x:5=124(dư 4)
a,142+26x5 b,216-124:4+56
c,175x(9-45:5) d,108:x=5(dư 3)
4468 : Y = 124 ( dư 4 )
4468 : Y = 124 ( dư 4 )
Y = (4468 : 124) + 4
Y = 36 + 4
Y = 40
Vậy Y = 40
Chúc bạn ngày càng học giỏi !!!
\(4468\div Y=124\)(dư 4)
\(Y=\left(4468-4\right)\div124\)
\(Y=4464\div124\)
\(Y=36\)
4468 : Y = 124 ( dư 4 )
=> ( 4468 - 4 ) : Y = 124
=> 4464 : Y = 124
=> Y = 4464 : 124
=> Y = 36
Tìm x biết : 71563 : x = 124 (dư 139 )
71563:x=124(dư 139)
x=(71563-139):124
x=71424:124
x=576
71563 : x = 124 = ( dư 139 )
20 : ( x - 5) = 4 . 25 - 20
( 4 + 3) ( x -5) + 14 = 25 + 124 : 4
49 . x - 14 .x = 49 . 10 - 70
tìm x biết x bằng :36+124:5+9^4
làm nhanh giúp ạ
a) x- 45= 48- 68
b) 157- (x- 124)= -483
c) 6x+ 15= -9
d) (1- x). 5^4= 3. 5^5
b) 157-(x-124)=-483
x-124=157-(-483)
x-124=640
x=640+124
x=764
Tìm x biết, X+1/125+x+2/124+x+3/123+x+4/122+x+146/5=0
x/3=y/4,y/5=z/7 và 2x+3y-z=-124
\(\dfrac{x}{3}=\dfrac{y}{4}\Rightarrow\dfrac{x}{15}=\dfrac{y}{20}\)
\(\dfrac{y}{5}=\dfrac{z}{7}\Rightarrow\dfrac{y}{20}=\dfrac{z}{28}\)
\(\Rightarrow\dfrac{x}{15}=\dfrac{y}{20}=\dfrac{z}{28}=\dfrac{2x}{30}+\dfrac{3y}{60}+\dfrac{-z}{-28}=\dfrac{2x+3y-z}{30+60-28}=\dfrac{-124}{62}=-2\)
\(\Rightarrow\left\{{}\begin{matrix}\dfrac{x}{15}=-2\\\dfrac{y}{20}=-2\\\dfrac{z}{28}=-2\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x=15.\left(-2\right)=-30\\y=20.\left(-2\right)=-40\\z=28.\left(-2\right)=-56\end{matrix}\right.\)
Ta có: \(\dfrac{x}{3}=\dfrac{y}{4}=\dfrac{x}{15}=\dfrac{y}{20}\left(1\right)\)
\(\dfrac{y}{5}=\dfrac{z}{7}=\dfrac{y}{20}=\dfrac{z}{28}\left(2\right)\)
Từ (1) và (2) suy ra:
\(\dfrac{x}{15}=\dfrac{y}{20}=\dfrac{z}{28}\Rightarrow\dfrac{2x}{30}=\dfrac{3y}{60}=\dfrac{z}{28}\)
Áp dụng tính chất dãy tỉ số bằng nhau, ta có:
\(\dfrac{2x}{30}=\dfrac{3y}{60}=\dfrac{z}{28}=\dfrac{2x+3y-z}{30+60-28}=\dfrac{-124}{62}=-2\)
Do đó:
\(\dfrac{x}{15}=-2\Rightarrow x=15.\left(-2\right)=-30\)
\(\dfrac{y}{20}=-2\Rightarrow y=20.\left(-2\right)=-40\)
\(\dfrac{z}{28}=-2\Rightarrow z=28.\left(-2\right)=-56\)
Vậy x = -30; y = -40; z = -56.
\(#Tmiamm\)