)=\(\frac{\left(a+5\right)-a}{\left(b+6\right)-b}\)=a/b=5/6
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a+5/a-5=b+6/b-6=a+5/b+6=b+6/b-69 (giao hoán trung tỉ)=>(a+5)-5/(b+6)-6=(a+5)-a/(b+6)-6=a/b=5/6
BẠN ƠI CÁI MÀ '/' LÀ PHẦN NHA
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Cho \(\frac{a+5}{a-5}=\frac{b+6}{b-6}\left(a\ne5;b\ne6\right).\)Chứng minh rằng \(\frac{a}{b}=\frac{5}{6}\)
\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)
<=> \(\frac{a-5+10}{a-5}=\frac{b-6+12}{b-6}\)
<=> \(1+\frac{10}{a-5}=1+\frac{12}{b-6}\)
<=> \(\frac{10}{a-5}=\frac{12}{b-6}\)
<=> 10( b - 6 ) = 12( a - 5 )
<=> 5( b - 6 ) = 6( a - 5 )
<=> 5b - 30 = 6a - 30
<=> 5b = 6a
<=> \(\frac{6}{5}=\frac{b}{a}\)hay \(\frac{a}{b}=\frac{5}{6}\)( đpcm )
Cho \(\frac{a+5}{a-5}=\frac{b+6}{b-6}\left(a\ne5;b\ne6\right)\) Chứng minh rằng \(\frac{a}{b}=\frac{5}{6}\)
\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)
\(\Leftrightarrow\frac{a-5+10}{a-5}=\frac{b-6+12}{b-6}\)
\(\Leftrightarrow1+\frac{10}{a-5}=1+\frac{12}{b-6}\)
\(\Leftrightarrow\frac{10}{a-5}=\frac{12}{b-6}\)
\(\Rightarrow10.\left(b-6\right)=12.\left(a-5\right)\)
\(10b-60=12a-60\)
\(10b=12a\)
\(\frac{a}{b}=\frac{10}{12}=\frac{5}{6}\)
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\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)
\(=>\frac{a+5}{b+6}=\frac{a-5}{b-6}=\frac{a+5-\left(a-5\right)}{b+6-\left(b-6\right)}=\frac{a+5-a+5}{b+6-b+6}=\frac{10}{12}=\frac{5}{6}\)
\(\frac{a+5}{b+6}=\frac{a-5}{b-6}=\frac{a+5+\left(a-5\right)}{b+6+\left(b-5\right)}=\frac{a+5+a-5}{b+6+b-6}=\frac{2a}{2b}=\frac{a}{b}\)
=>\(\frac{a}{b}=\frac{a+5}{b+5}=\frac{5}{6}\)
=>\(\frac{a}{b}=\frac{5}{6}\)
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cho \(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)\(\left(a\ne5;b\ne6\right)\)tìm \(\frac{a}{b}\)
Ta có: \(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)
\(\Rightarrow\left(a+5\right).\left(b-6\right)=\left(a-5\right).\left(b+6\right)\)
\(ab-6a+5b-30=ab+6a-5b-30\)
\(\Rightarrow5b-6a=6a-5b\)
\(5b+5b=6a+6a\)
\(10b=12a\)
\(\Rightarrow\frac{a}{b}=\frac{10}{12}=\frac{5}{6}\)
Vậy \(\frac{a}{b}=\frac{5}{6}\)
Tham khảo nhé~
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Cho \(\frac{a+5}{a-5}=\frac{b+6}{b-6}\) \(\left(a\ne5,b\ne6\right)\). Như vậy tỉ số \(\frac{a}{b}\) bằng .....
\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\Rightarrow\left(a+5\right).\left(b-6\right)=\left(a-5\right)\left(b+6\right)\)
\(\Rightarrow ab-6a+5b-30=ab+6a-5b-30\)
\(\Rightarrow\left(ab-6a+5b-30\right)-\left(ab+6a-5b-30\right)=0\)
\(\Rightarrow ab-6a+5b-30-ab-6a+5b+30=0\)
\(\Rightarrow-12a+10b=0\)
\(\Rightarrow-12a=10b\Rightarrow\frac{a}{b}=\frac{-10}{12}\Rightarrow\frac{a}{b}=\frac{-5}{6}\)
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\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\Rightarrow ab+5b-6a-30=ab+6a-5b-30\)
\(\Rightarrow5a-6b=6a-5b\)
\(5a-6a=-5b+6b\)
\(-a=b\)
\(\frac{a}{b}=-1\)
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Xem thêm câu trả lời
cho \(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)(\(a\ne5;b\ne6\).chứng minh rằng \(\frac{a}{b}=\frac{5}{6}\)
\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\Rightarrow\left(a+5\right)\left(b-6\right)=\left(a-5\right)\left(b+6\right)\)
\(\Rightarrow ab-6a+5b-30=ab+6a-5b-30\)
\(\Rightarrow5b=6a\)
\(\Rightarrow\frac{a}{b}=\frac{5}{6}\)
Đpcm
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Cho \(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)(\(a\ne5;b\ne6\))
Chứng minh rằng \(\frac{a}{b}=\frac{5}{6}\)
\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)
\(\Leftrightarrow\left(a+5\right)\left(b-6\right)=\left(b+6\right)\left(a-5\right)\)
\(\Leftrightarrow ab-6a+5b-30=ab-5b+6a-30\)
\(\Leftrightarrow-6a+5b=6a-5b\)
\(\Leftrightarrow5b+5b=6a+6a\)
\(\Leftrightarrow10b=12a\)
\(\Leftrightarrow\frac{a}{b}=\frac{10}{12}=\frac{5}{6}\)
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Cho \(\frac{a+5}{a-5}=\frac{b+6}{b-6}(a\ne5;b\ne6)\)
Chứng minh rằng \(\frac{a}{b}=\frac{5}{6}\)
Ta có: \(\frac{x+5}{x-5}=\frac{b+6}{b-6}\)
\(\Leftrightarrow\left(a+5\right)\left(b-6\right)=\left(a-5\right)\left(b+6\right)\)
\(\Leftrightarrow ab-6a+5b-30=ab+6a-5b-30\)
\(\Leftrightarrow16a=10b\)
\(\Leftrightarrow\frac{a}{b}=\frac{10}{12}=\frac{5}{6}\left(đpcm\right)\)